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a) 7(x-5)+14=56
<=>7(x-5)=42
<=>x-5=6
<=>x=11
b)9(x+1)-3=15
<=>9(x+1)=18
<=>x+1=2
<=>x=1
c)12(x+5)-36=48
<=>12(x+5)=84
<=>x+5=7
<=>x=2
d)5(x+14)=145
<=>x+14=29
<=>x=15
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15 : ( x + 2 ) = ( 33 + 3 ) : 10
15 : ( x + 2 ) = ( 27 + 3 ) : 10
15 : ( x + 2 ) = 30 : 10
15 : ( x + 2 ) = 3
x + 2 = 15 : 3
x + 2 = 5
x = 5 - 2
x = 3
Vậy x = 3
32( x + 1 ) - 3 = 23 + 72 . 2 : 14
9( x + 1 ) - 3 = 8 + 49 . 2 : 14
9( x + 1 ) - 3 = 8 + 98 : 14
9( x + 1 ) - 3 = 8 + 7
9( x + 1 ) - 3 = 15
9( x + 1 ) = 15 + 3
9( x + 1 ) = 18
x + 1 = 18 : 9
x + 1 = 2
x = 2 - 1
x = 1
Vậy x = 1
Học Tốt!!!
a, 15 : (x+2) = (33 +3) :10
15 : (x+2) = (27+3): 10
15 : ( x+2) = 30: 2
15 : (x + 2) = 15
x+2 = 15: 15
x+2 = 1
x = 1-2
x = -1
b, 32 (x+1) - 3 = 23 + 72 . 2 :14
9 ( x+1) -3 = 8 + 49 . 2 : 14
9 (x+1) -3 = 8+98:14
9 (x+1) -3 = 8+7
9 (x+1) -3 = 15
9 (x+1) =15+3
9(x+1) = 18
x+1 = 18 :2
x+1 = 9
x = 9-1
x =8
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a/ (ghi lại cái đề)
=>+ 3x-7=2
3x=2+7=9
x=3
+ 3x-7=-2
3x=-2+7=5
x=\(\frac{5}{3}\)
b/ (5x-10)2=100
=> +5x-10=10
5x=10+10=20
x=4
+ 5x-10=-10
5x=-10+10=0
x=0
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a) \(2\left(2x-7\right)^2=18\)
\(\Leftrightarrow\left(2x-7\right)^2=9\)
\(\Leftrightarrow\left(2x-7\right)^2=3^2\)
\(\Leftrightarrow2x-7=3\)
\(\Leftrightarrow2x=10\)
\(\Leftrightarrow x=5\)
2.(2X-7)^2= 18
(2X-7)^2=18:2
(2x-7)^2= 9
(2x-7)^2 = 3^2 = (-3)^2
=> (2x-7)^2 = 3^2 và (2x-7)^2 = (-3)^2
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a) (x - 140) : 7 = 33-23.3
(x - 140) : 7 = 27 - 8 . 3
(x - 140) : 7 = 27 - 24
(x - 140) : 7 = 3
x - 140 = 21
x = 161
b) 7 (x - 14) + 35 = 52+279 : 32
7 (x - 14) + 35 = 25 + 279 : 9
7 (x - 14) + 35 = 25 + 31
7 (x - 14) + 35 = 56
7 (x - 14) = 21
x - 14 = 3
x = 17
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Câu 2:
(8^7)/(2^18)
=(2^21)/(2^18)
=2^3=8 không chia hết cho 14 nhé