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a)(5\(\frac{2}{7}\). \(\frac{8}{11}\)+ \(\frac{2}{11}\).5\(\frac{2}{7}\)): 3\(\frac{4}{11}\)- 1\(\frac{3}{7}\)
= 5\(\frac{2}{7}\). (\(\frac{8}{11}\)+\(\frac{2}{11}\)):\(\frac{37}{11}\)-\(\frac{10}{7}\)
= \(\frac{37}{7}\).\(\frac{8}{11}\).\(\frac{11}{37}\)-\(\frac{10}{7}\)
= \(\frac{37.8.11}{7.11.37}\)- \(\frac{10}{7}\)
= \(\frac{8}{7}\)-\(\frac{10}{7}\)
= \(\frac{-2}{7}\)
a, 3 \(\frac{14}{19}\)+ \(\frac{13}{17}\)+ \(\frac{35}{43}\)+ 6\(\frac{5}{19}\)+ \(\frac{8}{43}\)= \(\left(3\frac{14}{19}+6\frac{5}{19}\right)+\left(\frac{35}{43}+\frac{8}{43}\right)+\frac{13}{17}=\)\(9+1+\frac{13}{17}=8+\frac{13}{17}=8\frac{13}{17}\)
b, \(\frac{-5}{7}.\frac{2}{11}+\frac{-5}{7}.\frac{9}{11}+1\frac{5}{7}\)\(=\frac{-5}{7}\left(\frac{2}{11}+\frac{9}{11}\right)+1\frac{5}{7}\)\(=\frac{-5}{7}.1+1\frac{5}{7}\)\(=\frac{-5}{7}+\frac{12}{7}=\frac{7}{7}=1\)
Chúc bn học tốt
\(3\frac{14}{19}+\frac{13}{17}+\frac{35}{43}+6\frac{5}{19}+\frac{8}{43}\)
\(=\left(3\frac{14}{19}+6\frac{5}{19}\right)+\left(\frac{35}{43}+\frac{8}{43}\right)+\frac{13}{17}\)
\(=10+1+\frac{13}{17}=11+\frac{13}{17}=11\frac{13}{17}\)
\(B=\frac{5}{7}.\frac{2}{11}+\frac{5}{7}.\frac{12}{11}-\frac{5}{7}.\frac{7}{11}\)
\(B=\frac{5}{7}.\left(\frac{2}{11}+\frac{12}{11}\right)-\frac{5}{7}.\frac{7}{11}\)
\(B=\frac{5}{7}.\frac{14}{11}-\frac{5}{7}.\frac{7}{11}\)
\(B=\frac{5}{7}.\left(\frac{14}{11}-\frac{7}{11}\right)\)
\(B=\frac{5}{7}.\frac{7}{11}\)
\(B=\frac{35}{77}=\frac{5}{11}\)
a) \(\frac{27}{8}\times\frac{5}{7}\times\frac{8}{27}+\frac{2}{7}\)
\(=\frac{27\times5\times8}{8\times7\times27}+\frac{2}{7}\)
\(=\frac{5}{7}+\frac{2}{7}\)
\(=1\)
b) \(1,6\times\frac{25}{32}-\left(\frac{2}{3}+\frac{4}{5}\right):\frac{11}{5}\)
\(=\frac{8}{5}\times\frac{25}{32}-\left(\frac{2}{3}+\frac{4}{5}\right).\frac{5}{11}\)
\(=\frac{5}{4}-(\frac{10}{33}+\frac{4}{11})\)
\(=\frac{5}{4}-\frac{2}{3}\)
\(=\frac{7}{12}\)
chịu luôn rùi! ! phần b, mk ko tính nhanh đc! cho mk xin lỗi bn nhiều nha!
\(5\frac{2}{7}\).\(\frac{8}{11}+5\frac{2}{7}\).\(\frac{5}{11}-5\frac{2}{7}\).\(\frac{2}{11}\)
=\(5\frac{2}{7}\).\(\)(\(\frac{8}{11}+\frac{5}{11}-\frac{2}{11}\))
=\(5\frac{2}{7}\).1
=\(5\frac{2}{7}\)