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S=1+2+2^2+2^3+...+2^2002
2S=2+2^2+2^3+2^4+...+2^2003
2S-S=(2+2^2+2^3+2^4+...+2^2003)-(1+2+2^2+2^3+...+2^2002)
2S-S=(2-2)+(2^2-2^2)+(2^3-2^3)+...+(2^2002-2^2002)+(2^2003-1)
S=0+0+0+...+0+(2^2003-1)
S=2^2003-1 (rút gọn)
tick nha
S=1+2+2^2+2^3+...+2^2002
=>2S=2+22+23+24+...+22013
=>2S-S=2+22+23+24+...+22013-1-2-22-23-...-22012
=>S=22013-1
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S=30+32+34+36+...+3200
6S=32+34+36+...+3202
6S-S=(32+34+36+...+3202)-(1+32+34+...+3200)
5S=1+(32-32)+(34-34)+...+(3200-3200)+3202
S=(3200+1):5\(\frac{ }{ }\)
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\(\text{C=1+2-3-4+5+6-7-8+9+...+2002-2003-2004+2005+2006}\)
\(\text{C=1+(2-3-4+5)+(6-7-8+9)+...+(2002-2003-2004+2005)+2006}\)
\(\text{C=1+0+0+...+0+2006}\)
\(\text{C=1+2006}\)
\(C=2007\)
HỌC TỐT!!!
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A= - 2014 +2014 +1 . (-1) +(- 8) - 12/25 - 17/37 +13/25 - 20/37
A = ( -2014+2014) + ( - 1) +(-8) - (12/25 - 13/25 ) - (17/37 +20/37)
A = 0 +(-1) + (-8) +1/25 -1
A =(-9) +0,04 - 1
A = - 9,96
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1+(-2)+3+(-4)+.....+(-19)+20=[1+(-2)]+[3+(-4)]+....+[(-19)+20]= (-1)+(-1)+....+(1) (có 10 thừa số -1)
=(-1).10= -10
A = 20 + 21 + 22 + 23 +....+ 22002
2A = 21 + 22 + 23 + 24 +....+ 22003
2A - A = ( 21 + 22 + 23 + 24 +....+ 22003 ) - ( 20 + 21 + 22 + 23 + .... + 22002 )
A = 22003 - 1
Hk tốt
mình cảm ơn