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a)\(\frac{27}{5}\text{x}\frac{91}{12}\text{x}\frac{125}{9}\text{x}\frac{96}{13}=\frac{27}{9}\text{x}\frac{91}{13}\text{x}\frac{125}{5}\text{x}\frac{96}{12}=3\text{x}7\text{x}25\text{x}8\)
Đến đây tự tính nha !
b)\(\frac{2539}{35}\text{x}\frac{7}{90}+\frac{561}{35}\text{x}\frac{7}{90}=\frac{7}{90}\text{x}\left(\frac{2539}{35}+\frac{561}{35}\right)=\frac{7}{90}\text{x}\frac{3100}{35}=\frac{3100}{90}\text{x}\frac{7}{35}=\frac{310}{9}\text{x}\frac{1}{5}=\frac{62}{9}\)
\(\frac{23}{27}\)>\(\frac{22}{29}\)
Có 2 cách , cách 1 : Quy đồng mẫu số : \(\frac{667}{783}\)> \(\frac{594}{783}\) suy ra \(\frac{23}{27}\)>\(\frac{22}{29}\)
cách 2: Quy đồng tử số : \(\frac{506}{594}\)>\(\frac{506}{667}\)suy ra \(\frac{23}{27}\)>\(\frac{22}{29}\)
a) \(\frac{14}{15}+\frac{3}{11}+\frac{1}{15}+\frac{3}{11}+\frac{10}{22}\)
\(=\left(\frac{14}{15}+\frac{1}{15}\right)+\left(\frac{3}{11}+\frac{3}{11}\right)+\frac{10}{22}\)
\(=1+1+\frac{10}{22}\)
\(=2+\frac{10}{22}\)
\(=\frac{27}{11}\)
b) 9,25 + 9,25 x 8 + 9,25
= 9,25 x ( 8 + 1 + 1 )
= 9,25 x 10
= 92,5
\(y=\frac{1+5+11+19+29+41+55+71+89}{2+6+12+20+30+42+56+72+90}\)
\(y=\frac{1x2-1+2x3-1+3x4-1+4x5-1+5x6-1+6x7-1+7x8-1+8x9-1+9x10-1}{1x2+2x3+3x4+4x5+5x6+6x7+7x8+8x9+9x10}\)
\(y=\frac{\left(1x2+2x3+...+9x10\right)-\left(1+1+1+1+1+1+1+1+1\right)}{1x2+2x3+...+9x10}\)
\(y=\frac{1x2+2x3+...+9x10}{1x2+2x3+...+9x10}-\frac{9}{1x2+2x3+...+9x10}\)
\(y=1-\frac{9}{1x2+2x3+...+9x10}\)
NHẦM LÀM LẠI :
\(B=\left(5+7+1\right)+\left(\frac{19}{29}+\frac{10}{29}\right)+\left(\frac{43}{52}+\frac{9}{52}\right)+\frac{1}{7}=13+1+1+\frac{1}{7}=15\frac{1}{7}\)
B=\(\left(5+\frac{1}{7}+\frac{19}{29}\right)+\left(7+\frac{43}{52}+1+\frac{10}{29}\right)+\frac{9}{52}=\left(5+7+1\right)+\left(\frac{19}{29}+\frac{10}{29}\right)+\left(\frac{43}{52}+\frac{10}{52}+\frac{9}{52}\right)+\frac{1}{7}=13+1+1+\frac{1}{7}=15\frac{1}{7}\)
27 , 29 − 14 , 43 − 2 , 5 C á c h 1 : 27 , 29 − 14 , 4 ⏟ 3 − 2 , 5 = 12 , 86 − 2 , 5 = 10 , 36 C á c h 2 : 27 , 29 − 14 , 43 − 2 , 5 = 27 , 29 − 14 , 43 + 2 , 5 ⏟ = 27 , 29 − 16 , 93 = 10 , 36 29 , 82 − 11 , 6 + 10 , 3 C á c h 1 : 29 , 82 − 11 , 6 + 10 , 3 ⏟ = 29 , 82 − 21 , 9 = 7 , 92 C á c h 2 : 29 , 82 − 11 , 6 + 10 , 3 = 29 , 82 − 11 , 6 ⏟ − 10 , 3 = 18 , 22 − 10 , 3 = 7 , 92