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\(2^x=32=>x=5\)
\(2^{x+1}=32=>x+1=5=>x=4\)
\(x^3=125=>x=5\)
\(\left(x+1\right)^3=125=>x+1=5=>x=4\)
3. x3 = 125 => x = 5
4. (x + 1)3 = 125
(x + 1)3 = 53
=> x + 1 = 5
=> x = 4
t i c k nhé!! 45457474678789886973463125135153152454654657657868768
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a/2x+2-2x=96
2x(22-1)=96
2x3=96
2x=96:3
2x=32
2x=25
x=5
b/(x-1)3=125
(x-1)3=53
x-1=5
x=6
c/(2x+1)3=343
(2x+1)3=73
2x+1=7
2x=6
x=3
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(5^{x+1}=125=5^3\)
\(\Rightarrow x+1=3\Rightarrow x=2\)
b) \(\left(x-16\right)^2=9=3^2\)
\(\Rightarrow x-16=3\Rightarrow x=19\)
d) \(\left(x-1\right)^2=\left(x-1\right)^3\)
\(\Rightarrow\orbr{\begin{cases}x-1=0\\x-1=1\end{cases}\Rightarrow\orbr{\begin{cases}x=1\\x=2\end{cases}}}\)
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a) 3x-5=4
3x = 4+5
3x=9
=> 9 = 3x = 32
<=> x=2
b) 5x-2 = 125
=> 5x-2 = 53
<=> x-2 = 3
x = 3+2
x = 5
c) x3 = 8
<=> x3 = 8 = 23
<=> x= 2
d) (x-1)3 = 125
=> x-1 = 5
x = 5+1
x = 6
a) 3^x-5=4
=>3^x =9
=>3^x =3^2
=> x = 2
b)5^x-2=125
=>5^x-2=5^3
=>x-2=3
=>x =5
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\left(x-2\right)^5=243\)
\(\left(x-2\right)^5=3^5\)
\(\Rightarrow x-2=3\)
\(\Rightarrow x=5\)
vay \(x=5\)
b) \(\left(x+1\right)^3=125\)
\(\left(x+1\right)^3=5^3\)
\(\Rightarrow x+1=5\)
\(\Rightarrow x=4\)
vay \(x=4\)
![](https://rs.olm.vn/images/avt/0.png?1311)
(2*x+1)3=125
(2*x+1)=5^3
2*x+1 =5
2*x =5-1
2*x =4
x=4:2
x=2
con may cau hoi kia lat lam tiep
chuc bn hoc gioi!
nha
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2x.4=128
=> 2x=128:4
=> 2x=32
=> 2x=25
=> x=5
(2x+1)3=125
=>(2x+1)3=53
=>2x+1=5
=>2x=5-1
=>2x=4
=>2x=22
=>x=2
2x-15=17
=>2x=17+15
=>2x=32
=>2x=25
=>x=5
(x+1)3=125
(x+1)3=53
x+1 =5
x =5-1=4
( x + 1 )3 = 125
<=> 2x + 1 = 5 ( vì là bậc 3 lên giữ nguyên dấu )
<=> 2x = 4
<=> x = 2