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Có gạch ngang của phân số nhưng hơi mờ,các bạn chịu khó nhìn kĩ nhé:)
A=5.415.99-4.320.89=5.230.318-22.227.320
=229.318(2.5-32)=229.318
B=5.29.619-7.229.276=5.29.219.319-7.229.318
=228.318(5.3-7.2)=228.318
=>A:B=229.318:228:318=2
b ) \(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{99.100}\)
= 1 - 1/2 + 1/2 - 1/3 + ... + 1/99 - 1/100
= 1 - 1/100
= 99/100
c ) Đặt A = \(\frac{1}{2^2}+\frac{1}{3^2}+...+\frac{1}{100^2}\)
=> A < \(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{99.100}\)
=> A < 1 - 1/2 + 1/2 - 1/3 + ... + 1/99 - 1/100= 1 - 1/100 = 99/100 < 1
Vậy \(\frac{1}{2^2}+\frac{1}{3^2}+...+\frac{1}{100^2}\)< 1
b, \(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{98.99}+\)\(\frac{1}{99.100}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{98}-\frac{1}{99}+\frac{1}{99}-\frac{1}{100}\)
\(=1-\frac{1}{100}\)
\(=\frac{99}{100}\)
c,Ta thấy
\(\frac{1}{2^2}< \frac{1}{1.2}\)
\(\frac{1}{3^2}< \frac{1}{2.3}\)
\(\frac{1}{4^2}< \frac{1}{3.4}\)
\(.....\)
\(\frac{1}{100^2}< \frac{1}{99.100}\)
\(\Rightarrow\frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{4^2}+...+\frac{1}{100^2}\)\(< \frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{99.100}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{99}-\frac{1}{100}\)
\(=1-\frac{1}{100}< 1\)
\(\Rightarrow\frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{4^2}+...+\frac{1}{100^2}< 1\left(đpcm\right)\)
TA CÓ:6A= 1.6+6.6+6.6^2+..........+6^1000.6
6A= 6+6^2+6^3+ +6^1000+6^1001
A=1+6+6^2+........+6^1000
6A-A=6^1001-1
vì 6^1001 chia hết cho 6:;1 chia 6 dư 5 suy ra A chia 6 dư 5
\(\frac{A}{B}=\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)
\(=\frac{5.\left(2^2\right)^{15}.\left(3^2\right)^9-2^2.3^{20}.\left(2^3\right)^9}{5.2^9.2^{19}.3^{19}-7.2^{29}.\left(3^3\right)^6}\)
\(=\frac{5.2^{30}.3^{18}-2^{29}.3^{20}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}=\frac{2^{29}.3^{18}.\left(5.2-3^2\right)}{2^{28}.3^{18}.\left(5.3-7.2\right)}\)
\(=\frac{2^{29}.3^{18}.1}{2^{28}.3^{18}.1}=2\)
A = 5 x 415 x 99 - 4 x 320 x 89 = 5 x 230 x 318- 22 x 227 x 320
=229 x 318 x(2x5-32)=229 x 318
B = 5 x 29 x 619 - 7 x 229 x 276=5 x 29 x 219 x 319 - 7 x 229 x 318
=228 x 318 x (5 x 3-7 x 2)= 228.318
=>A:B= 229.318:228:318=2
Gọi tổng trên là A
Ta có:
A=2100--299-298-...-22-2-1
=>2A=2101-2100-299-...-23-22-2
=>2A-A=A=(2101-2100-299-...-23-22-2)-(2100--299-298-...-22-2-1)
=>A=2101-1
Thank mình đi
Đặt B = 2^100 - 2^99 - 2^98 - ... - 2^2 - 2 - 1
2B = 2^101 - 2^100 - 2^99 - ... - 2^3 - 2^2 - 2
B = 2B - B = ( 2^101 - 2^100 - 2^99 - ... - 2^3 - 2^2 - 2 ) - ( 2^100 - 2^99 - 2^98 - ... - 2^2 - 2 - 1 )
B = 2^101 - 2^100 - 2^99 - .... - 2^3 - 2^2 - 2 - 2^100 + 2^99 + 2^98 + ... + 2^2 + 2 + 1
B = 2^101 - 2^100 - 2^100 + 1
B = 2^101 - 2 . 2^100 + 1
B = 2^101 - 2^101 + 1
B = 0 + 1
B = 1
a, (3x +)^3 =4^3 b, (2x +1 )^3 =5^3
<=>3x +1 =4 <=>2x +1 =5
<=>x=1 <=>x=2
\(A=6^3+6^6+6^9+...+6^{27}\)
\(6^3.A=6^6+6^9+6^{12}+...+6^{30}\)
\(216A-A=215A=6^{30}-6^3\)
\(\Rightarrow A=\frac{6^{30}-6^3}{215}\)
63+66+69+...+627
Đặt A=63+66+69+...+627
6A=63.(63+66+69+...+627)
6A=66+69+612+...+630
6A-A=630-63
5A=630-63
A=(630-63)/5