NT
2
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Các câu hỏi dưới đây có thể giống với câu hỏi trên
VT
1
26 tháng 2 2022
\(\dfrac{3.4.5}{10.2.6}=\)\(\dfrac{3.2.2.5}{2.5.3.2}=\dfrac{1}{0}\)
=> hình như đề sai phải k pạn?
Vì k có phép chia 1:0 nên k có phân số 1/0
S
1 tháng 3 2017
a) Cách 1 : (3/4 + 1/2) x 5/7
= 5/4 x 5/7
= 25/28
Cách 2 : (3/4 + 1/2) x 5/7
= 3/4 x 5/7 + 1/2 x 5/7
= 15/28 + 5/14
= 25/28
b) Cách 1 : 5/7 x 13/21 + 2/7 x 13/21
= 65/147 + 26/147
= 13/21
Cách 2 : 5/7 x 13/21 + 2/7 x 13/21
= (5/7 + 2/7) x 13/21
= 1 x 13/21
= 13/21
câu c tự làm
XO
29 tháng 6 2019
a) Ta có \(\frac{1.2+2.4+3.6+4.8+5.10}{3.4+6.8+9.12+12.16+15.20}\)
= \(\frac{1.2+1.2.2.2+1.3.2.3+1.4.2.4+1.5.2.5}{3.4+3.2.4.2+3.3.4.3+3.4.4.4+3.5.4.5}\)
= \(\frac{1.2+1.2.4+1.2.9+1.2.16+1.2.25}{3.4+3.4.4+3.4.9+3.4.16+3.4.25}\)
= \(\frac{1.2.\left(1+4+9+16+25\right)}{3.4.\left(1+4+9+16+25\right)}\)
= \(\frac{1.2.55}{3.4.55}\)
= \(\frac{1.2.55}{3.2.2.55}\)
= \(\frac{1}{3.2}\)
= \(\frac{1}{6}\)
b) \(\frac{111111}{666665}=\frac{111111}{666665}\)
(dấu "." là dấu "x")
NT
1
15 tháng 2 2018
\(5-\frac{13}{17}=\frac{5}{1}-\frac{13}{17}=\frac{85}{17}-\frac{13}{17}=\frac{72}{17}\)
\(\frac{2}{5}-\frac{1}{7}=\frac{14}{35}-\frac{5}{35}=\frac{9}{35}\)
\(\frac{4}{9}-\frac{2}{9}=\frac{4-2}{9}=\frac{2}{9}\)
\(\frac{5}{4}-\frac{1}{3}=\frac{15}{12}-\frac{4}{12}=\frac{11}{12}\)
\(\frac{5}{2}-\frac{1}{4}-\frac{2}{3}=\frac{30}{12}-\frac{3}{12}-\frac{8}{12}=\frac{19}{12}\)
\(\frac{4}{3}-\frac{2}{5}+\frac{1}{2}=\frac{40}{30}-\frac{12}{30}+\frac{15}{30}=\frac{40-12+15}{30}=\frac{53}{30}\)
tk cho mk,mk đang bị trừ điểm
SC
5
F
23 tháng 1 2020
Bài giải
a, \(\frac{4}{5}-\frac{2}{3}+\frac{1}{5}-\frac{1}{3}\)
\(=\left(\frac{4}{5}+\frac{1}{5}\right)-\left(\frac{2}{3}+\frac{1}{3}\right)=1-1=0\)
b, \(\frac{2}{5}\text{ x }\frac{7}{4}-\frac{2}{5}\text{ x }\frac{3}{7}\)
\(=\frac{2}{5}\text{ x }\left(\frac{7}{4}-\frac{3}{7}\right)=\frac{2}{5}\text{ x }\frac{37}{28}=\frac{37}{70}\)
c, \(\frac{13}{4}\text{ x }\frac{2}{3}\text{ x }\frac{4}{13}\text{ x }\frac{3}{12}=\frac{13\text{ x }2\text{ x }4\text{ x }3}{4\text{ x }3\text{ x }13\text{ x }12}=\frac{1}{6}\)
d, \(\frac{75}{100}+\frac{18}{21}+\frac{19}{32}+\frac{1}{4}+\frac{3}{21}+\frac{13}{32}\)
\(=\frac{3}{4}+\frac{18}{21}+\frac{19}{32}+\frac{1}{4}+\frac{3}{21}+\frac{13}{32}\)
