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s=\(\frac{1}{5.3.2}\) +\(\frac{1}{5.3.2.3}\) +.............+\(\frac{1}{5.3.670.671}\)
s=1/15(1/1.2+1/2.3+..................+1/670.671)
s=1/15(1-1/2+1/2-1/3+.............+1/670-1/671)
s=1/15(1-1/671)
s=1/15.670/671
s=134/2013
S=1/5.6+1/10.9+1/15.12+...+1/3350.2013
=(1/5).(1/3).(1/1.2+1/2.3+1/3.4+...+1/670.671)
=(1/15). (1-1/2+1/2-1/3+...+1/670-1/671)
=(1/15). (1-1/671)
=1/15.670/671
=134/2013
\(A=\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+...+\frac{1}{24}-\frac{1}{25}\)\(\frac{1}{25}\)
\(A=\frac{1}{5}-\frac{1}{25}\)
\(A=\frac{5}{25}-\frac{1}{25}=\frac{4}{25}\)
\(A=\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+...+\frac{1}{24.25}\)
\(A=\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+...+\frac{1}{24}-\frac{1}{25}\)
\(A=\frac{1}{5}-\frac{1}{25}\)
\(A=\frac{4}{25}\)
a) Ta có:
1/( 2.3 ) = ( 3 - 2 )/( 2.3 )
= 3/( 2.3 ) - 2/( 2.3 )
= 1/2 - 1/3.
1/( 3.4 ) = ( 4 - 3 )/( 3.4 )
= 4/( 3.4 ) - 3/( 3.4 )
= 1/3 - 1/4.
b)
Ta có:
A = 1/( 5.6 ) + 1/( 6.7 ) + 1/( 7.8 ) + ..... + 1/( 2019.2020 )
A = 1/5 - 1/6 + 1/6 - 1/7 + 1/7 - 1/8 + ..... + 1/2019 - 1/2020
A = 1/5 - 1/2020
A = 403/2020
Vậy A = 403/2020.
a) Ta có: \(\frac{1}{2.3}=\frac{3-2}{2.3}=\frac{3}{2.3}-\frac{2}{2.3}=\frac{1}{2}-\frac{1}{3}\)
\(\frac{1}{3.4}=\frac{4-3}{3.4}=\frac{4}{3.4}-\frac{3}{3.4}=\frac{1}{3}-\frac{1}{4}\)
b) Ta có: \(A=\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+.......+\frac{1}{2019.2020}\)
\(=\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+........+\frac{1}{2019}-\frac{1}{2020}\)
\(=\frac{1}{5}-\frac{1}{2020}=\frac{403}{2020}\)
\(=\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+...+\frac{1}{24}-\frac{1}{25}\)
\(=\frac{1}{5}-\frac{1}{25}\)
\(=\frac{4}{25}\)
\(=\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+...+\frac{1}{24}-\frac{1}{25}=\frac{1}{5}-\frac{1}{25}=\frac{4}{25}\)
thi thoang giup ti
S = 1/5.6 + 1/10.9+....+ 1/3350.2013
=1/5 . 1/3 .( 1/2+ 1/2.3 + 1/3.4 +... + 1/670.671)
=1/15. ( 1-1/2 + 1/2 - 1/3+...+ 1/670-1/671)
= 1/15 .( 1 - 1/671 )
= 1/15 .670/671
=134/2013
Cám ơn tôi đê. đề cô Phượng đúng không