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\(6\frac{5}{7}-\left(1\frac{3}{4}+2\frac{5}{7}\right)\)
\(=6\frac{5}{7}-1\frac{3}{4}-2\frac{5}{7}\)
\(=\left(6\frac{5}{7}-2\frac{5}{7}\right)-1\frac{3}{4}\)
\(=4-1\frac{3}{4}\)
\(=2\frac{1}{4}\)
\(6\frac{5}{7}-\left(1\frac{3}{4}+2\frac{5}{7}\right)\)
\(=6\frac{5}{7}-1\frac{3}{4}-2\frac{5}{7}\)
\(=\left(6\frac{5}{7}-2\frac{5}{7}\right)-1\frac{3}{4}\)
\(=4-\frac{7}{4}\)
\(=\frac{16}{4}-\frac{7}{4}\)
\(=\frac{9}{4}\)
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= \(6\frac{5}{7}-1\frac{3}{4}-2\frac{5}{7}=6\frac{5}{7}-2\frac{5}{7}\)\(-1\frac{3}{4}\)= \(4-1\frac{3}{4}\)=\(\frac{9}{4}\)
47/7 - (7/4 + 19/7) =47/7 -125/28 =gomen =tao xin lỗi chịu rùi = <3
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6^2.4.3+3+3.5^3
=36.4.3+3+3.125
=36.4.3+3+3.1+3.125
=3.(36.4+1+125)
=3.(144+1+125)
=3.280
=840
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\(\frac{5}{16}+\frac{5}{7}+0,4+\frac{1}{6}-\frac{4}{35}\)
= \(\frac{5}{16}+\frac{25}{35}+\frac{2}{5}+\frac{1}{6}-\frac{4}{35}\)
= \(\frac{5}{16}+\frac{2}{5}+\frac{1}{6}+\frac{25}{35}-\frac{4}{35}\)
= \(\frac{5}{16}+\frac{2}{5}+\frac{1}{6}+\frac{2}{3}\)
= \(\frac{5}{16}+\frac{2}{5}+\frac{5}{6}\)
= \(\frac{5}{16}+\frac{37}{30}\)
= \(\frac{371}{240}\)
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\(a)\frac{4^{17}.3^4.9^6}{6^{13}}=\frac{2^{34}.3^4.3^{12}}{2^{13}.3^{13}}=\frac{2^{21}.3^{16}}{3^{13}}=2^{21}.3^3\)
\(b)\frac{2^{16}+2^8}{2^{13}+2^5}=\frac{2^8\left(2^8+1\right)}{2^5\left(2^8+1\right)}=\frac{2^3\left(2^8+1\right)}{2^8+1}=2^3=8\)
\(a,\frac{4^{17}\times3^4\times9^6}{6^{13}}\)
\(=\frac{2^{34}\times3^4\times3^{12}}{2^{13}\times3^{13}}\)
\(=\frac{2^{34}\times3^{16}}{2^{13}\times3^{13}}\)
\(=2^{21}\times3^3\)
\(b,\frac{2^{16}+2^8}{2^{13}+2^5}\)
\(=\frac{2^8\left(2^8+2^0\right)}{2^5\left(2^8+2^0\right)}\)
\(=\frac{2^8}{2^5}\)
\(=8\)
~Study well~
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\(3\cdot15\cdot4+12\cdot19+6\cdot66\cdot2\)
\(=\left(3\cdot4\right)\cdot15+12\cdot19+\left(6\cdot2\right)\cdot66\)
\(=12\cdot15+12\cdot19+12\cdot66\)
\(=12\cdot\left(15+19+66\right)\)
\(=12\cdot100\)
\(=1200\)
\(3.15.4+1.19+6.66.2\)
= ( 3. 4 ) . 15 + 12 .19 - (6.2) . 66
= 12 . 15 + 12 . 19 + 12 . 66
= 12.(15 + 19 + 66)
= 2 . 100
= 1200
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\(\frac{16.17-5}{16.16+11}\)
\(=\frac{16.16+16-5}{16.16+11}\)
\(=\frac{16.16+11}{16.16+11}\)
\(=1\)
\(\frac{16\cdot17-5}{16\cdot16+11}\)
\(=\frac{16\cdot17-5}{16\cdot17-16-11}\)
\(=\frac{16\cdot17-5}{16\cdot17-5}\)
\(=1\)
mk ko copy của Trần Thùy Dung nhé
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45 × 16 - 17 / 28 + 45 × 15
= 45 × (15 + 1) - 17 / 28 + 45 × 15
= 45 × 15 + (45 - 17) / 28 + 45 × 15
= 45 × 15 + 28 / 28 + 45 × 15
= 1
\(\frac{45\times16-17}{28+45\times15}\)
\(=\frac{45\left(15+1\right)-17}{28+45\times15}\)
\(=\frac{45\times15+\left(45-17\right)}{28+45\times15}\)
\(=\frac{45\times15+28}{28+45\times15}\)
\(=1\)
Khoảng cách giữa các số: 2
Dãy trên có số số hạng là: (22-2):2+1= 11 (số hạng)
Tổng dãy trên là: (22+2)x11:2= 132
Đáp số: 132
2 + 4+ 6 +...+22`
Khoảng cách : `2`
Số hạng :
`(22-2)/2 + 1 = 11(số-hạng)`
Tổng :
`(22+2)xx11:2=132 `
Vậy,.....