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1. 25 . 3x-3 = 2025
3x-3 = 2025 : 25
3x-3 = 81
3x-3 = 34
=> x - 3 = 4
x = 4 + 3
x = 7
Vậy x = 7
2. Chứng minh:
M = 2 + 22 + 23 +...+298
M = ( 2 + 22 ) + ( 23 + 24 ) +...+ ( 297 + 298 )
M = 2.( 1 + 2 ) + 23.( 1 + 2 ) +...+ 297.( 1 + 2 )
M = 2.3 + 23.3 +...+ 297.3 \(⋮\)3
=> M\(⋮\)3
=> (1+2X-1)x (2x-1+1)/4=225
=> 2x+2x/4=225
=> 4x^2/4=225
=> x^2= 225
=> x=15
cái ^ là mũ nha bạn
chúc bn hok tốt
`Answer:`
a. Tổng: \([\left(2x-1\right)-1]:2+1=x\) số hạng
Ta có: \(1+3+5+7+9+...+\left(2x-1\right)=225\)
\(\Rightarrow x.\left(2x-1+1\right):2=225\)
\(\Leftrightarrow2x^2:2=225\)
\(\Leftrightarrow x^2=225\)
\(\Leftrightarrow x=15\)
b. Mình sửa đề nhé: \(2^x+2^{x+1}+2^{x+2}+2^{x+3}+...+2^{x+2015}=2^{2019}-8\)
\(\Rightarrow2^x.\left(1+2+2^2+...+2^{2015}\right)=2^{2019}-8\)
Ta đặt \(K=1+2+2^2+...+2^{2015}\)
\(\Rightarrow2^x.K=2^{2019}-8\)
\(\Rightarrow2K=2.\left(1+2+2^2+...+2^{2015}\right)\)
\(\Rightarrow2K=2+2^2+2^3+...+2^{2015}+2^{2016}\)
\(\Rightarrow2K-K=\left(2+2^2+2^3+...+2^{2015}+2^{2016}\right)-\left(1+2+2^2+...+2^{2015}\right)\)
\(\Rightarrow K=2^{2016}-1\)
\(\Rightarrow2^x.\left(2^{2016}-1\right)=2^{2019}-8\)
\(\Rightarrow2^{x+2016}-2^x=2^{2019}-2^3\)
\(\Rightarrow\hept{\begin{cases}x+2016=2019\\x=3\end{cases}}\Rightarrow x=3\)
c) pt <=> \(x-\frac{21}{5}=\frac{23}{7}< =>x=\frac{23}{7}+\frac{21}{5}=\frac{262}{35}\)
vậy x = \(\frac{262}{35}\)
d) \(x-\frac{3}{4}=\frac{51}{8}< =>x=\frac{51}{8}+\frac{3}{4}=\frac{57}{8}\)
vậy x = \(\frac{57}{8}\)
e) pt <=> \(\frac{7}{8}:x=\frac{7}{2}< =>\frac{7}{8}.\frac{1}{x}=\frac{7}{2}< =>\frac{7}{8x}=\frac{7}{2}< =>56x=14< =>x=\frac{14}{56}=\frac{1}{4}\)
vậy x = \(\frac{1}{4}\)
a) pt <=> \(x+\frac{11}{4}=\frac{17}{3}< =>x=\frac{17}{3}-\frac{11}{4}=\frac{35}{12}\)
vậy x = \(\frac{35}{12}\)
b) pt <=> \(\frac{x.7}{2}=\frac{19}{4}< =>x=\frac{19.2}{4.7}=\frac{38}{28}=\frac{19}{14}\)
vậy x = \(\frac{19}{14}\)
a, 2x + 2x+1 + 2x+2 + 2x+3 = 480
=> 2x + 2x.2 + 2x.22 + 2x.23 = 480
=> 2x.(1 + 2 + 22 + 23) = 480
=> 2x.15 = 480
=> 2x = 480 : 15
=> 2x = 32 = 25
=> x = 5
b, |7 - x| = -13 - 5.(-8)
|7 - x| = 27
\(\Rightarrow\hept{\begin{cases}7-x=27\\-7+x=27\end{cases}}\Rightarrow\hept{\begin{cases}x=-20\\x=34\end{cases}}\)
a) \(3^{x+1}=729\)\(\Leftrightarrow3.3^x=729\Rightarrow3^x=243\Rightarrow3^x=3^5\Rightarrow x=5\)
b) \(2^x+2^{x+1}+2^{x+3}=704\Rightarrow2^x+2^x.2+2^x.2^3=704\Rightarrow2^x\left(1+2+8\right)=704\)
\(\Rightarrow2^x.11=704\Rightarrow2^x=64\Rightarrow2^x=2^5\Rightarrow x=5\)