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NT
26 tháng 3 2018
a) \(\left(56.27+56.35\right):62\)
\(=56.\left(27+35\right):62\)
\(=56.62:62\)
\(=56\)
b) \(3\frac{2}{7}.12\frac{1}{2}-3\frac{2}{7}.5\frac{1}{2}+1\frac{1}{2}:\frac{3}{4}\)
\(=3\frac{2}{7}.\left(12\frac{1}{2}-5\frac{1}{2}\right)+\frac{3}{2}.\frac{4}{3}\)
\(=\frac{23}{7}.7+2\)
\(=23+2\)
\(=25\)
c) \(\frac{16.17-5}{16.16+11}\)
\(=\frac{16.\left(16+1\right)-5}{16.16+11}\)
\(=\frac{16.16+16-5}{16.16+11}\)
\(=\frac{16.16+11}{16.16+11}\)
\(=1\)
KL
23 tháng 8 2017
1. \(\dfrac{16.17-5}{16.16-1}:\left(x-\dfrac{2}{3}\right)=\dfrac{1}{3}\)
<=> \(\dfrac{272-5}{256-1}:\left(x-\dfrac{2}{3}\right)=\dfrac{1}{3}\)
<=> \(\dfrac{267}{255}:\left(x-\dfrac{2}{3}\right)=\dfrac{1}{3}\)
<=> x - \(\dfrac{2}{3}=\dfrac{267}{85}\)
<=> x = \(\dfrac{971}{255}\)
@Triều Nguyễn Quốc
KL
23 tháng 8 2017
2. a, 8\(\dfrac{1}{5}\left(11\dfrac{94}{1591}-6\dfrac{38}{1517}\right):8\dfrac{11}{13}\)
= \(\dfrac{41}{5}\left(5\dfrac{60}{1763}\right):\dfrac{355}{43}\)
= \(\dfrac{41}{5}.\dfrac{8875}{1763}:\dfrac{355}{43}\)
= \(\dfrac{1775}{43}:\dfrac{355}{43}\)
= 5
@Triều Nguyễn Quốc
23 tháng 9 2015
\(\frac{16.17-5}{16.16+11}=\frac{16.16+16-5}{16.16+11}=\frac{16.16+11}{16.16+11}=1\)
27 tháng 8 2018
\(\frac{16.1-5}{16.16+11}=\frac{16-5}{16+11}=\frac{5}{11}\)
27 tháng 8 2018
\(\frac{16.1-5}{16.16+11}=\frac{16-5}{16+11}=\frac{5}{11}\)
28 tháng 3 2018
\(\frac{16.17-5}{16.16+11}=\frac{16.\left(16+1\right)-5}{16.16+11}=\frac{16.16+16-5}{16.16+11}=\frac{16.16+11}{16.16+11}=1\)
18 tháng 7 2017
\(\dfrac{-5}{7}.\dfrac{2}{11}+\dfrac{-5}{7}.\dfrac{9}{14}+1\dfrac{5}{7}\)
\(=\dfrac{-5}{11}.\dfrac{2}{7}+\dfrac{-5}{11}.\dfrac{9}{7}+\dfrac{12}{7}\)
\(=\dfrac{-5}{11}\left(\dfrac{2}{7}+\dfrac{9}{7}\right)+\dfrac{12}{7}\)
\(=\dfrac{-5}{11}.\dfrac{11}{7}+\dfrac{12}{7}\)
\(=\dfrac{-5}{7}+\dfrac{12}{7}=\dfrac{7}{7}=1\)
2 tháng 5 2017
\(\dfrac{-5}{7}.\dfrac{2}{11}+\dfrac{-5}{11}.\dfrac{9}{7}-1\dfrac{5}{7}\)
\(=\dfrac{-5}{11}.\dfrac{2}{7}+\dfrac{-5}{11}.\dfrac{9}{7}-\dfrac{12}{7}\)
\(=\dfrac{-5}{11}\left(\dfrac{2}{7}+\dfrac{9}{7}\right)-\dfrac{12}{7}\)
\(=\dfrac{-5}{11}.\dfrac{11}{7}-\dfrac{12}{7}\)
\(=\dfrac{-5}{7}+\dfrac{-12}{7}=\dfrac{-17}{7}\)
Ta có: \(\dfrac{16.17-5}{16.16+11}\)= \(\dfrac{16.\left(16+1\right)-5}{16.16+11}\)
= \(\dfrac{16.16+16-5}{16.16+11}\)= \(\dfrac{16.16+11}{16.16+11}\)= 1
\(\dfrac{16.17-5}{16.16+11}\) = \(\dfrac{16.\left(16+1\right)-5}{16.16+11}\) = \(\dfrac{16.16+16-5}{16.16+11}\) =\(\dfrac{16.16+11}{16.16+11}=1\)