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\(5,2\times99-2,6\times6+5,2\times4\)
\(=5,2\times99-2,6\times2\times3+5,2\times4\)
\(=5,2\times99-5,2\times3+5,2\times4\)
\(=5,2\times\left(99-3+4\right)\)
\(=5,2\times100\)
\(=520\)
5,2 x 99 - 2,6 + 5,2 x 4
= 5,2 x 99 - 5,2 x 3 + 5,2 x 4
= 5,2 x ( 99 - 3 + 4 )
= 5,2 x 100
= 5,2 x 100
= 520
Chúc bạn học giỏi !!!
1,25 x 4,2 + 119,6 : 5,2 - 23,19
= 5,25 + 23 - 23,19
= 5,06
14,75 - 7,15 : 5 + 2,6 x 3,5
= 14,75 - 1,43 + 9,1
= 22,42
\(\frac{2x-4,36}{0,125}=0,25.42,9-11,7.0,25+0,25.0,8\)
\(\Leftrightarrow\frac{2x-4,36}{0,125}=0,25.\left(42,9-11.7+0,8\right)\)
\(\Leftrightarrow\frac{2x-4,36}{0,125}=0,25.32\)
\(\Leftrightarrow\frac{2x-4,36}{0,125}=8\)
\(\Leftrightarrow2x-4,36=1\)
\(\Leftrightarrow2x=5,36\)
\(\Leftrightarrow x=2,68\)
b) \(N=\frac{1}{1.5}+\frac{1}{5.10}+\frac{1}{10.15}+\frac{1}{15.20}+...+\frac{1}{2005.2010}\)
\(\Leftrightarrow N=\frac{1}{5}\left(1-\frac{1}{5}+\frac{1}{5}-\frac{1}{10}+\frac{1}{10}-\frac{1}{15}+\frac{1}{15}-\frac{1}{20}+...+\frac{1}{2005}-\frac{1}{2010}\right)\)
\(\Leftrightarrow N=\frac{1}{5}\left(1-\frac{1}{2010}\right)\)
\(\Leftrightarrow N=\frac{1}{5}.\frac{2009}{2010}=\frac{2009}{10050}\)
Bài 1:
a)\(\frac{2\cdot x-4,36}{0,125}=0,25\cdot42,9-11,7\cdot0,25+0,25\cdot0,8\)
\(\frac{2\cdot x-4,36}{0,125}=0,25\cdot\left(42,9-11,7+0,8\right)\)
\(\frac{2\cdot x-4,36}{0,125}=0,25\cdot32\)
\(\frac{2\cdot x-4,36}{0,125}=8\)
\(2\cdot x-4,36=8\cdot0,125\)
\(2\cdot x-4,36=1\)
\(2\cdot x=1+4,36\)
\(2\cdot x=5,36\)
\(x=\frac{5,36}{2}=2,68\)
b) \(N=\frac{1}{1\cdot5}+\frac{1}{5\cdot10}+\frac{1}{10\cdot15}+\frac{1}{15\cdot20}+...+\frac{1}{2005\cdot2010}\)
\(4N=\frac{4}{1\cdot5}+\frac{4}{5\cdot10}+\frac{4}{10\cdot15}+\frac{4}{15\cdot20}+...+\frac{4}{2005\cdot2010}\)
\(4N=1-\frac{1}{5}+\frac{1}{5}-\frac{1}{10}+\frac{1}{10}-\frac{1}{15}+\frac{1}{15}-\frac{1}{20}+...+\frac{1}{2005}-\frac{1}{2010}\)
\(4N=1-\frac{1}{2010}=\frac{2009}{2010}\)
\(N=\frac{2009}{2010}\div4=\frac{2009}{8040}\)
Bài 2:
a) ( x + 5,2 ) : 3,2 = 4,7 ( dư 0,5 )
\(x+5,2=4,7\cdot3,2+0,5\)
\(x+5,2=15,54\)
\(x=15,54-5,2=10,34\)
