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\(3xy-2x+y=3\)
\(\Leftrightarrow9xy-6x+3y=9\)
\(\Leftrightarrow\left(3x+1\right)\left(3y-2\right)=7\)
Ta có bảng giá trị:
3x+1 | -7 | -1 | 1 | 7 |
3y-2 | -1 | -7 | 7 | 1 |
x | -8/3 | -2/3 | 0 | 2 |
y | 1/3 | -5/3 | 3 | 1 |
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2xy-x+y=3 =>x(2y-1)+y=3 =>2x(2y-1)+2y=6 =>2x(2y-1)+2y-1=5
=>(2x+1)(2y-1)=5
Tự lập bảng nha
=>(x,y) thuộc (0,3);(2,1);(-1,-2);(-3,0)
2xy - x + y = 3
=> 2(2xy - x + y) = 6
=> 4xy - 2x + 2y = 6
=> 2x(2y - 1) + (2y - 1) = 5
=> (2x + 1)(2y - 1) = 5
=> 2x + 1; 2y - 1 \(\in\)Ư(5) = {1; -1; 5; -5}
Lập bảng :
2x + 1 | 1 | -1 | 5 | -5 |
2y - 1 | 5 | -5 | 1 | -1 |
x | 0 | -1 | 2 | -3 |
y | 3 | -2 | 1 | 0 |
Vậy ...
3xy + 2x - y = 2
=> 3(3xy + 2x - y) = 6
=> 9xy + 6x - 3y = 6
=> 3x(3y + 2) - (3y + 2) = 4
=> (3x - 1)(3y + 2) = 4
=> 3x - 1; 3y + 2 \(\in\)Ư(4) = {1; -1; 2; -2; 4; -4}
Lập bảng :
3x - 1 | 1 | -1 | 2 | -2 | 4 | -4 |
3y + 2 | 4 | -4 | 2 | -2 | 1 | -1 |
x | 2/3(ktm) | 0 | 1 | -1/3(ktm) | 5/3(ktm) | -1 |
y | 2/3(ktm) | -2 | 0 | -4/3(ktm) | -1/3(ktm) | -1 |
Vậy ...
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y-2x+3xy=24
3xy+y-2x=24
y(3x+1)-2x=24
y(3x+1)-2x-24=0
y(3x+1)-2x-2/3-70/3=0
y(3x+1)-2(x+1/3)-70/3=0
3y(x+1/3)-2(x+1/3)-70/3=0
(x+1/3)(3y-2)=70/3
3(x+1/3)(3y-2)=70
(3x+1)(3y-2)=70
Tự làm nhé^^
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A=2(x+y)+3xy(x+y)+5x2y2(x+y)+2
A=2.0+3xy.0+5x2y2.0+2
A=2
B=xy(x+y)+2x2y (x+y)+5
B=xy.0+2x2y.0+5=5
a,Ta có 2(x+y)+3xy(x+y)+5x2y2(x+y)+4
Xg thay x+y=0 vào là dc bn nhó
Chúc bn hok tốt
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2:
a: A(x)=0
=>5x-10-2x-6=0
=>3x-16=0
=>x=16/3
b: B(x)=0
=>5x^2-125=0
=>x^2-25=0
=>x=5 hoặc x=-5
c: C(x)=0
=>2x^2-x-3=0
=>2x^2-3x+2x-3=0
=>(2x-3)(x+1)=0
=>x=3/2 hoặc x=-1