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\(\frac{5^4.20^4}{25^5.4^5}=\frac{5^4.\left(5.2^2\right)^4}{\left(5^2\right)^5.\left(2^2\right)^5}=\frac{5^4.5^4.2^8}{5^{10}.2^{10}}=\frac{5^8.2^8}{2^{10}.2^{10}}=\frac{1}{5^2.5^2}=\frac{1}{25.4}=\frac{1}{100}\)
\(\dfrac{5^4.20^4}{25^5.4^5}=\dfrac{25^2\left(5.4\right)^4}{25^5.4^5}=\dfrac{1.5^4.4^4}{25^3.4^5}=\dfrac{25^2.1}{25^3.4}=\dfrac{1}{25.4}=\dfrac{1}{100}\)
\(\frac{-7}{25}.\frac{11}{13}+\frac{-7}{25}.\frac{2}{13}-\frac{18}{25}\)
\(=\frac{-7}{25}.\left(\frac{11}{13}+\frac{2}{13}\right)-\frac{18}{25}\)
\(=\frac{-7}{25}.1-\frac{18}{25}\)
\(=\frac{-7}{25}-\frac{18}{25}\)
\(=-1\)
\(5\frac{2}{5}.4\frac{2}{7}+5\frac{5}{7}.5\frac{2}{5}\)
\(=5\frac{2}{5}.\left(4\frac{2}{7}+5\frac{5}{7}\right)\)
\(=5,4.10=54\)
\(-0,8\cdot1\frac{9}{25}-\frac{4}{5}\cdot\frac{64}{25}\)
\(=\frac{-4}{5}\cdot\frac{34}{25}+\frac{-4}{5}\cdot\frac{64}{25}\)
\(=\frac{-4}{5}\left(\frac{34}{25}+\frac{64}{25}\right)\)
\(=\frac{-4}{5}\cdot\frac{98}{25}\)
\(=\frac{-392}{125}\)
Chắc sai =))
a) \(\frac{27}{8}\times\frac{5}{7}\times\frac{8}{27}+\frac{2}{7}\)
\(=\frac{27\times5\times8}{8\times7\times27}+\frac{2}{7}\)
\(=\frac{5}{7}+\frac{2}{7}\)
\(=1\)
b) \(1,6\times\frac{25}{32}-\left(\frac{2}{3}+\frac{4}{5}\right):\frac{11}{5}\)
\(=\frac{8}{5}\times\frac{25}{32}-\left(\frac{2}{3}+\frac{4}{5}\right).\frac{5}{11}\)
\(=\frac{5}{4}-(\frac{10}{33}+\frac{4}{11})\)
\(=\frac{5}{4}-\frac{2}{3}\)
\(=\frac{7}{12}\)
chịu luôn rùi! ! phần b, mk ko tính nhanh đc! cho mk xin lỗi bn nhiều nha!
TL:
\(\frac{5^4.20^4}{25^5.4^5}=\frac{5^4.\left(4.5\right)^4}{\left(5^2\right)^5.4^5}=\frac{5^8.4^4}{5^{10}.4^5}=\frac{1}{5^2.4}=\frac{1}{25.4}=\frac{1}{100}\)
HT
54 . 204 / 255 . 45
= 54 . ( 4 . 5 )4 / (52)5 . 45
= 58 . 44 / 510 . 45
= 1 / 52 . 4
= 1 / 25 . 4
= 1 / 100