Question

[Kênh Kiến Thức]

Tính (a + b + c)³

Answer 1

[♡#•Hắc•Thiên•Thiên•#♡(๖ۣۜTεαм๖ۣTαм๖...]

=a^3+3a^2b+3b^2a+b^3+3b^2c+3c^2b+c^3

Answer 2

[đặng quốc khánh]

$\mathrm{(a}+b+c{)}^3=\left(\right(a+b)+c{)}^3=(a+b{)}^3+c^3+3(a+b)c(a+b+c)$
$=a^3+b^3+3ab(a+b)+c^3+3(a+b)c(a+b+c)$
$=a^3+b^3+c^3+3(a+b)(ab+c(a+b+c\left)\right)$
$=a^3+b^3+c^3+3(a+b)(ab+ac+bc+c^2)$
$=a^3+b^3+c^3+3(a+b)(a+c)(b+c)$