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a) \(326-2x=78\Rightarrow2x=326-78=248\)
\(\Rightarrow x=248:2=124\)
b) \(42.5-\left(3x+6\right)=3^4\Rightarrow210-\left(3x+6\right)=81\)
\(\Rightarrow3x+6=210-81=129\Rightarrow3x=129-6=123\)
\(\Rightarrow x=123:3=41\)
a, 326 -2x =78
\(\Rightarrow\)2x=326-78=248
\(\Rightarrow\)x=248/2=124
b,\(42.5-\left(3x+6\right)=3^4\)
\(\Rightarrow\)\(210-3x-6=81\)
\(\Rightarrow\)3x=123
\(\Rightarrow\)x=123/3=41
c, \(4^x:64=4^{250}\)
\(\Rightarrow\)\(4^x:4^3=4^{250}\)
\(\Rightarrow\)x=253
d, \(30x+1+2+3+...+30=495\)
\(\Rightarrow\)\(30x+465=495\)
\(\Rightarrow\)\(x=1\)
a) \(5^4:\left(2x-1\right)^2=25\\ \Leftrightarrow5^4:\left(2x-1\right)^2=5^2\\ \Leftrightarrow5^4:5^2=\left(2x-1\right)^2\\ \Leftrightarrow\left[{}\begin{matrix}\left(2x-1\right)^2=5^2\\\left(2x-1\right)^2=\left(-5\right)^2\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}2x-1=5\\2x-1=-5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-2\end{matrix}\right.\)
b) \(17^3.x=17^4\\ \Rightarrow x=17^4:17^3=17\)
c) \(\left(2x+1\right)^3:49=7\\ \Leftrightarrow\left(2x-1\right)^3:7^2=7\\ \Leftrightarrow\left(2x-1\right)^3=7.7^2=7^3\\ \Leftrightarrow2x-1=7\\ \Leftrightarrow x=4\)
a)54 : (2x - 1)2 =25
54 : (2x - 1)2 =52
(2x - 1)2 =54 : 52
(2x - 1)2 = 52
2x - 1 = 5
2x = 5+1
2x = 6
x = 6: 2
x = 3
b)173.x = 174
x = 174 : 173
x = 17
c)(2x + 1)3 : 49 =7
(2x + 1)3 = 7 . 49
(2x + 1)3 = 343
(2x + 1)3 = 73
2x +1 = 7
2x = 7- 1
2x = 6
x = 6:2
x = 3
A, \(4^{2x-6}=1\)
\(\Rightarrow4^{2x-6}=4^0\)
\(\Rightarrow2x-6=0\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=3\)
B, \(5^{2x-3}-2.5^2=5^2.3\)
\(\Rightarrow5^{2x-3}=5^2.3+2.5^2\)
\(\Rightarrow5^{2x-3}=5^2.\left(3+2\right)\)
\(\Rightarrow5^{2x-3}=5^2.5\)
\(\Rightarrow5^{2x-3}=5^3\)
\(\Rightarrow2x-3=3\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=3\)
Nguyễn Ngô Gia Hân:
1.Tìm x
\(^{\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{x.\left(x+1\right)}=\frac{29}{30}}\)
\(^{\Leftrightarrow\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{x}+\frac{1}{\left(x+1\right)}=\frac{29}{30}}\)
\(^{\Leftrightarrow\frac{1}{1}+\left(\frac{1}{2}-\frac{1}{2}\right)+\left(\frac{1}{3}-\frac{1}{3}\right)+\left(\frac{1}{4}-\frac{1}{4}\right)+...+\left(\frac{1}{x}-\frac{1}{x}\right)-\frac{1}{x+1}=\frac{29}{30}}\)
\(^{\Leftrightarrow\frac{1}{1}+0+0+0+...+0-\frac{1}{x+1}=\frac{29}{30}}\)
\(^{\Leftrightarrow\frac{1}{1}-\frac{1}{x+1}=\frac{29}{30}}\)
\(^{\Leftrightarrow\frac{1}{x+1}=\frac{1}{1}-\frac{29}{30}}\)
\(^{\Leftrightarrow\frac{1}{x+1}=\frac{1}{30}}\)
\(^{\Leftrightarrow x+1=30}\)
\(^{\Leftrightarrow x=29}\)
Vậy x =29
Làm đc mỗi bài này thoi, tham khảo nha ~~
Bài 1 có rồi mk làm mấy bài sau nhé
Bài 2 :
Ta có :
\(3a=4b\)\(\Rightarrow\)\(\frac{b}{3}=\frac{a}{4}\) và \(b-a=-10\)
Áp dụng tính chất dãy tỉ số bằng nhau ta có :
\(\frac{b}{3}=\frac{a}{4}=\frac{b-a}{3-4}=\frac{-10}{-1}=10\)
Do đó :
\(\frac{a}{4}=10\)\(\Rightarrow\)\(a=10.4=40\)
\(\frac{b}{3}=10\)\(\Rightarrow\)\(b=10.3=30\)
Vậy \(a=40\) và \(b=30\)
Chúc bạn học tốt ~
2/
a) \(3x+18=3^5\): \(3^2\)
\(3x+3.6=3^3\)
\(3\left(x+6\right)=3^3\)
\(x+6=3^2\)
\(x+6=9\)
\(x=3\)
b) \(95-3\left(x+1\right)=32\)
\(3\left(x+1\right)=95-32\)
\(3\left(x+1\right)=63\)
\(x+1=21\)
\(x=20\)
3/ so sánh \(4^{30}\) và \(3^{40}\)
\(4^{30}=\left(4^3\right)^{10}=64^{10}\)
\(3^{40}=\left(3^4\right)^{10}=81^{10}\)
Vì \(64^{10}< 81^{10}\)
nên \(4^{30}< 3^{40}\)
B)|2x-1|=8
Chia lam hai trường hợp
2x-1=8hoac. 2x-1=-8
2x=8+1 2x=-8+1
2x=9. 2x=-9
x=9:2. X=-9:2
. X=-4,5
x=4,5