\(=\left(\frac{3}{4}+\frac{1}{4}\right)+\left(\frac{18}{21}+\frac{3}{21}\right)+\left(\frac{19}{32}+\frac{13}{32}\right)\)
\(=1+1+1\)
\(=3\)
e, \(\frac{2}{5}+\frac{6}{9}+\frac{3}{4}+\frac{3}{5}+\frac{1}{3}+\frac{1}{4}\)
\(=\frac{2}{5}+\frac{2}{3}+\frac{3}{4}+\frac{3}{5}+\frac{1}{3}+\frac{1}{4}\)
\(=\frac{1}{5}\left(2+3\right)+\frac{1}{3}\left(2+1\right)+\frac{1}{4}\left(3+1\right)\)
\(=\frac{1}{5}\cdot5+\frac{1}{3}\cdot3+\frac{1}{4}\cdot4\)
\(=1+1+1\)
\(=3\)
M
23 tháng 1 2020
a, \(\frac{4}{5}-\frac{2}{3}+\frac{1}{5}-\frac{1}{3}\)
\(=\left(\frac{4}{5}+\frac{1}{5}\right)-\left(\frac{2}{3}+\frac{1}{3}\right)=1-1=0\)
b, \(\frac{2}{5}\text{ x }\frac{7}{4}-\frac{2}{5}\text{ x }\frac{3}{7}\)
\(=\frac{2}{5}\text{ x }\left(\frac{7}{4}-\frac{3}{7}\right)=\frac{2}{5}\text{ x }\frac{37}{28}=\frac{37}{70}\)
c, \(\frac{13}{4}\text{ x }\frac{2}{3}\text{ x }\frac{4}{13}\text{ x }\frac{3}{12}=\frac{13\text{ x }2\text{ x }4\text{ x }3}{4\text{ x }3\text{ x }13\text{ x }12}=\frac{1}{6}\)
d, \(\frac{75}{100}+\frac{18}{21}+\frac{19}{32}+\frac{1}{4}+\frac{3}{21}+\frac{13}{32}\)
\(=\frac{3}{4}+\frac{18}{21}+\frac{19}{32}+\frac{1}{4}+\frac{3}{21}+\frac{13}{32}\)
\(=\left(\frac{3}{4}+\frac{1}{4}\right)+\left(\frac{18}{21}+\frac{3}{21}\right)+\left(\frac{19}{32}+\frac{13}{32}\right)\)
\(=1+1+1\)
\(=3\)
e, \(\frac{2}{5}+\frac{6}{9}+\frac{3}{4}+\frac{3}{5}+\frac{1}{3}+\frac{1}{4}\)
\(=\frac{2}{5}+\frac{2}{3}+\frac{3}{4}+\frac{3}{5}+\frac{1}{3}+\frac{1}{4}\)
\(=\frac{1}{5}\left(2+3\right)+\frac{1}{3}\left(2+1\right)+\frac{1}{4}\left(3+1\right)\)
\(=\frac{1}{5}\cdot5+\frac{1}{3}\cdot3+\frac{1}{4}\cdot4\)
\(=1+1+1\)
\(=3\)
\(\dfrac{5}{7\times12}+\dfrac{4}{12\times16}+\dfrac{3}{16\times19}+\dfrac{2}{19\times21}+\dfrac{1}{21\times22}\\ =\dfrac{1}{7}-\dfrac{1}{12}+\dfrac{1}{12}-\dfrac{1}{16}+\dfrac{1}{16}-\dfrac{1}{19}+\dfrac{1}{16}-\dfrac{1}{21}+\dfrac{1}{21}-\dfrac{1}{22}\\ =\dfrac{1}{7}-\dfrac{1}{22}\\ =\dfrac{15}{154}\)
\(\dfrac{5}{7\times12}+\dfrac{4}{12\times16}+\dfrac{3}{16\times19}+\dfrac{2}{19\times21}+\dfrac{1}{21\times22}\)
\(=\dfrac{1}{7}-\dfrac{1}{12}+\dfrac{1}{12}-\dfrac{1}{16}+\dfrac{1}{16}-\dfrac{1}{19}+\dfrac{1}{19}-\dfrac{1}{21}+\dfrac{1}{21}-\dfrac{1}{22}\)
\(=\dfrac{1}{7}-\dfrac{1}{22}\)
\(=\dfrac{22}{154}-\dfrac{7}{154}\)
\(=\dfrac{15}{154}\)