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a.17⋅(29−(−111)]+29⋅(−17)17⋅(29−(−111))+29⋅(−17)
=17⋅(29+111)−29⋅17=17⋅(29+111)−29⋅17
=17⋅(29+111−29)=17⋅(29+111−29)
=17⋅(29−29+111)=17⋅(29−29+111)
=17⋅111=17⋅111
=2997=2997
b.19⋅43+(−20)⋅43−(−40)19⋅43+(−20)⋅43−(−40)
=19⋅43−20⋅43+40=19⋅43−20⋅43+40
=43(19−20)+40=43(19−20)+40
=43⋅(−1)+40=43⋅(−1)+40
=−43+40=−43+40
=−3=−3
[ chúc bạn học tốt ]
\(a,\left(4+32+6\right)+\left(10-32-2\right)\\ =\left(10+32\right)+\left(10-32-2\right)\\ =10+32+10-32-2\\ =20-2\\ =18\\ b,300:4+300:6-25\\ =300:\left(4+6\right)-25\\ =300:10-25\\ =30-25\\ =5\\ c,17.\left[29-\left(-111\right)\right]+29.\left(-17\right)\\ =17.\left(29+111\right)+29.\left(-1\right).17\\ =17.\left(29+111-29\right)\\ =17.111=1887\\ d,19.43+\left(-20\right).43-\left(-40\right)\\ =19.43+\left(-20\right).43+40\\ =43.\left(19-20\right)+40\\ =-43+40\\ =-3\)
\(\left(-12\right)+\left(-13\right)+36+\left(-11\right)=\left(-12-13-11\right)+36\)
\(=\left(-36\right)+36\)
\(=0\)
a)\(2575+37-2576-29=\left(2575-2576\right)+\left(37-29\right)=-1+9=8\)
b)\(34+35+36+37-14-15-16-17\)
\(=\left(34-14\right)+\left(35-15\right)+\left(36-16\right)+\left(37-17\right)\)
\(=20+20+20+20+20\)
\(=20.5\)
\(=100\)
a) 2575+37-2576-29=(2575+2576)-29+37=-1-29+37=-30+37=7
b)34+35+36+37-14-15-16-17=(34-14)+(35-15)+(36-16)+(37-17)=20+20+20+20=80
X
a,2575+37-2576-29=37+[(2575-2576)-29]=37+(-30)=7
b,34+35+36+37-14-15-16-17=(34-14)+(35-15)+(36-16)+(37-17)=20+20+20+20=80
a, 24.( 5 - 178 ) + 178 .(10 + 24)
= 24.5 - 24 .178 + 178 .10 + 178.24
= (24.5 + 178.10) -( 24.178 - 178.24)
=(120 + 1780) - 0
= 1900
b ,29.(-101)
= 29.( -100 -1)
= - 2900 - 29
= -2929
c, (-56 + 130) - (43 - 56) - (-20 - 43)
= -56 + 130 - 43 + 56 + 20 + 43
= (-56 + 56) - (43 - 43) + ( 130 + 20)
= 0 - 0 + 150
= 150
a) Ta có: \(17\cdot\left[29-\left(-111\right)\right]+29\cdot\left(-17\right)\)
\(=17\cdot\left[29+111-29\right]\)
\(=17\cdot111=1887\)
b) Ta có: \(19\cdot43+\left(-20\right)\cdot43-\left(-40\right)\)
\(=43\cdot\left(19-20\right)+40\)
\(=-43+40=-3\)
Sao Nguyễn Lê Phước Thịnh lm khác bn ??? Ai sai