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\(\left(\frac{1313}{1414}+\frac{10}{160}\right)-\left(\frac{130}{140}-\frac{1515}{1616}\right)\)
\(=\left(\frac{13}{14}+\frac{1}{16}\right)-\left(\frac{13}{14}-\frac{15}{16}\right)\)
\(=\frac{13}{14}+\frac{1}{16}-\frac{13}{14}+\frac{15}{16}\)
\(=\left(\frac{13}{14}-\frac{13}{14}\right)+\left(\frac{1}{16}+\frac{15}{16}\right)\)
\(=0+1\)
\(=1\)
Có (\(\frac{1313}{1414}\)+\(\frac{10}{160}\)) - (\(\frac{130}{140}\)-\(\frac{1515}{1616}\))
=\(\frac{13}{14}\)+\(\frac{1}{16}\)-\(\frac{13}{14}\)+\(\frac{15}{16}\)
=(\(\frac{13}{14}-\frac{13}{14}\)) + (\(\frac{1}{16}+\frac{15}{16}\))
=0+1=1
a) \(\frac{5252}{7575}=\frac{52}{75};\frac{525252}{757575}=\frac{52}{75}\)
Vậy cả 3 phân số trên bằng nhau
b) \(\frac{1313}{1515}=\frac{13}{15};\frac{131313}{151515}=\frac{13}{15}\)
Vậy các phân số trên bằng nhau
\(\frac{52}{73}=\frac{52\cdot101}{73\cdot101}=\frac{5252}{7373}\)
\(\frac{52}{73}=\frac{52\cdot10101}{73\cdot10101}=\frac{525252}{737373}\)
\(1,\frac{201}{205}=1-\frac{4}{205};\frac{2013}{2015}=1-\frac{2}{2015}=1-\frac{4}{4030}.Vì:205< 4030nen:\frac{4}{205}>\frac{4}{4030}\Rightarrow\frac{201}{205}< \frac{2013}{2015}\)
\(b,\frac{133}{135}=1-\frac{2}{135};\frac{1313}{1515}=\frac{13}{15}=1-\frac{2}{15}.Mà:15< 135nen:\frac{2}{135}< \frac{2}{15}\Rightarrow\frac{133}{135}>\frac{1313}{1515}\)
\(2,\frac{103}{105}=1-\frac{2}{105};\frac{205}{208}=1-\frac{2}{208}.\text{Dễ thấy: 105.1,5 bé hơn 208 nên:}\frac{103}{105}< \frac{205}{208}\)
\(b,tươngtựa\)
\(c,\frac{1111}{1212}=\frac{11}{12}=1-\frac{1}{12};\frac{141414}{151515}=\frac{14}{15}=1-\frac{1}{15}.Mà:12< 15nen:\frac{1111}{1212}< \frac{141414}{151515}\)
Ta có : Q=\(\frac{1010+1011+1012}{1011+1012+1013}\)=\(\frac{1010}{1011+1012+1013}+\frac{1011}{1011+1012+1013}+\frac{1012}{1011+1012+1013}\)
Vì1010/1011>1010/1011+1012+1013
1011/1012>1011/1011+1012+1013
1012/1013>1012/1011+1012+1013
=>P>Q
\(\frac{52}{75}=\frac{52.101}{75.101}=\frac{5252}{7575};\frac{52}{75}=\frac{52.10101}{75.10101}=\frac{525252}{757575}\)
\(\frac{13}{15}=\frac{13.101}{15.101}=\frac{1313}{1515};\frac{13}{15}=\frac{13.10101}{15.10101}=\frac{131313}{151515}\)
\(\frac{ab}{cd}=\frac{101ab}{101cd}=\frac{abab}{cdcd};\frac{ab}{cd}=\frac{10101ab}{10101cd}=\frac{ababab}{cdcdcd}\)
ai k minh minh k lai
\(a,\frac{1995}{1996}.\frac{19961996}{19311931}.\frac{193119311931}{199519951995}\) \(c,\frac{1997.1996-1}{1995.1997+1996}\)
\(=\frac{1995}{1996}.\frac{1996}{1931}.\frac{1931}{1995}\) \(=\frac{1997.\left(1995+1\right)-1}{1995.1997+1996}\)
\(=\frac{1995.1996.1931}{1996.1931.1995}\) \(=\frac{1997.1995+1997-1}{1997.1995+1996}\)
\(=1\) \(=\frac{1997.1995+1996}{1995.1997+1996}\)
\(=1\)
Ý (a) giống ý (b)
Ý (c) giống ý (d)
Có : 1717/8585 = 17.101/85.101 = 17/85 = 1/5
1313/5151 = 13.101/51.101 = 13/51
Mà 13/51 > 13/65 = 1/5
=> 1717/8585 < 1313/5151
Tk mk nha
Có : 1717/8585 = 17.101/85.101 = 17/85 = 1/5
1313/5151 = 13.101/51.101 = 13/51
Mà 13/51 > 13/65 = 1/5
=> 1717/8585 < 1313/5151
\(\frac{1313}{1515}+\frac{-1011}{5055}\)
= \(\frac{13}{15}+\frac{-1}{5}\)
= \(\frac{13}{15}+\frac{-3}{15}\)
= \(\frac{10}{15}=\frac{2}{3}\)
\(\frac{1313}{1515}+\frac{-1011}{5055}\)
\(=\frac{13}{15}+\frac{-1}{5}\)
\(=\frac{2}{3}\)
Hok Tốt