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3 tháng 3 2018
a) -23 + 176 - (2176 - 23)
= -23 + 176 - 2176 + 23
= (-23 + 23) + (176 - 2176)
= 0 + (-2000)
= -2000
b) 125 . (-24) + 24 . 225
= (-125) . 24 + 24 . 225
= 24 . (-125 + 225)
= 24 . 100
= 2400
3 tháng 5 2017
\(\frac{-11}{23}.\frac{6}{7}+\frac{8}{7}.\frac{-11}{23}-\frac{1}{23}\)=\(\frac{-11}{23}.\left(\frac{6}{7}+\frac{8}{7}\right)-\frac{1}{23}\)=\(\frac{-11}{23}.2-\frac{1}{23}\)=\(\frac{-22}{23}-\frac{1}{23}=\frac{-21}{23}\)
24 tháng 9 2015
\(B=\frac{\left(315+372\right).3+\left(372+315\right).7}{26.13+74.14}=\frac{315.3+372.3+372.7+315.7}{26.13+74.14}=\frac{315.\left(7+3\right)+372.\left(7+3\right)}{26.13+74.14}=\frac{3150+3720}{26.13+74.14}\)
đến đấy bó tay
5 tháng 8 2016
\(\frac{17}{23}.\frac{8}{16}.\frac{23}{17}.\left(-80\right).\frac{3}{4}\)
\(=\left(\frac{17}{23}.\frac{23}{17}\right).\left(\frac{1}{2}.\frac{3}{4}.\left(-80\right)\right)\)
\(=1.\left(\frac{3}{8}.\left(-80\right)\right)\)
\(=1.\left(-30\right)=-30\)
PL
14 tháng 3 2018
a) \(\frac{31}{23}-\left(\frac{7}{23}+\frac{8}{23}\right)\)
\(=\frac{31}{23}-\frac{15}{23}\)
\(=\frac{16}{23}\)
b) \(\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)\)
\(=\frac{1}{3}+\frac{12}{67}+\frac{13}{41}-\frac{79}{67}+\frac{28}{41}\)
\(=\frac{1}{3}+\left(\frac{12}{67}-\frac{79}{67}\right)+\left(\frac{13}{41}+\frac{28}{41}\right)\)
\(=\frac{1}{3}+\frac{-67}{67}+\frac{41}{41}\)
\(=\frac{1}{3}-1+1\)
\(=\frac{1}{3}\)
c) \(\frac{38}{45}-\left(\frac{8}{45}-\frac{17}{52}-\frac{3}{11}\right)\)
\(=\frac{38}{45}-\frac{8}{45}+\frac{17}{52}+\frac{3}{11}\)
\(=\frac{30}{45}+\frac{17}{52}+\frac{3}{11}\)
\(=\frac{2}{3}+\frac{17}{52}+\frac{3}{11}\)
\(=\frac{104+51}{156}+\frac{3}{11}\)
\(=\frac{155}{156}+\frac{3}{11}\)
\(=\frac{156}{156}-\frac{1}{156}+\frac{3}{11}\)
\(=1-\frac{1}{156}+\frac{3}{11}\)
\(=1-\left(\frac{11-468}{1716}\right)\)
\(=1-\frac{-457}{1716}\)
\(=1+\frac{457}{1716}\)
\(=\frac{2173}{1716}\)
14 tháng 3 2018
a)31/23-(7/32+8/23)=31/23-7/32-8/23=(31/23-8/23)-7/32=1-7/32=25/32
L
6 tháng 3 2017
\(B=-\frac{2}{17}+\frac{15}{23}+-\frac{15}{17}+\frac{4}{19}+\frac{8}{23}\)
\(B=\left(-\frac{2}{17}+-\frac{15}{17}\right)+\left(\frac{15}{23}+\frac{8}{23}\right)+\frac{4}{19}\)
\(B=\left(-1\right)+1+\frac{4}{19}\)
\(B=0+\frac{4}{9}=\frac{4}{9}\)
\(C=-\frac{1}{2}+\frac{3}{21}+-\frac{2}{6}+-\frac{5}{30}\)
\(C=-\frac{1}{2}+\frac{1}{7}+-\frac{1}{3}+-\frac{1}{6}\)
\(C=\left(-\frac{1}{2}+-\frac{1}{3}+-\frac{1}{6}\right)+\frac{1}{7}\)
\(C=\left(-1\right)+\frac{1}{7}\)
\(C=-\frac{6}{7}\)
Ủng hộ tk Đúng nhé ! ^^
6 tháng 3 2017
B= -2 + 15 + (-15) + 4 + 8
17 23 17 19 23
B= [(-2) + (-15)] + [15 + 8] + 4
17 17 23 23 19
B= -1 +1+ 4 vậy B=4
19 19
23 tháng 6 2017
\(A=\frac{8}{9}\cdot\frac{15}{16}\cdot\frac{24}{25}\cdot...\cdot\frac{360}{361}\cdot\frac{399}{400}\)
\(A=\frac{2\cdot4\cdot3\cdot5\cdot4\cdot6\cdot...\cdot18\cdot20\cdot19\cdot21}{3\cdot3\cdot4\cdot4\cdot5\cdot5\cdot...\cdot19\cdot19\cdot20\cdot20}\)
\(A=\frac{2\cdot21}{3\cdot20}\)
\(A=\frac{7}{10}\)
\(B=\frac{9}{8}\cdot\frac{16}{15}\cdot\frac{25}{24}\cdot...\cdot\frac{441}{440}\cdot\frac{484}{483}\)
\(B=\frac{3\cdot3\cdot4\cdot4\cdot5\cdot5\cdot...\cdot21\cdot21\cdot22\cdot22}{2\cdot4\cdot3\cdot5\cdot4\cdot6\cdot...\cdot20\cdot22\cdot21\cdot23}\)
\(B=\frac{3\cdot22}{2\cdot23}=\frac{33}{23}\)
\(C=\frac{17}{23}.\left(\frac{7}{61}+\frac{28}{61}+\frac{26}{61}\right)\)
\(C=\frac{17}{23}\cdot1=\frac{17}{23}\)
30 tháng 4 2018
a)\(=\frac{-3}{7}+\frac{15}{26}-\frac{2}{13}+\frac{3}{7}\)
\(=\left(\frac{-3}{7}+\frac{3}{7}\right)-\left(\frac{15}{26}+\frac{2}{13}\right)\)
\(=0-\frac{19}{26}\)
\(=-\frac{19}{26}\)
30 tháng 4 2018
c)\(=\frac{-11}{23}.\left(\frac{6}{7}+\frac{8}{7}\right)-\frac{1}{23}\)
\(=\frac{-11}{23}.2-\frac{1}{23}\)
\(=\frac{-22}{23}-\frac{1}{23}\)
\(=-1\)
\(\frac{400}{101}\)
\(A=\frac{113+892+187+808}{742-23+158-372}\)
\(A=\frac{\left(113+187\right)+\left(892+808\right)}{\left(742-372\right)+\left(158-23\right)}\)
\(A=\frac{300+1700}{370+135}\)
\(A=\frac{2000}{505}=\frac{400}{101}\)