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Giải:
a)124+(-52).124 + (-124).(-47)
=124+(-52).124+124.47
=124+124.[(-52)+47]
=124+124.(-5)
=124.(-4)
=-496
b)(-2)3.(-6).(-5)3
=-8.(-6).(-125)
=-8.(-125).(-6)
=1000.(-6)
=-6000
Chúc bạn học tốt
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áp dụng quy tắc đổi dấu
b) 35-19+2019-35-2019=-19+[(35-35)-(2019-2019)]
=-19+0+=-19
a) \(124+\left(-56\right).124+\left(-124\right)\left(-47\right)=124.1-56.124+124.47\)
\(=124.\left(1-56+47\right)=124.\left(-8\right)=-992\)
b) \(35-19+2019-35+\left(-2019\right)=35-19+2019-35-2019\)
\(=\left(35-35\right)+\left(2019-2019\right)-19=0+0-19=0-19=-19\)
c) \(345-150\div\left[\left(3^3-24\right)^2-\left(-21\right)\right]+2020^0\)
\(=345-150\div\left[\left(27-24\right)^2+21\right]+1=345-150\div\left(3^2+21\right)+1\)
\(=345-150\div24+1=345-6,25+1=339,75\)
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https://www.google.com.vn/search?q=google+calculator&rlz=1C1GGRV_enVN751VN751&oq=google+cal&aqs=chrome.2.0j69i57j0l4.5783j0j7&sourceid=chrome&ie=UTF-8
Vào đó tính
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Bài 1 \(a)5^{36}=(5^3)^{12}=125^{12}\)
\(11^{24}=(11^2)^{12}=121^{12}\)
Vì 125 > 121 nên \(5^{36}>11^{24}\)
\(b)21^{15}=(3\cdot7)^{15}=3^{15}\cdot7^{15}\)
\(27^5\cdot49^8=(3^3)^5\cdot(7^2)^8=3^{15}\cdot7^{16}\)
Vì 15 < 16 nên \(3^{15}\cdot7^{15}< 3^{15}\cdot7^{16}\)
hay : \(21^{15}< 27^5\cdot49^8\)
Bài 2 tự làm
Chúc bạn học tốt
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a) 12 x 31 + 225 : 52
= 12 x 3 + 225 : 25
= 36 + 9
= 45
b) 124 : 22 + 52 x 51 - 9
= 124 : 4 + 25 x 5 - 9
= 31 + 125 - 9
= 156 - 9
= 147
a) 12 x 31 + 225 : 52 b) 124 : 22 + 52 x 51 - 9
= 12 x 3 + 1,8 = 124 : 4 + 53 - 9
= 36 + 1,8 = 31 + 125 - 9
= 37,8 = 156 - 9
= 147
Hok tốt :3