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n = 25.3x^2
Vì n có 60 ước nên ta có:
(5 + 1)(x2 + 1) = 60
=> 6(x2 + 1) = 60
=> x2 + 1 = 10
=> x2 = 9
=> x = 3 (Vì x thuộc N*)
Do đó n = 25.33^2 = 25.39 = 629856
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Ta có: B = 3 + 35 + 37 + .... + 31991
=> B = (3 + 35) + (37 + 311) + .... + (31987 + 31991)
=> B = 3.(1 + 34) + 37.(1 + 34) + ... + 31987.(1 + 34)
=> B = 3.82 + 37.82 + .... + 31987. 82
=> B = 82.(3 + 37 + ... + 31987) chia hết cho 41
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C1:
A = \(3\frac{5}{7}+4\frac{2}{3}\)\(-\left(2\frac{5}{7}+2\frac{1}{3}\right)\)
A = \(3\frac{5}{7}+4\frac{2}{3}\)\(-2\frac{5}{7}-2\frac{1}{3}\)
A = \(3\frac{5}{7}-2\frac{5}{7}+4\frac{2}{3}-2\frac{1}{3}\)
A = \(1+2\frac{1}{3}\)
A = \(1+\frac{7}{3}\)
A = \(\frac{10}{3}\)
C2:
A = \(3\frac{5}{7}+4\frac{2}{3}\)\(-\left(2\frac{5}{7}+2\frac{1}{3}\right)\)
A = \(\frac{26}{7}+\frac{14}{3}-\frac{19}{7}-\frac{7}{3}\)
A = \(1+\frac{14}{3}-\frac{7}{3}=\frac{10}{3}\)
C1: Ta có: \(B=8\frac{1}{9}-3\frac{2}{7}+6\frac{8}{7}-3\frac{5}{7}\)
\(=8+\frac{1}{9}-\left(3+\frac{2}{7}\right)+6+\frac{8}{7}-\left(3+\frac{5}{7}\right)\)
\(=8+\frac{1}{9}-3-\frac{2}{7}+6+1+\frac{1}{7}-3-\frac{5}{7}\)
= \(\left(8-3+6+1-3\right)+\left(\frac{1}{9}-\frac{2}{7}+\frac{1}{7}-\frac{5}{7}\right)\)
\(=9+\left(\frac{-47}{63}\right)\)
\(=\frac{520}{63}\)
C2: Đổi hỗn số ra phân số rồi tính ( cj nghĩ thế )
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22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64
27 = 128; 28 = 256; 29 = 512; 210 = 1024
32 = 9; 33 = 27; 34 = 81; 35 = 243
42 = 16; 43 = 64; 44 = 256
52 = 25; 53 = 125; 54 = 625
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dai the giai bao gio xong chac mua quyt nam sau moi giai xong
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Bài 1a
B=4/1.3 + 4/3.5 + 4/5.7+...+4/2017.2019
B=4.2/(1.3).2 + 4.2/(3.5).2 + 4.2/(5.7).2+....+4.2/(2017.2019).2
B=2.( 2/1.3 + 2/3.5 + 2/5.7 +...+ 2/2017.2019 )
B=2.(1-1/3+1/3-1/5+1/5-1/7+....+1/2017-1/2019)
B=2.(1-1/2019)
B=2.(2019/2019-1/2019)
B=2.2018/2019
B=4036/2019
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\(\Rightarrow2S=6+\frac{3}{1}+\frac{3}{2}+...+\frac{3}{2^8}\)
\(\Rightarrow2S-S=\left(6+3+\frac{3}{2}+...+\frac{3}{2^8}\right)-\left(3+\frac{3}{2}+...+\frac{3}{2^9}\right)\)
\(\Rightarrow S=3-\frac{3}{2^9}\)
\(S=3+\frac{3}{2}+\frac{3}{2^2}+\frac{3}{2^3}+...+\frac{3}{2^9}\)
\(\Rightarrow\frac{1}{2}.S=\frac{3}{2}+\frac{3}{2^2}+\frac{3}{2^3}+...+\frac{3}{2^{10}}\)
\(\Rightarrow S-\frac{1}{2}.S=\frac{1}{2}.S=3+\frac{3}{2}+\frac{3}{2^2}+\frac{3}{2^3}+...+\frac{3}{2^9}-\left(\frac{3}{2}+\frac{3}{2^2}+\frac{3}{2^3}+...+\frac{3}{2^{10}}\right)\)
\(\Rightarrow\frac{1}{2}.S=3-\frac{3}{2^{10}}\)
\(\Rightarrow S=6-\frac{6}{2^{10}}\)
(-3)^2+(-5)^3//-5/
=9+(-125)/5
=9+(-25)=16
(-3)2 +( -5 )3 : |-5|
= 9 - 15 :5
= 9 - 3
= 6