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\(a,\)\(\frac{1}{2}.\left(\frac{2}{9}+\frac{3}{7}-\frac{5}{37}\right)\)
\(\Rightarrow\frac{1}{2}.\left(\frac{2.259}{2331}+\frac{3.333}{2331}-\frac{5.63}{2331}\right)\)
\(\Rightarrow\frac{1}{2}.\left(\frac{518}{2331}+\frac{999}{2331}-\frac{315}{2331}\right)\)
\(\Rightarrow\frac{1}{2}.\left(\frac{518+999-315}{2331}\right)\)
\(\Rightarrow\frac{1}{2}.\frac{1202}{2331}\)
\(\Rightarrow\frac{601}{2331}\)
\(b,\)\(\left(-\frac{5}{28}+1,75+\frac{8}{35}\right):\left(-3\frac{9}{20}\right)\)
\(\Rightarrow\frac{9}{5}:\left(-\frac{69}{20}\right)\)
\(=-\frac{12}{23}\)
\(c,\)\(\frac{1}{3}.\frac{1}{5}-\frac{7}{27}.\frac{36}{14}\)
\(=\frac{1}{15}-\frac{2}{3}\)
\(=\frac{1}{15}-\frac{10}{15}=-\frac{9}{15}=-\frac{3}{5}\)
\(d,\)\(70,5-528:\frac{15}{2}\)
\(=70,5-\frac{352}{5}\)
\(=\frac{1}{10}\)
c.
\(\frac{1}{3}\times\frac{5}{7}-\frac{7}{27}\times\frac{36}{14}\)
\(=\frac{1}{3}\times\frac{5}{7}-\frac{7}{3\times9}\times\frac{4\times9}{7\times2}\)
\(=\frac{1}{3}\times\frac{5}{7}-\frac{1}{3}\times\frac{4}{6}\)
\(=\frac{1}{3}\times\left(\frac{5}{7}-\frac{4}{6}\right)\)
\(=\frac{1}{3}\times\left(\frac{30-38}{42}\right)\)
\(=\frac{1}{3}\times\frac{-8}{42}\)
\(=-\frac{4}{63}\)
Chúc bạn học tốt
a) \(\frac{7}{11}\)
b)\(\frac{218}{165}\)
c)\(\frac{1}{4}\)
d)\(\frac{-21}{20}\)
e)\(\frac{2}{9}\)
g) 1
h)\(\frac{-561}{26}\)
i)\(\frac{4}{3}\)
\(a,\frac{6}{10}=\frac{3}{5};\frac{6}{16}=\frac{3}{8};-\frac{15}{20}=\frac{3}{4};-\frac{10}{30}=\frac{-1}{3}\)
\(b,\frac{42}{28}=\frac{3}{2};\frac{54}{-21}=-\frac{10}{7};-\frac{27}{33}=-\frac{9}{11};\frac{25}{14}=\frac{25}{14}\)
\(c,\frac{125}{1000}=\frac{1}{8};\frac{198}{126}=\frac{11}{7};\frac{3}{243}=\frac{1}{81};\frac{103}{2090}=\frac{103}{2090}\)
\(d,\frac{2.3}{9.14}=\frac{28}{3}\)
1) A = \(\frac{-15}{19}.\frac{23}{37}+\frac{14}{37}.\frac{15}{19}=\frac{15}{19}.\frac{-23}{37}+\frac{14}{37}.\frac{15}{19}=\frac{15}{19}.\left(\frac{-23}{37}+\frac{14}{37}\right)=\frac{15}{19}.\frac{-9}{37}=\frac{-135}{703}\)
#)Trả lời :
\(A=\frac{\left(140+70+42+28+20+15\right)}{420}\)
\(A=\frac{315}{420}=\frac{\left(315:105\right)}{\left(420:105\right)}=\frac{3}{4}\)
Vậy : \(A=\frac{3}{4}\)
#~Will~be~Pens~#
\(E=\left(\frac{-2}{3}.\frac{-9}{10}\right).\left(\frac{-5}{6}.\frac{-14}{15}\right).\left(\frac{-20}{21}.\frac{-27}{28}\right).\frac{-35}{36}\)
\(E=\frac{3}{5}.\frac{7}{9}.\frac{45}{49}.\frac{-35}{36}\)
\(E=\left(\frac{3}{5}.\frac{-35}{36}\right).\left(\frac{7}{9}.\frac{45}{49}\right)\)
\(E=\frac{-7}{12}.\frac{5}{7}\)
\(E=\frac{-5}{12}\)
vậy \(E=\frac{-5}{12}\)
E=-2/3.-5/6.-9/10.-14/15.-20/21.-27/28.-35/36
=-2/3.-5/2.3.-3.3/2.5.-2.7/3.5.-4.5/3.7.3.3.3/4.7.-5.7/4.3.3
=-5/12