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( 27 - 11 ) + ( 20 - 9 - 27 )
= 27 - 11 + 20 - 9 - 27
= (27 - 27) + 20 - (11 + 9)
= 20 - 20 = 0
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a) -175 - ( -7 . 5^2 + 4 . 2^3)
= -175 - ( -175 + 32 )
= -175 - -175 +32
= 0 +32
= 32
b) (-27) + 20 + (-9) + 27 + (-11)
= (-27 + 27 ) + 20 + (-11) + (- 9)
= 0 + 9 + (-9)
= 0 + 0
= 0
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\(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)
\(=\frac{5.\left(2^2\right)^{15}.\left(3^2\right)^9-2^2.3^{20}.\left(2^3\right)^9}{5.2^9.\left(2.3\right)^{19}-7.2^{29}.\left(3^3\right)^6}\)
\(=\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}\)
\(=\frac{5.2^{30}.3^{18}-2^{29}.3^{20}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\)
\(=\frac{2^{29}.3^{18}.\left(5.2-3^2\right)}{2^{28}.3^{18}.\left(5.3-7.2\right)}\)
\(=\frac{2^{29}.3^{18}.1}{2^{28}.3^{18}.1}\)
\(=\frac{2^{29}}{2^{28}}=2\)
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a: \(=\dfrac{20\left(1-12\right)}{30\left(-1-10\right)}=\dfrac{2}{3}\)
b: \(=\dfrac{11^9\cdot3^{18}}{3^{18}\cdot11^{11}}=\dfrac{1}{121}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(=\dfrac{20\left(1-12\right)}{30\left(-1-10\right)}=\dfrac{20}{30}=\dfrac{2}{3}\)
b: \(=\dfrac{11^9\cdot3^{18}}{3^{10}\cdot11^{11}\cdot3^8}=\dfrac{1}{121}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Tách hai dấu ngoặc thành hai vế A và B
Ta có :
A=5.415.99-4.320.89=5.230.318-22.227.320
=229.318(2.5-32)=229.318
B=5.29.619-7.229.276=5.29.219.319-7.229.318
=228.318(5.3-7.2)=228.318
=>A:B=229.318:228:318=2
=[(-27)+27]+[20+(-9)+(-11)] = 0+ 0=0
=0 nha Tran Thi Xuan