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\(\frac{7}{y}=\frac{1}{12}\)
\(=>\frac{7}{y}=\frac{7}{84}\)
\(=>y=84\)
\(\frac{9}{10}-y.\frac{3}{4}=\frac{2}{5}\)
\(y.\frac{3}{4}=\frac{9}{10}-\frac{2}{5}=\frac{1}{2}\)
\(y=\frac{1}{2}:\frac{3}{4}\)
\(y=\frac{1}{2}.\frac{4}{3}\)
\(y=\frac{2}{3}\)
\(\frac{5}{6}:\left[y+\frac{7}{9}\right]=\frac{3}{4}\)
\(y+\frac{7}{9}=\frac{5}{6}:\frac{3}{4}\)
\(y+\frac{7}{9}=\frac{5}{6}.\frac{4}{3}\)
\(y+\frac{7}{9}=\frac{10}{9}\)
\(y=\frac{10}{9}-\frac{7}{9}\)
\(y=\frac{3}{9}\)
\(y=\frac{1}{3}\)
1, 7/y=1/12
=>7.12=y
=>y=84
2, 9/10-y.3/4=2/5
=>y.3/4=9/10-2/5
=>y.3/4=1/2
=>y=1/2:3/4=2/3
3, 5/6[y+7/9]=3/4
=>y+7/9=5/6:3/4
=>y+7/9=10/9
=>y=10/9-7/9
=>y=1/3

\(a.\)\(y-\frac{11}{3}=\frac{12}{5}\)
\(y=\frac{12}{5}+\frac{11}{3}\)
\(y=\frac{91}{15}\)
\(b.2-y=\frac{15}{6}\)
\(y=2-\frac{15}{6}\)
\(y=-\frac{1}{2}\)
\(c.y\times2\frac{2}{3}=\frac{4}{9}\)
\(y=\frac{4}{9}:2\frac{2}{3}\)
\(y=\frac{1}{6}\)
\(d.y:1\frac{2}{5}=\frac{21}{10}\)
\(y=\frac{21}{10}\times1\frac{2}{5}\)
\(y=\frac{147}{5}\)

\(a.\frac{Y}{3}=\frac{27}{Y}\Leftrightarrow\frac{Y^2}{3Y}=\frac{3.27}{3Y}\)
\(\Rightarrow Y^2=3.27=81\)
Do \(\orbr{\begin{cases}81=\left(-9\right)^2\\81=9^2\end{cases}\Rightarrow}\orbr{\begin{cases}Y=-9\\Y=9\end{cases}}\)
Vậy \(Y\in\left\{-9;9\right\}.\)
\(b.\frac{15}{Y}=\frac{Y}{9}\Leftrightarrow\frac{15.9}{Y.9}=\frac{Y^2}{9.Y}\)
\(\Rightarrow15.9=135=Y^2\)
Do \(\orbr{\begin{cases}135=\left(-\sqrt{135}\right)^2\\135=\sqrt{135}^2\end{cases}\Rightarrow}\orbr{\begin{cases}Y=-\sqrt{135}\\Y=\sqrt{135}\end{cases}}\)
Vậy \(Y\in\left\{-\sqrt{135};\sqrt{135}\right\}.\)
\(c.\frac{15}{48}:y=\frac{10}{4}\)
\(\Rightarrow y=\frac{15}{48}:\frac{10}{4}=\frac{1}{8}\)
Vậy \(y=\frac{1}{8}.\)
\(d.\frac{20}{y}.9=\frac{60}{135}\)
\(\Rightarrow\frac{20}{y}=\frac{60}{135}:9=\frac{20}{135}\)
\(\Leftrightarrow y=135\)
Vậy \(y=135.\)
\(e.\frac{16}{Y}=\frac{Y}{9}\Leftrightarrow\frac{16.9}{Y.9}=\frac{Y^2}{Y.9}\)
\(\Rightarrow16.9=144=Y^2\)
Do \(\orbr{\begin{cases}144=\left(-12\right)^2\\144=12^2\end{cases}\Rightarrow\orbr{\begin{cases}Y=-12\\Y=12\end{cases}}}\)
Vậy \(Y\in\left\{-12;12\right\}\)
\(g.\frac{25}{Y}=\frac{Y}{9}\Leftrightarrow\frac{25.9}{Y.9}=\frac{Y^2}{9.Y}\)
\(\Rightarrow25.9=225=Y^2\)
Do \(\orbr{\begin{cases}225=\left(-15\right)^2\\225=15^2\end{cases}\Rightarrow\orbr{\begin{cases}Y=-15\\Y=15\end{cases}}}\)
Vậy \(Y\in\left\{-15;15\right\}.\)
\(h.y-\frac{12}{42}=\frac{10}{12}\)
\(\Rightarrow y=\frac{10}{12}+\frac{12}{42}=\frac{47}{42}\)
Vậy \(Y=\frac{47}{42}.\)
\(i.y+\frac{5}{30}=\frac{18}{2}\)
\(\Rightarrow y=\frac{18}{2}-\frac{5}{30}=\frac{53}{54}\)
Vậy \(y=\frac{53}{54}.\)
mấy câu này gần như là giống nhau nên mik giải 1 câu rồi bạn dựa theo mà giải tiếp nha
y/3 = 27/y => y2 = 3 . 27
=> y2 = 81 => y = 9 hoặc -9
vậy .....

