K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Các câu hỏi dưới đây có thể giống với câu hỏi trên
A
2
4 tháng 8 2018
\(a,\left(0,125\right)^3.8^3\)
\(=\left(0,125.8\right)^3\)
\(=1^3\)
\(=1\)
\(b,\left(-39\right)^4:13^4\)
\(=\left(-39:13\right)^4\)
\(=-3^4\)
\(=81\)
10 tháng 11 2018
a) \(\dfrac{-3}{5}.51\dfrac{11}{13}+\dfrac{3}{5}.21\dfrac{11}{13}\)
\(=\dfrac{-3}{5}.\left(51\dfrac{11}{13}-21\dfrac{11}{13}\right)\)
\(=\dfrac{-3}{5}.30\)
\(=-18.\)
b) \(\left|\dfrac{-3}{4}\right|.\left|-\dfrac{2}{3}\right|=\dfrac{3}{4}.\dfrac{2}{3}=\dfrac{1}{2}\).
c) \(\dfrac{-3}{5}+5\dfrac{1}{13}-\dfrac{2}{3}+1\dfrac{3}{5}-\dfrac{11}{33}\)
\(=\left(1\dfrac{3}{5}-\dfrac{3}{5}\right)+5\dfrac{1}{13}-\left(\dfrac{2}{3}+\dfrac{11}{33}\right)\)
\(=1+\dfrac{66}{13}-1\)
\(=\dfrac{66}{13}.\)
d) \(\dfrac{3}{4}.\sqrt{16}-10.\sqrt{0,81}\)
\(=\dfrac{3}{4}.4-10.\dfrac{9}{10}\)
\(=3.9\)
\(=27.\)
e) \(\left(\dfrac{3}{4}\right)^3:\left(\dfrac{-3}{8}\right)^3=\dfrac{3^3}{4^3}.\dfrac{\left(-8\right)^3}{3^3}=\left(\dfrac{-8}{4}\right)^3=\left(-2\right)^3=-8\)
f) \(\dfrac{6^4.15^3}{8.9^3.10^3}=\dfrac{2^4.3^4.3^3.5^3}{2^3.3^6.2^3.5^3}=\dfrac{2.3^7}{2^3.3^6}=\dfrac{3}{2^2}=\dfrac{3}{4}.\)
TK
30 tháng 9 2020
a, \(\frac{3}{5}+\frac{-1}{3}\)
=\(\frac{9}{15}+\frac{-5}{15}\)
=\(\frac{4}{15}\)
b,\(\frac{-2}{13}+\frac{-11}{26}\)
=\(\frac{-4}{26}+\frac{-11}{26}\)
=\(\frac{-15}{26}\)
c, \(-2+\frac{-5}{8}\)
=\(\frac{-16}{8}+\frac{-5}{8}\)
=\(\frac{-21}{8}\)
d,\(\frac{13}{30}-\frac{1}{5}\)
=\(\frac{13}{30}-\frac{6}{30}\)
=\(\frac{7}{30}\)
e,\(\frac{2}{21}-\frac{-1}{28}\)
=\(\frac{56}{588}-\frac{-21}{588}\)
=\(\frac{77}{588}=\frac{11}{84}\)
bài dễ mà <3
b bạn gõ lại đề giúp mình nhé
V
21 tháng 7 2018
*Trả lời :
a) \(-\dfrac{3}{4}.5\dfrac{3}{13}-0,75.\dfrac{36}{13}\)
= \(-\dfrac{3}{4}.\dfrac{68}{13}-\dfrac{3}{4}.\dfrac{36}{13}\)
=\(\dfrac{3}{4}.\dfrac{-68}{13}-\dfrac{3}{4}.\dfrac{36}{13}\)
=\(\dfrac{3}{4}.\cdot\left(\dfrac{-68}{13}-\dfrac{36}{13}\right)\)
=\(\dfrac{3}{4}.\left(-8\right)\)
= \(-6\)
b)\(4\dfrac{5}{9}:\left(-\dfrac{5}{7}\right)+\dfrac{49}{9}:\left(-\dfrac{5}{7}\right)\)
=\(\dfrac{41}{9}-\left(-\dfrac{5}{7}\right)+\dfrac{49}{9}:\left(-\dfrac{5}{7}\right)\)
=\(\left(\dfrac{41}{9}+\dfrac{49}{9}\right):\left(-\dfrac{5}{7}\right)\)
=\(\dfrac{90}{9}:\left(-\dfrac{5}{7}\right)\)
=\(10:\left(-\dfrac{5}{7}\right)\)
=\(-14\)
c)\(\left(-\dfrac{3}{5}+\dfrac{4}{9}\right):\dfrac{7}{11}+\left(-\dfrac{2}{5}+\dfrac{5}{9}\right):\dfrac{7}{11}\)
=\(\left(-\dfrac{3}{5}\right)+\dfrac{4}{9}:\dfrac{7}{11}+\left(-\dfrac{2}{5}\right)+\dfrac{5}{9}:\dfrac{7}{11}\)(áp dụng tính chất phá ngoặc )
=\(\left\{\left[-\dfrac{3}{5}+\left(-\dfrac{2}{5}\right)\right]+\left(\dfrac{4}{9}+\dfrac{5}{9}\right)\right\}:\dfrac{7}{11}\)
=\(\left(-\dfrac{5}{5}+\dfrac{9}{9}\right):\dfrac{7}{11}\)
=\(\left(-1+1\right):\dfrac{7}{11}\)
\(=0:\dfrac{7}{11}\)
=0.
d)\(\dfrac{6}{7}:\left(\dfrac{3}{26}-\dfrac{3}{13}\right)+\dfrac{6}{7}:\left(\dfrac{1}{10}-\dfrac{8}{5}\right)\)
=\(\dfrac{6}{7}:\left[\dfrac{3}{26}+\left(-\dfrac{6}{26}\right)\right]+\dfrac{6}{7}:\left[\dfrac{1}{10}+\left(-\dfrac{16}{10}\right)\right]\)
=\(\dfrac{6}{7}:\left(-\dfrac{3}{26}\right)+\dfrac{6}{7}:\left(-\dfrac{3}{2}\right)\)
=\(\dfrac{6}{7}:\left[\left(-\dfrac{3}{26}\right)+\left(-\dfrac{39}{26}\right)\right]\)
=\(\dfrac{6}{7}:\left(-\dfrac{21}{13}\right)\)
=\(-\dfrac{26}{49}\)
27 tháng 11 2018
\(-\frac{9}{22}+\frac{5}{31}+\frac{-13}{22}+\frac{88}{31}+\frac{1}{2}\)
\(=-1+3+\frac{1}{2}\)
\(=2+\frac{1}{2}\)
\(=\frac{5}{2}\)
27 tháng 11 2018
= \(\left(\frac{-9}{22}+\frac{-13}{22}\right)+\left(\frac{5}{31}+2\frac{26}{31}\right)+0,5\)
= \(-1+3+0,5\)
= \(2+0,5\)
= \(2,5\)
k mik nhé
♥♪♕ ๖ۣۜHắc ๖ۣۜTiểu ๖ۣۜThư ♕♪♥
\(4^{13}.5^{26}=4^{13}.\left(5^2\right)^{13}=4^{13}.25^{13}\)
\(\left(4.25\right)^{13}=100^{13}\)
tik mik nhé !!