b)\(A=\frac{4047991-2010\cdot2009}{4050000-2011\cdot2009}\)
\(A=\frac{4047991-2010\cdot2009}{4050000-2009-2010\cdot2009}\)
\(A=\frac{4047991-2010\cdot2009}{4047991-2010\cdot2009}=1\)
Bài 3:
a) \(104,5\cdot x-14,1\cdot x+9,6\cdot x=25\)
\(x\cdot\left(104,5-14,1+9,6\right)=25\)
\(x\cdot100=25\)
\(x=\frac{25}{100}=\frac{1}{4}=0,25\)
b) \(T=\frac{2009\cdot2010+2000}{2011\cdot2010-2020}\)
\(T=\frac{2009\cdot2010+2000}{2009\cdot2010+4020-2020}\)
\(T=\frac{2009\cdot2010+2000}{2009\cdot2010+2000}=1\)
\(\frac{x}{y}\times\frac{3}{7}=\frac{4}{9}\)
\(\Rightarrow\frac{x}{y}=\frac{4}{9}:\frac{3}{7}\)
\(\Rightarrow\frac{x}{y}=\frac{28}{27}\)
\(a,14,75-7,15:5+2,6\times3,5\\ =14,75-1,43+9,1\\ =13,32+9,1\\ =22,42\\ b,13,5:4,5\times2,4+\left(156,9-80,6\right)\\ =13,5:4,5\times2,4+76,3\\ =3\times2,4+76,3\\ =7,2+76,3\\ =83,5\\ c,1,25\times4,2+119,6:5,2-23,19\\ =5,25+23-23,19\\ =28,25-23,19\\ =5,06\)
a, 5 x ( 4 + 6 x X ) = 290
4 + 6 x X = 290 : 5
4 + 6 x X = 58
6 x X = 58 - 4
6 x X = 54
X = 54 : 6
X = 9
b, ( 15 x 24 - X ) : 0,25 = 100 : \(\frac{1}{4}\)
( 15 x 24 - X ) : 0,25 = 400
15 x 24 - X = 400 x 0,25
15 x 24 - X = 100
360 - X = 100
X = 360 - 100
X = 260
c) X x 4,8 + 5,2 x X = 160
X x ( 4,8 + 5,2 ) = 160
X x 10 = 160
X = 160 : 10
X = 16
d) \(\frac{17}{5}:x=\frac{34}{5}:\frac{4}{3}\)
\(\frac{17}{5}:x=\frac{51}{10}\)
\(x=\frac{17}{5}:\frac{51}{10}\)
\(x=\frac{2}{3}\)
Chính xác đến 100 %
Học tốt #
=(3/2)x(4/3)x....x(100/99)
=(3x4x5x...x100)/(2x3x...x99)
=100/2
=50
\(a.5,2\times9+5,2=5,2\times\left(9+1\right)=5,2\times10=52\)
\(b.12,3\times101-12,3=12,3\times\left(101-1\right)=12,3\times100=1230\)
\(c.1,25\times0,25\times2,3\times4\times8\times11=\left(1,25\times8\right)\times\left(0,25\times4\right)\times2,3\times11=10\times1\times25,3=253\)
a , 5,2 . 9 + 5,2
= 5,2 . 9 + 5,2 . 1
= 5,2 . ( 9 + 1 )
= 5,2 . 10
= 52 .
b , 12,3 . 101 - 12,3
= 12,3 . 101 - 12,3 . 1
= 12,3 . ( 101 - 1 )
= 12,3 . 100
= 1230 .
c , 1,25 . 0,25 . 2,3 . 4 . 8 . 11
= ( 1,25 . 8 ) . ( 0,25 . 4 ) . ( 2,3 . 11 )
= 10 . 1 . 25,3
= 10 . 25,3
= 253 .
Hok tốt :))
\(=5.2\cdot99-5.2\cdot3+5.2\cdot4=5.2\cdot100=520\)