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\([\)6+(\(\dfrac{1}{2}\))3\(]\):\(\dfrac{3}{12}\)=\([\)6+\(\dfrac{1}{8}\)\(]\):\(\dfrac{1}{4}\)=\(\dfrac{49}{8}\):\(\dfrac{1}{4}\)=\(\dfrac{49}{2}\).
707: [(2x -5) + 74] = 42 - 32
(2x -5) + 74 = 101
2x - 5 + 74 = 101
2x + 69 = 101
2x = 32 = 25
=> x = 5
707: [(2x -5) + 74] = 42 - 32
(2x -5) + 74 = 101
2x - 5 + 74 = 101
2x + 69 = 101
2x = 32 = 25
=> x = 5
11 3/4-[65/4-41/2]+1-2/3
47/4-[65/4-41/2]+1-2/3
47/4-(-17/4)+1-2/3
16/1+1-2/3
16/1+1/1-2/3
17/1-2/3
51/3-2/3
49/3
a)\(x^{15}=x\Rightarrow x\in\left\{0;1\right\}\) d)Là ý b
b)\(\left(2x+1\right)^3=125\\ \left(2x+1\right)^3=5^3\Rightarrow2x+1=5\\ 2x=4\\ x=2\) e)\(\left(x-3\right)^2=25\\ \Rightarrow\left(x-3\right)^2=5^2\\ \Rightarrow\hept{\begin{cases}x-3=5\Rightarrow x=8\\x-3=-5\Rightarrow x=-2\end{cases}}\)
c)\(\left(x-5\right)^4=\left(x-5\right)^6\\ \Rightarrow x-5\in\left\{0;1\right\}\Rightarrow x\in\left\{5;6\right\}\)
47 - mở ngoặc vuông mở ngoặc tròn 45 x 2 mũ 4 - 5 mũ 2 x 12 đóng ngoặc tròn chia 14 đóng ngoặc vuông
\(\left[\frac{1}{33}+\frac{31}{333}-\left(\frac{341}{3333}\right)^2\right]\times\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)
=\(\left[\frac{1}{33}+\frac{31}{333}-\left(\frac{341}{3333}\right)^2\right]\times\left(\frac{3}{6}-\frac{2}{6}-\frac{1}{6}\right)\)
=\(\left[\frac{1}{33}+\frac{31}{333}-\left(\frac{341}{3333}\right)^2\right]\times\left(\frac{0}{6}\right)\)
=\(\left[\frac{1}{33}+\frac{31}{333}-\left(\frac{341}{3333}\right)^2\right]\times0\)
=0