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![](https://rs.olm.vn/images/avt/0.png?1311)
A=1.2+2.3+3.4+...+99.100
=>3A=1.2.3+2.3.3+3.4.3+...+99.100.3
=1.2.3+2.3(4-1)+3.4(5-2)+....+99.100(101-98)
=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+99.100.101-98.99.100
=99.100.101=999900
=>A=333300
vậy A=333300
l-i-k-e cho mình nha
![](https://rs.olm.vn/images/avt/0.png?1311)
A=1.2+ 2.3+.......+99.100
Nhân cả 2 vế với 3, ta được:
3A=1.2.3+ 2.3.3+ 3.4.3+ 4.5.3+...... 99.100.3
= 1.2.3 + 2.3(4-1) + 3.4.(5-2) +...+ 99.100.(101-98)
= 1.2.3 + 2.3.4 -1.2.3 + 3.4.5-2.3.4 +...+ 99.100.101-98.99.100
= 99.100.101
----> A = (99.100.101):3
A = 333300
Vậy A=333300
gọi tổng là S ta có
3S=1.2.3-0.1.2+2.3.4-1.2.3+....+99.100.101-98.99.100
=>3s=99.100.101
=>S=99.100.101:3=333300
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có : M = 1 . 2 + 2 . 3 + 3 . 4 + ........+ 99 . 100
3M = 1 . 2 . 3 + 2 . 3 . ( 4 - 1 ) + 3 . 4 . ( 5 - 2 ) + ..........+ 99 . 100 . ( 101 - 98 )
3M = 1 . 2 . 3 + 2 . 3 . 4 - 1. 2 . 3 + 3 . 4 . 5 - 2 . 3 . 4 + ..........+ 99 . 100 . 101 - 98 . 99 . 100
3M = 99 . 100 . 101
M = 33 . 100 . 101 = 333300
Đúng nha !!!
![](https://rs.olm.vn/images/avt/0.png?1311)
gọi tổng là S ta có
3S=1.2.3-0.1.2+2.3.4-1.2.3+......+99.100.101-98.99.100
=>3S=98.99.100
=>S=\(\frac{98.99.100}{3}=323400\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: 3A=1.2.3+2.3.3+3.4.3+.....+99.100.3
3A=1.2.3+2.3.(4-1)+3.4..(5-2)+....+99.100.(101-98)
3A=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+....+99.100.101-98.99.100
3A=99.100.101
A=\(\frac{99.100.101}{3}\)
A=333300
Đặt A= 1.2+2.3 +.......+99.100
3A= 1.2.3+2.3.4+3.4.3 +......+ 99.100.3
3A= 1.2. (3 - 0) + 2.3.(4 - 1) +3.4. (5 - 2)....... . 99.100. (101 - 98)
3A = (1.2.3 + 2.3.4 + 3.4.5 +...... + 99.100.101) - (0.1.2 + 1.2.3 + 2.3.4 +.......+ 98.99.100)
3A = 99.100.101 - 0.1.2
3A = 999900 - 0
3A= 999900
A= 999900 : 3
A = 333300
![](https://rs.olm.vn/images/avt/0.png?1311)
=>3C=1.2.3+2.3.3+...+99.100.3
= 1.2.(3 - 0) + 2.3.(4 - 1) +...+ 99.100.(101 - 98)
= 1.2.3 - 0.1.2 + 2.3.4 - 1.2.3 +...+ 99.100.101 - 98.99.100
= 99.100.101
=>\(C=\frac{99.100.101}{3}=333300\)
\(C = 1.2+2.3+3.4+...+99.100\)
\(\Rightarrow3C=1.2.3+2.3.3+3.4.3+...+99.100.3\)
\(3C=1.2.\left(3-0\right)+2.3.\left(4-1\right)+3.4.\left(5-2\right)+...+99.100.\)\(\left(101-98\right)\)
\(3C=\left(1.2.3+2.3.4+3.4.5+...+99.100.101\right)\)\(-\left(0.1.2+1.2.3+2.3.4+...+98.99.100\right)\)
\(3C=99.100.101-0.1.2\)
\(3C=999900-0=999900\)
\(C=999900:3\)
\(\Rightarrow C=333300\)
![](https://rs.olm.vn/images/avt/0.png?1311)
3Z = 1.2.3 + 2.3.3 + 3.3.4 + .... + 3.99.100
Z= 1.2.3 + 2.3.4 + 3.4.5 + .... + 99.100.101
=> Z - 3Z = 1.2.3 - 1.2.3 + 2.3.(4-3) + 3.4 ( 5-3) + .... + 99.100 ( 101 -3)
= 1.2.3 + 2.3.4 + .... + 98.99.100
=> Z -3Z = Z - 99.100.101
=> Z = 99.100.101/3 = 333300
![](https://rs.olm.vn/images/avt/0.png?1311)
A= 1.2 +2.3+ 3.4 +4.5+...+ 99.100
3A = 1.2.3 +2.3.3+ 3.4.3+...+99.100.3
3A = 1.2.3 +2.3(4-1)+ 3.4(5-2)+...+99.100(101-98)
3A = 1.2.3 +2.3.4-1.2.3+ 3.4.5-2.3.4+...+99.100.101-98.99.100
3A = 999900
A = 333300
A= 1. 2 + 2.3 +3.4 + 4.5 + 99.100
A=2 +6+12+20 + 9900
A = 9930
bn nha
tk mk nha
Đặt P = 1.2+2.3+3.4+...+99.100
3P = 1.2.3+2.3.3+3.4.3+...+99.100+3
3P = 1.2 (3-0) +2.3(4-1)+3.4(5-2) +...+ 99.100( 101-98)
3P = ( 1.2.3 + 2.3.4 + 3.4.5 + 99.100.101 ) -( 0.1.2 + 1.2.3 + 2.3.4 + ....+ 98.99.100)
3P = 99.100.101 - 0.1.2
3P = 999900 - 0
3P = 999900
P = 999900 : 3
P = 333300
( Câu trả lời bằng hình ảnh)