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\(\frac{5}{17}.\frac{16}{33}+\frac{5}{33}.\frac{20}{17}-\frac{2}{17}.\frac{5}{33}\)
\(=\frac{5}{17}.\frac{16}{33}+\frac{5}{17}.\frac{20}{33}-\frac{5}{17}.\frac{2}{33}\)
\(=\frac{5}{17}.\left(\frac{16}{33}+\frac{20}{33}-\frac{2}{33}\right)\)
\(=\frac{5}{17}.\frac{34}{33}\)
\(=\frac{10}{33}\)
Chúc bạn học tốt !!!
a) \(\left(3^{35}+3^{34}-3^{33}\right):3^{32}\)
\(=\frac{3^{35}}{3^{32}}+\frac{3^{34}}{3^{32}}-\frac{3^{33}}{3^{32}}\)
\(=3^3+3^2-3\)
\(=27+9-3\)
\(=33\)
b) \(5^3.37+5^3.64-5^7:5^4\)
\(=5^3.37+5^3.64-5^3\)
\(=5^3\left(37+64-1\right)\)
\(=5^3.100\)
\(=125.100\)
\(=12500\)
\(\left(3^{35}+3^{34}-3^{33}\right)\div3^{32}=3^{33}\left(3^2+3-1\right)\div3^{32}\)
\(=3^{33}.11\div3^{32}=11\left(3^{33-32}\right)=11.3=33\)
Ta có: \(2\frac{1}{3}+\frac{11}{5}:33-\frac{1}{50}.\left(-5\right)^2\)
\(=\frac{7}{3}+\frac{11}{5}.\frac{1}{33}-\frac{1}{50}.25\)
\(=\frac{7}{3}+\frac{11}{165}-\frac{25}{50}\)
\(=\frac{7}{3}+\frac{1}{15}-\frac{1}{2}\)
\(=\frac{70}{30}+\frac{2}{30}-\frac{15}{30}\)
\(=\frac{56}{30}=\frac{28}{15}\)
(-1/4+7/33-5/3)-(-5/12+6/11-5/42)
=-1/4+7/33-5/3-5/12-6/11+5/42
=-1/4-5/12+7/33-6/11-5/3+5/42
=-8/12+(-3/11)-25/12
=-8/12-25/12+(-3/11)
=-33/12+-3/11
=-11/4+-3/11
=-133/44
Mk làm sai rồi !
\(\left(\frac{-1}{4}+\frac{7}{33}-\frac{5}{3}\right)-\left(\frac{-5}{12}+\frac{6}{11}-\frac{5}{42}\right)\)
\(=\frac{-1}{4}+\frac{7}{33}-\frac{5}{3}+\frac{5}{12}-\frac{6}{11}+\frac{5}{42}\)
\(=\left(\frac{5}{12}-\frac{1}{4}\right)-\left(\frac{5}{3}-\frac{5}{42}\right)-\left(\frac{6}{11}-\frac{7}{33}\right)\)
\(=\frac{1}{6}-\frac{65}{42}-\frac{1}{3}\)
\(=\frac{-29}{21}-\frac{1}{3}\)
\(=\frac{-12}{7}\)
a) 22 + 3 . 23 = 22 + 3 . 8 = 22 + 24 = 46
b) 41 . 67 + 33 . 41 = 41 . ( 67 + 33 ) = 41 . 100 = 4100
c) 322 . 5 - [ 622 : 4 + 2 . ( 11 - 8) ] = 322 . 5 - [ 622 : 4 + 2 . 3 ] = 322 . 5 - [ 155,5 + 6 ] = 322 . 5 - 161,5 = 1610 + 161,5 = 1448,5
a ) \(-\frac{2}{5}.\frac{5}{-9}=\frac{-2.1}{1.-9}=\frac{-2}{-9}=\frac{2}{9}\)
b ) \(-\frac{7}{31}.0=0\) ( vì số nào nhân không đều bằng 0 )
c ) \(\frac{-28}{33}:\frac{-3}{33}=\frac{-28}{33}.\frac{33}{-3}=\frac{-28.1}{1.-3}=\frac{-28}{-3}=\frac{28}{3}\)
a) 18.17−3.6.7
= 18.17 - 18 . 7
= 18 ( 17 - 7 )
= 18 . 10 = 180
b) 54−6.(17+9)
= 54 - 102 - 54
= - 102
c) 33.(17−5)−17.(33−5)
= 33. 17 - 33. 5 - 17 .33 + 17 . 5
= 17 . 5 - 33 . 5
= 5 ( 17 - 33 )
= 5. (-16)
= - 80
a) 18.17 - 3.6.7
= 18.17 - 18.7
= 18.(17 - 7 )
= 18 . 10
= 180
b) 54 - 6.(17 + 9)
= 6.9 - 6.17 + 6.9
= (6.9 - 6.9) - 6.17
= 0 - 6.17
= 0 - 102
= -102
c) 33.(17 - 5) - 17.(33 - 5)
= 33.17 - 33.5 - 17 . 33 - 17.5
= 33.(17 - 17) - 5.(33 - 17 )
= 33. 0 - 5.16
= 0 - 80
= -80
A=33. \(\left(1-\frac{2}{3}\right)\left(1-\frac{2}{5}\right)...\left(1-\frac{2}{99}\right)\)
A=33.\(\frac{1}{3}.\frac{3}{5}....\frac{97}{99}\)
A=33.\(\frac{1}{99}\)
A=\(\frac{33}{99}=\frac{1}{3}\)
