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NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
20 tháng 2 2024
a; - \(\dfrac{10}{13}\) + \(\dfrac{5}{17}\) - \(\dfrac{3}{13}\) + \(\dfrac{12}{17}\) - \(\dfrac{11}{20}\)
= - (\(\dfrac{10}{13}\) + \(\dfrac{3}{13}\)) + (\(\dfrac{5}{17}\) + \(\dfrac{12}{17}\)) - \(\dfrac{11}{20}\)
= - 1 + 1 - \(\dfrac{11}{20}\)
= 0 - \(\dfrac{11}{20}\)
= - \(\dfrac{11}{20}\)
b; \(\dfrac{3}{4}\) + \(\dfrac{-5}{6}\) - \(\dfrac{11}{-12}\)
= \(\dfrac{9}{12}\) - \(\dfrac{10}{12}\) + \(\dfrac{11}{12}\)
= \(\dfrac{10}{12}\)
= \(\dfrac{5}{6}\)
c; [13.\(\dfrac{4}{9}\) + 2.\(\dfrac{1}{9}\)] - 3.\(\dfrac{4}{9}\)
= [\(\dfrac{52}{9}\) + \(\dfrac{2}{9}\)] - \(\dfrac{4}{3}\)
= \(\dfrac{54}{9}\) - \(\dfrac{4}{3}\)
= \(\dfrac{14}{3}\)
4 tháng 3 2019
a) \(\frac{3}{5}+\frac{7}{10}+\frac{-13}{20}=\frac{12}{20}+\frac{14}{20}+\frac{-13}{20}=\frac{12+14+\left(-13\right)}{20}=\frac{13}{20}\)
b) \(\frac{1}{2}+\frac{-1}{5}+\frac{1}{4}+\frac{1}{6}=\frac{60}{120}+\frac{-24}{120}+\frac{30}{120}+\frac{20}{120}\)\(=\frac{60+\left(-24\right)+30+20}{120}=\frac{86}{120}=\frac{43}{60}\)
c) \(\frac{2}{3}+\frac{-3}{4}+\frac{5}{8}+\frac{-1}{2}\)\(=\frac{16}{24}+\frac{-18}{24}+\frac{15}{24}+\frac{-12}{24}\)\(=\frac{16+\left(-18\right)+15+\left(-12\right)}{24}=\frac{1}{24}\)
4 tháng 3 2019
\(a)\frac{3}{5}+\frac{7}{10}+\frac{-13}{20}\)
\(\frac{3}{5}+\frac{7}{10}+\frac{-13}{20}=\frac{3.4}{5.4}+\frac{7.2}{10.2}+\frac{-12}{20}\)
\(=\frac{12}{20}+\frac{14}{20}+\frac{-13}{20}=\frac{12+14+\left(-13\right)}{20}\)
\(=\frac{13}{20}\)
\(b)\frac{1}{2}+\frac{-1}{5}+\frac{1}{4}+\frac{1}{6}\)
\(\frac{1}{2}+\frac{-1}{5}+\frac{1}{4}+\frac{1}{6}=\frac{1.30}{2.30}+\frac{-1.12}{5.12}+\frac{1.15}{4.15}+\frac{1.10}{6.10}\)
\(=\frac{30}{60}+\frac{-12}{60}+\frac{15}{60}+\frac{10}{60}=\frac{30+\left(-12\right)+15+10}{60}\)
\(=\frac{43}{60}\)
\(c)\frac{2}{3}+\frac{-3}{4}+\frac{5}{8}+\frac{-1}{2}\)
\(\frac{2}{3}+\frac{-3}{4}+\frac{5}{8}+\frac{-1}{2}=\frac{2.8}{3.8}+\frac{-3.6}{4.6}+\frac{5.3}{8.3}+\frac{-1.12}{2.12}\)
\(=\frac{16}{24}+\frac{-18}{24}+\frac{15}{24}+\frac{-12}{24}\)\(=\frac{16+\left(-18\right)+15+\left(-12\right)}{24}\)
\(=\frac{1}{24}\)
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#0006
B
22 tháng 3 2019
\(A=\left(\frac{21}{5}-\frac{3}{5}\right):\frac{16}{8}:\frac{9}{10}\)
\(A=\frac{18}{5}:\frac{16}{8}:\frac{9}{10}\)
\(A=\frac{18}{5}\times\frac{8}{16}\times\frac{10}{9}\)
\(A=\frac{9}{5}\times\frac{8}{8}\times\frac{10}{9}\)
\(A=\frac{72}{40}\times\frac{10}{9}\)
\(A=\frac{8}{4}\times\frac{1}{1}\)
\(A=\frac{8}{9}\)
B
22 tháng 3 2019
\(B=\left(1\frac{1}{20}+\frac{36}{100}\right):\frac{84}{25}:\left(2+\frac{14}{16}\right)\)
\(B=\left(\frac{21}{20}+\frac{36}{100}\right):\frac{84}{25}:\left(\frac{32}{16}+\frac{14}{16}\right)\)
\(B=\left(\frac{105}{100}+\frac{36}{100}\right):\frac{84}{25}:\frac{46}{16}\)
\(B=\frac{141}{100}:\frac{84}{25}:\frac{46}{16}\)
\(B=\frac{141}{100}\times\frac{25}{84}\times\frac{16}{46}\)
\(B=\frac{141}{4}\times\frac{1}{84}\times\frac{16}{46}\)
\(B=\frac{141}{336}\times\frac{16}{46}\)
\(B=\frac{141}{21}\times\frac{1}{46}\)
\(B=\frac{141}{966}\)
KN
21 tháng 1 2019
a) \(-2011-\left(200-2011\right)\)
\(=-2011-200+2011\)
\(=\left(-2011+2011\right)-200\)
\(=0-200\)
\(=-200\)
b) \(\left(-2\right)^2-\left(-2000\right)^0+\left(-1\right)^{2018}-\left|-20\right|\)
\(=4-1+1-20\)
\(=4-20\)
\(=-16\)
21 tháng 1 2019
Bài 1 :
\(a)-2011-(200-2011)\)
\(=-2011-(200+2011)\)
\(=(-2011+2011)-200\)
\(=0-200=-200\)
\(b)(-2)^2-(-2000)^0+(-1)^{2018}-\left|-20\right|\)
\(=4-1+1-20\)
\(=4-20=-16\)
\(c)23\cdot18-23\cdot26+(-23)\cdot2\)
\(=23\cdot(18-26)+-(23\cdot2)\)
\(=23\cdot(-8)+(-46)\)
\(=-230\)
Bài 2 : Tìm số nguyên x biết :
\(a)3x-(-5)=20\)
\(\Rightarrow3x+5=20\)
\(\Rightarrow3x=20-5\)
\(\Rightarrow3x=15\Rightarrow x=5\)
\(b)3(x+2)=-4+(-2)^3\)
\(\Rightarrow3(x+2)=-4+(-8)\)
\(\Rightarrow3(x+2)=-12\)
\(\Rightarrow x+2=-12\div3\)
\(\Rightarrow x+2=-4\)
Tự tìm x câu b, và câu c,
Bài 3 tự làm