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Bài 41: Tìm 2 biểu thức có giá trị bằng nhau:
a) \(4.2145=8580\)
b) \(3964.6=23784\)
c) \(10287.5=51435\)
d) \(\left(3+2\right).10287=5.10287=51435\)
e) \(\left(2100+45\right).4=2145.4=8580\)
g) \(\left(4+2\right).\left(3000+964\right)=6.3964=23784\)
Vậy các cặp có giá trị bằng nhau là:
\(4.2145=\left(2100+45\right).4\)
\(3964.6=\left(4+2\right).\left(3000+964\right)\)
\(10287.5=\left(3+2\right).10287\)
a/ 4 x 2145 = 2145 x 4
b/ 3964 x 6 = 6 x 3964
c/ 10287 x 5 = 5 x 10287
d/ ( 3 + 2 ) x 10287 = 10287 x ( 3 + 2 )
e/ ( 2100 + 45 ) x 4 = 4 x ( 2100 + 45 )
g/ ( 4 + 2 ) x ( 3000 + 964 ) = ( 4 + 2 ) x ( 3000 + 964 )
Đoán mò thôi :)))
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13 x 45 + 55 x 13 - 13 x 100
= 13 x (45 + 55 - 100)
= 13 x 0
= 0
~Học tốt~
13x45+55x13-13x100
=13x(45+55-100)
=13x0
=0
#Thiên_Hy
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72 x 11 = 792
32 x 11 = 352
45 x 11 = 495
61 x 11 = 671
53 x 11 = 583
72 * 11 = 792
32 * 11 = 352
45 * 11 = 495
61 *11 = 671
53 *11 = 583
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a, 45 x 46 + 45 x 45 - 30 - 15= 45x( 46+45) -30 -15= 45 x 91 - 30 - 15= 4095 - 30 - 15= 4050
b, 891 x 29 + 29 x 8+ 29= 29 x ( 891 + 8+ 1)= 29 x 900= 26100
c, 73 x ( 84+17) + 27 x (74+27)= 73 x 101 + 27 x 101= 101 x ( 73+27)= 101 x 100= 10100
d, chịu
d, đề bài= 13 x ( 99 + 2) + 13 x 1001+ 11 x 1300= 13 x 101 + 13 x 1001+ 13 x 1100= 13 x ( 101 + 1001 + 1100) = 13 x 2202= 28626
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a=13 =>45a=585
a=26 =>45a=1170
a=39 =>45a=1755 đúng ko ạ :)
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a) 4 x 2145 = d) (2100 + 45) x 4 (a = d)
c) 3964 x 4 = (4x 2) x(3000 + 964) (c = g)
e) 10287 x 5 = b) (3 + 2) x 10287 (b = e)
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a) 4 x 2145 = d) (2100 + 45) x 4 (d)
c) 3964 x 4 = (4x 2) x(3000 + 964) (g)
e) 10287 x 5 = b) (3 + 2) x 10287 (b)
=3000:(13+87)
=3000:100
=30
45x39+45x61
=45x(39+61)
=45x100
=4500
3000:13+3000:87
=3000:(13+87)
=3000:100
=30
HT