Question

[Đỗ Lan Anh]

Tìn B=1+2+4+8+...+4098

Answer 1

[Trần Thanh Phương]

\(B=1+2+4+...+4096\)

\(B=1+2+2^2+2^3+...+2^{12}\)

\(2B=2+2^2+...+2^{13}\)

\(2B-B=\left(2+2^2+...+2^{13}\right)-\left(1+2+...+2^{12}\right)\)

\(B=2^{13}-1\)

Answer 2

[My Love bost toán]

B=1+2+4+8+...+4098

B=\(1+2+2^2+2^3+....+2^{12}\)

2B=\(2+2^2+2^3+2^4+.....+2^{13}\)

2B-B=\(\left(2+2^2+2^3+2^4+...+2^{13}\right)-\left(1+2+2^2+2^3...+2^{12}\right)\)

B=\(2^{13}-1\)