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\(\frac{16.17-5}{16.16+11}\)
\(=\frac{16.16+16-5}{16.16+11}\)
\(=\frac{16.16+11}{16.16+11}\)
\(=1\)
\(\frac{16\cdot17-5}{16\cdot16+11}\)
\(=\frac{16\cdot17-5}{16\cdot17-16-11}\)
\(=\frac{16\cdot17-5}{16\cdot17-5}\)
\(=1\)
mk ko copy của Trần Thùy Dung nhé
\(\frac{16.17-5}{16.16+11}\)
\(=\frac{17-5}{16+11}\)
\(=\frac{12}{27}\)
Bài làm
\(\frac{16x17-5}{16x16+11}\)
\(=\frac{272-5}{256+11}\)
\(=\frac{267}{267}\)
\(=1\)
# Học tốt #
\(\frac{16.17-5}{16.16+11}\)
\(=\frac{16.\left(16+1\right)-5}{16^2+11}\)
\(=\frac{16^2+16-5}{16^2+11}\)
\(=\frac{16^2+11}{16^2+11}=1\)
(Nhớ k cho mình với nhé!)
\(\frac{5}{11}.\frac{3}{7}+\frac{5}{7}.\frac{4}{11}-\frac{3}{11}\)
\(=\frac{3}{11}.\frac{5}{3}.\frac{3}{7}+\frac{5}{7}.\frac{4}{3}.\frac{3}{11}-\frac{3}{11}\)
\(=\frac{3}{11}.\left(\frac{5}{7}+\frac{20}{21}-1\right)\)
\(=\frac{3}{11}.\left(\frac{15+20}{21}-1\right)\)
\(=\frac{3}{11}.\left(\frac{35}{21}-1\right)\)
\(=\frac{3}{11}.\frac{14}{21}\)
\(=\frac{14}{77}\)
5/11 x 3/7 + 5/7 x 4/11 - 3/11
= 5/11 x 3/7 + 5/11 x 4/7 - 3/11
= 5/11 x ( 3/7 + 4/7 ) - 3/11
= 5/11 x 1 - 3/11
= 5/11 - 3/11
= 2/11
Tk nha !!
Trả lời
\(P=\frac{\frac{2}{3}-\frac{1}{4}+\frac{5}{11}}{\frac{5}{12}+1-\frac{7}{11}}\)
\(\Leftrightarrow P=\frac{\frac{8}{12}-\frac{3}{12}+\frac{5}{11}}{\frac{5}{12}+\frac{12}{12}-\frac{7}{11}}\)
\(\Leftrightarrow P=\frac{\frac{5}{12}+\frac{5}{11}}{\frac{17}{12}-\frac{7}{11}}\)
\(\Leftrightarrow P=\frac{\frac{55}{132}+\frac{60}{132}}{\frac{187}{132}-\frac{84}{132}}\)
\(\Leftrightarrow P=\frac{\frac{115}{132}}{\frac{103}{132}}\)
\(\Leftrightarrow P=\frac{115}{132}\)
=8/19x(5/11+7/11)+8/11x1/19
=8/19x1+8/11x1/19
=8x1/19+8/11x1/19
=1/19x(8+8/11)
còn lại bấm máy tính
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
P=7/11 .(-5/13+1)+8/11.-7/13
P=7/11.8/13+8/11.-7/13
P=7.8/11.13+8/11.-7/13
P=7/13.8/11+8/11.-7/13
Rồi
gộp thừa số chung là 8/11 vào
kết quả là 0 nha
à nhầm,
đọc lại thì thấy Nguyễn Thành Công sai rồi
các bạn cứ sai bạn ấy thật lực cho mk nha
tức nó vì làm mk sai
a, 3 \(\frac{14}{19}\)+ \(\frac{13}{17}\)+ \(\frac{35}{43}\)+ 6\(\frac{5}{19}\)+ \(\frac{8}{43}\)= \(\left(3\frac{14}{19}+6\frac{5}{19}\right)+\left(\frac{35}{43}+\frac{8}{43}\right)+\frac{13}{17}=\)\(9+1+\frac{13}{17}=8+\frac{13}{17}=8\frac{13}{17}\)
b, \(\frac{-5}{7}.\frac{2}{11}+\frac{-5}{7}.\frac{9}{11}+1\frac{5}{7}\)\(=\frac{-5}{7}\left(\frac{2}{11}+\frac{9}{11}\right)+1\frac{5}{7}\)\(=\frac{-5}{7}.1+1\frac{5}{7}\)\(=\frac{-5}{7}+\frac{12}{7}=\frac{7}{7}=1\)
Chúc bn học tốt
\(3\frac{14}{19}+\frac{13}{17}+\frac{35}{43}+6\frac{5}{19}+\frac{8}{43}\)
\(=\left(3\frac{14}{19}+6\frac{5}{19}\right)+\left(\frac{35}{43}+\frac{8}{43}\right)+\frac{13}{17}\)
\(=10+1+\frac{13}{17}=11+\frac{13}{17}=11\frac{13}{17}\)
\(\frac{16.17-5}{16.16+11}\)
\(=\frac{16.\left(16+1\right)-5}{16^2+11}\)
\(=\frac{16^2+16-5}{16^2+11}\)
\(=\frac{16^2+11}{16^2+11}\)
\(=1\)
(Nhớ k cho mình với nhé!)
\(\frac{16x17-5}{16x16+11}\)
=\(\frac{16x\left(16+1\right)-5}{16x16+11}\)
=\(\frac{16x16+16x1-5}{16x16+11}\)
= \(\frac{16x16+11}{16x16+11}\)
= 1 ( vì TS = MS )