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7 tháng 4 2022

\(\dfrac{2}{9}-\left(\dfrac{1}{10}+\dfrac{2}{9}\right)=\dfrac{2}{9}-\dfrac{1}{10}-\dfrac{2}{9}=-\dfrac{1}{10}\)

7 tháng 4 2022

2/9 - ( 1/20 + 2/9 )= 2/9 - 1/20 - 2/9 = ( 2/9 - 2/9) - 1/20 = -1/20

21 tháng 4 2019

\ có nghĩa lả phẩy hả

21 tháng 4 2019

b. (10 2/9 - 3 5/7) - (5 2/9 + 4/7)

= 10 2/9 - 3 5/7 - 5 2/9 - 4/7

= (10 2/9 - 5 2/9) - (3 5/7 -4/7)

= 5 - 3 1/7

= 5 - 22/7

= 13/7

\(\left(13\frac{4}{9}+2\frac{1}{9}\right)-3\frac{4}{9}\)

\(=\left(\frac{121}{9}+\frac{19}{9}\right)-\frac{31}{9}\)

\(=\frac{140}{9}-\frac{31}{9}\)

\(=\frac{109}{9}\)

 
18 tháng 4 2019

\(1,25\div\frac{15}{20}+\left(25\%-\frac{5}{6}\right)\div4\frac{2}{3}\)

\(=1,25\div\frac{3}{4}+\left(\frac{25}{100}-\frac{5}{6}\right)\div\frac{14}{3}\)

\(=1,25\times\frac{4}{3}+\left(\frac{6}{24}-\frac{20}{24}\right)\div\frac{14}{3}\)

\(=\frac{5}{3}+\frac{-14}{24}\times\frac{14}{3}\)

\(=\frac{60}{36}+\frac{-98}{36}\)

\(=\frac{-38}{36}=\frac{-19}{18}\)

11 tháng 2 2018

Ta có: A = 1+(-2)+3+(-4)+....+2003+(-2004) = 2005

     => A = (-1)+(-1)+(-1)+....+(-1) = (-1) x 2004 = -2004

14 tháng 8 2017

a) \(12.79-64.37+12.21-36.37+12000\)

\(=\left(12.79+12.21\right)-\left(64.37+36.37\right)+12000\)

\(=\left[12\left(79+21\right)-37\left(64+36\right)+12000\right]\)

\(=12.100-37.100+12000\)

\(=1200-3700+12000\)

\(=9500\)

b) \(112.39+1237+112.61\)

\(=\left(112.39+112.61\right)+1237\)

\(=112\left(39+61\right)+1237\)

\(=112.100+1237\)

\(=11200+1237\)

\(=12437\)

c) \(35.762+351-35.662\)

\(=35\left(762-662\right)+351\)

\(=35.100+351\)

\(=3500+351\)

\(=3851\)

d) \(\frac{20}{4}-\frac{5^9}{5^8}=5-5=0\)

e) \(\left(\frac{5^{19}}{5^{17}}-4\right):7=\left(5^2-4\right):7=21:7=3\)

f)  \(\frac{84}{4}+\frac{3^9}{3^7}+5^0=21+3^2+1=31\)

1 tháng 4 2022
1 tháng 4 2022

a)\(=\dfrac{3}{6}-\dfrac{4}{6}=-\dfrac{1}{6}\)

b)\(=-\dfrac{35}{9}-\dfrac{10}{9}=-\dfrac{45}{9}=-5\)

c)\(=\left[-10+9\right].\left[1,3.\left(2,5+7,5\right)\right]=-1.\left[1,3.10\right]=-1.13=-13\)

24 tháng 3 2021

=7/11+5/6+4/11-1/6

=(7/11+4/11)+(5/6-1/6)

=1+2/3

=5/3

\(A,\dfrac{7}{11}+\dfrac{5}{6}-\dfrac{-4}{11}-\dfrac{1}{6}\)

\(= (\dfrac{7}{11}+\dfrac{-4}{11})-(\dfrac{5}{6}-\dfrac{1}{6})\)

\(=\dfrac{3}{11}-\dfrac{2}{3}\)

\(= \dfrac{9}{33}-\dfrac{22}{33}\)

\(= \dfrac{-13}{33}\)

\(B,\dfrac{5}{9}.\dfrac{7}{3}+\dfrac{5}{9}.\dfrac{9}{13}-\dfrac{5}{9}:\dfrac{13}{5}\)

\(=(\dfrac{5}{9}.\dfrac{5}{9}:\dfrac{5}{9}).\dfrac{7}{3}+\dfrac{9}{13}-\dfrac{13}{5}\)

\(=(\dfrac{5}{9}.\dfrac{7}{3})+(\dfrac{9}{13}-\dfrac{13}{5})\)

\(=(\dfrac{5}{9}.\dfrac{21}{9})+(\dfrac{45}{65}-\dfrac{169}{65})\)

\(=\dfrac{35}{27}+\dfrac{-124}{65}\)

\(=\dfrac{2275}{1755}+\dfrac{-3348}{1755}\)

\(=\dfrac{-1073}{1755}\)