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Câu 1:
a) 25-(30+x) = x-(27-8)
25-30-x = x-19
-5-x = x-19
(-5)+19 = x+x
14 = 2x
x = 7
Vậy x = 7
b) (x-12)-15 = (20-7)-(18+x)
x-12-15 = 13-18-x
x-(12+15)= -5-x
x-27 = -5-x
x+x = -5+27
2x = 22
x = 11
Câu 2:
a) 4573+46-4573+35-16-5
= (4573-4573)+(46-16)+(35-5)
= 0+30+30
= 60
b) 32+34+36+38-10-12-14-16-18
= (32-12)+(34-14)+(36-16)+(38-18)-10
= 10+10+10+10-10
= 30
1, a) 25 - (30 + x) = x - (27 - 8)
25 - 30 - x = x - 27 + 8
-x - x = -27 + 8 - 25 + 30
-2x = -14
x = -14 : (-2)
x = 7
b) (x - 12) - 15 = (20 - 7) - (18 + x)
x - 12 - 15 = 20 - 7 - 18 - x
x + x = 20 - 7 - 18 + 12 + 15
2x = 22
x = 22 : 2
x = 11
2, a) 4573 + 46 - 4573 + 35 - 16 - 5
= (4573 - 4573) + (46 - 16) + (35 - 5)
= 0 + 30 + 30
= 60
b) 32 + 34 + 36 + 38 - 10 - 12 - 14 - 16 - 18
= (32 - 10) + (34 - 12) + (36 - 14) + (38 - 16) - 18
= 22 + 22 + 22 + 22 - 18
= 22 x 4 - 18
= 88 - 18
= 70
\(\frac{1}{2}+\frac{5}{6}+\frac{11}{12}+\frac{19}{20}+...+\frac{89}{90}\)
\(=1-\frac{1}{2}+1-\frac{1}{6}+1-\frac{1}{12}+1-\frac{1}{20}+...+1-\frac{1}{90}\)
\(=9-\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{90}\right)\)
\(=9-\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{9.10}\right)\)
\(=9-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{9}-\frac{1}{10}\right)\)
\(=9-\left(1-\frac{1}{10}\right)\)
\(=9-\frac{9}{10}=\frac{81}{10}\)
\(B=\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99}+\frac{1}{143}\)
\(=\frac{1}{3\cdot5}+\frac{1}{5\cdot7}+\frac{1}{7\cdot9}+\frac{1}{9\cdot11}+\frac{1}{11\cdot13}\)
\(=\frac{1}{2}\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+\frac{1}{11}-\frac{1}{13}\right)\)
\(=\frac{1}{2}\left(\frac{1}{3}-\frac{1}{13}\right)=\frac{5}{39}\)
a) =5
b) =10
c) =19
A)=5
B)=10
C )=19