a)100-9:(372:3.y-1)-14=83
<=>100-9:(124y-1)-14=83
<=>86-9:(124y-1)=83
<=>9:(124y-1)=3
<=>124y-1=3
<=>124y=4
<=>y=\(\frac{1}{31}\approx0,3223\)
b)7260-120:24.y+924=528,3
<=>8184-5y=528,3
<=>5y=7655,7
<=>y=1531,14
c)2000-52:(615:3:y-15)-14=1984
<=>1986-52:(205:y-15)=1984
<=>52:(205:y-15)=2
<=>205:y-15=26
<=>205:y=41
<=>y=5
d)y+y.1/3+5/18=7/18
<=>4/3y=1/9
<=>y=1/12
e)13/15-(5/21+y)7/12=7/10
<=>7/12.(5/21+y)=1/6
<=>5/36+7/12y=1/6
<=>7/12y=1/36
<=>y=1/21\(\approx\)0,4762
h)y+2.y+3.y+...+10.y=49,5
<=>55y=49,5
<=>y=0,9
i)y.(1975/8.9+1885/9.10+1755/10.11+1579/11.12)=1/24
<=>7991,364899y=1/24
<=>y=33/6329161
tích nha mỏi tay quá

\(\frac{5}{12}\): y =\(\frac{5}{6}\)-\(\frac{1}{2}\)*\(\frac{5}{4}\)
5/12.1/y=5/6-5/8
\(\frac{5}{12y}\)=\(\frac{5}{24}\)
\(\Rightarrow\)12y=24
y=2

a 9/15 x y = (5/7 +3/14) x 4/7
9/15 x y = 13/14 x 4/7
9/15 x y = 26/49
y= 26/49 : 9/15
y= 130/147
b, y : 0,25 = (2,5-1,3) : 0,75
y : 1/4 = 8/5
y= 8/5 x 1/4 = 2/5
a/
9/14 x y = (5/7 + 3/14) x 4/7
9/14 x y = 13/14 x 4/7
9/14 x y = 26/49
y = 26/49 : 9/14
y = 52/63
b/
y : 0,25= (2,5 - 1,3) : 0,75
y : 0,25= 1,2 : 0,75
y : 0,25= 1,6
y = 1,6 x 0,25
y = 0,4
chúc học tốt nhé!!! học giỏi !!!
\(y+y:\frac{12}{5}=\frac{9}{4}\)
\(y+y\times\frac{5}{12}=\frac{9}{4}\)
\(y\times\left(1+\frac{5}{12}\right)=\frac{9}{4}\)
\(y\times\frac{17}{12}=\frac{9}{4}\)
\(y=\frac{9}{4}:\frac{17}{12}\)
\(y=\frac{27}{17}\)