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\(=\left(\frac{84}{13}+\frac{35}{13}\right)^2-2\cdot\frac{84}{13}\cdot\frac{35}{13}\)
\(=7^2-\frac{5880}{169}\)
\(=49-\frac{5880}{169}\)
\(=\frac{8281}{169}-\frac{5880}{169}=\frac{2401}{169}\)
Ta có : A = ( 84/13 )2 + ( 35/13 )2 .
⇒ A = 842 / 132 + 352 / 132 .
⇒ A = ( 842 + 352 ) / 132 .
⇒ A = ( 7056 + 1225 ) / 169 .
⇒ A = 8281 / 169 .
⇒ A = 49 .
Vậy A = 49 .
Bài 1:
A,
(100+121+144)÷(169+196)
=365:365=1
B
,1.2.3...7.8.(9-1-8)
=1.2.3...7.8.0=0
C,
3^2.2^4.2^32/11.2^13.2^22-2^26
=3^2.2^36/11.2^35-2^36
=3^2.2^36/2^35-(11-2)
=9.2/9=2
D,
=1152-374-1152+(-65)+374
=(1152-1152)+(-374+374)+(-65)
=0+0+(-65)=-65
E,
=13-(12-11-10+9)+(8-7-6+5)-(4-3-2+1)
=13-0+0-0=13
Bài 2:
A,(19x+50)÷14=25-16
(19x+50)÷14=9
19x+50=126
19x=76
x=4
B,
31x+(1+2+3+...+30)=1240
31x+465=1240
31x=775
×=25
a ) 13 . 35 + 13 . 67 - 26
= 13 . ( 35 + 67 ) - 26
= 13 . 102 - 26
= 1326 - 26
= 1300
b) ( 25 .12 + 4 . 25 ) : 27
= [ 25 . ( 12 + 4 ) ] : 27
= 25 . 16 : 27
= 25 . 24 : 27
= 29 : 27
= 22 = 4
c) 23 . [ 50 - ( 17 - 54 : 33 )] + 16
= 8 . [ 50 - ( 17 - 54 : 27 )] + 16
= 8 . [ 50 - ( 17 - 2 )] + 16
= 8 . [ 50 - 15 ] + 16
= 8 . 35 + 16
= 280 + 16
= 296
K MK NHA
A = \(\dfrac{21^2.14.125}{35^5.6}\)
= \(\dfrac{\left(3.7\right)^2.\left(2.7\right).5^3}{\left(5.7\right)^5.\left(2.3\right)}\)
= \(\dfrac{3^2.7^2.2.7.5^3}{5^5.7^5.2.3}\)
= \(\dfrac{3^2.7^3.2.5^3}{5^5.7^5.2.3}\)
= \(\dfrac{3}{5^2.7^2}\)
= \(\dfrac{3}{35^2}\)
@Pham Thi Thu Trang
B = \(\dfrac{2^{10}.13+2^{10}.65}{2^8.104}\)
= \(\dfrac{2^{10}\left(13+65\right)}{2^8.104}\)
= \(\dfrac{2.78}{104}\)
= \(\dfrac{3}{2}\)
@Pham Thi Thu Trang
\(A=2+2^3+2^5+2^7+2^9+...+2^{2009}\)
\(\Leftrightarrow\)\(4A=2^3+2^5+2^7+2^9+2^{11}+...+2^{2011}\)
\(\Leftrightarrow\)\(4A-A=\left(2^3+2^5+2^7+...+2^{2011}\right)-\left(2+2^3+2^5+...+2^{2009}\right)\)
\(\Leftrightarrow\)\(3A=2^{2011}-2\)
\(\Leftrightarrow\)\(A=\frac{2^{2011}-2}{3}\)
Ta có :
\(A=2+2^3+2^5+...+2^{2009}\)
\(4A=2^3+2^5+2^7+...+2^{2011}\)
\(4A-A=\left(2^3+2^5+2^7+...+2^{2011}\right)-\left(2+2^3+2^5+...+2^{2009}\right)\)
\(3A=2^{2011}-2\)
\(A=\frac{2^{2011}-2}{3}\)
Vậy \(A=\frac{2^{2011}-2}{3}\)
Câu b) dễ hơn nữa làm tương tư câu a) nhưng B nhân cho 2
Câu c) thì C nhân cho 5
Câu d) thì D nhân cho 169
813.15-812.13=812.(8.15-13)=812.107
2512-25.2511=2512-2512=0
49-[35-(6-1)2 ]=49-(35-52)=49-(35-25)=49-10=39
=[(813.812).(15-13)] =(2512.2511)-25
=8.2 =25-25
=16 =1
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