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\(\left(\frac{-4}{13}+\frac{4}{13}+\frac{-12}{13}\right)\times\left(\frac{5}{17}+\frac{4}{17}\right)\)
\(=\)\(\frac{-12}{13}\times\left(\frac{5}{17}+\frac{4}{17}\right)\)
\(=\)\(\frac{-12}{13}\times\frac{9}{17}=\frac{-106}{221}\)
Lời giải:
a) $2^3.3^2=8.9=72$
b) $1\frac{4}{5}+\frac{6}{29}-\frac{4}{5}+\frac{23}{29}$
$=1+\frac{4}{5}+\frac{6}{29}-\frac{4}{5}+\frac{23}{29}$
$=1+(\frac{4}{5}-\frac{4}{5})+(\frac{6}{29}+\frac{23}{29})$
$=1+0+\frac{29}{29}=1+0+1=2$
c)
$\frac{-4}{13}.\frac{5}{17}+\frac{-12}{13}.\frac{4}{17}+\frac{4}{13}$
$=\frac{-4}{13}.\frac{5}{17}+\frac{-4}{13}.\frac{12}{17}+\frac{-4}{13}.(-1)$
$=\frac{-4}{13}(\frac{5}{17}+\frac{12}{17}-1)$
$=\frac{-4}{13}.(\frac{17}{17}-1)=\frac{-4}{13}.0=0$
a)|-10|:(-2):(-5)+(-3)2
=1+9
=10
b)1+(-2)+3+(-4)+5+(-6)+...+21+(-22)
=[1+(-2)]+[3+(-4)]+[5+(-6)]+...+[21+(-22]
=(-1)+(-1)+(-1)+...+(-1)
Mà từ 1 đến 22 có:(22-1):1+1:2=11(cặp)
Suy ra:1+(-2)+3+(-4)+5+(-6)+...+21+(-22)=(-11)
c)\(\frac{3}{4}.\frac{5}{9}+\frac{3}{4}.\frac{4}{9}\)
\(=\frac{3}{4}.\left(\frac{5}{9}+\frac{4}{9}\right)\)
\(=\frac{3}{4}\)
d)\(-\frac{4}{17}+\frac{5}{19}+-\frac{13}{17}+\frac{14}{19}+\frac{3}{115}\)
\(=\left[\left(-\frac{4}{17}\right)+\left(-\frac{13}{17}\right)\right]+\left(\frac{5}{19}+\frac{4}{19}\right)+\frac{3}{115}\)
\(=\left(-\frac{27}{17}\right)+1+\frac{3}{115}\)
\(=-\frac{1099}{1955}\)
e)\(\left(\frac{3}{4}+-\frac{7}{2}\right).\left(\frac{10}{11}+\frac{2}{22}\right)\)
\(=\left(\frac{3}{4}-\frac{14}{4}\right).\left(\frac{20}{22}+\frac{2}{22}\right)\)
\(=\left(-\frac{11}{4}\right).\left(\frac{22}{22}\right)\)
\(=-\frac{11}{4}\)
\(\frac{-4}{13}.\frac{5}{17}+\frac{-12}{13}.\frac{4}{17}+\frac{4}{13}\)
\(=\frac{4}{13}.\frac{-5}{17}+\frac{-12}{17}.\frac{4}{13}+\frac{4}{13}\)
\(=\frac{4}{13}.\left(\frac{-5}{17}+\frac{-12}{17}+1\right)\)
\(=\frac{4}{13}.0\)
\(=0\)