Question

[tran vinh]

tìm x,y,z nguyên dương biết x²+y²=z²

Answer 1

[28 . Phạm Tài Đức Pháp]

TL

HT ( sai thì cho mik xin lỗi nhìu )

Answer 2

[❖×✔ᴍê ʜọᴄ)ミ★ ❖(☂TΣΔM☂STUDIΣS☂)ミ★]

⇒(x2+1x2−2)+(y2+1y2−2)+(z2+1z2−2)=0⇒(x2+1x2−2)+(y2+1y2−2)+(z2+1z2−2)=0

⇒(x−1x)2+(y−1y)2+(z−1z)2=0⇒(x−1x)2+(y−1y)2+(z−1z)2=0

⇒\hept⎧⎪ ⎪⎨⎪ ⎪⎩x−1x=0y−1y=0z−1z=0⇒\hept⎧⎪ ⎪⎨⎪ ⎪⎩x=1xy=1yz=1z⇒\hept⎧⎨⎩x2=1y2=1z2=1⇒x=y=z=1⇒\hept{x−1x=0y−1y=0z−1z=0⇒\hept{x=1xy=1yz=1z⇒\hept{x2=1y2=1z2=1⇒x=y=z=1 (vì x,y,z >