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2. 3x = 162
3x = 162 : 2
3x = 81
3x = 34
=> x = 4
2x + 23 = 23 . 32
2x + 8 = 72
2x = 72 - 8
2x = 64
2x = 26
=> x = 6
a) 2.3x = 162
3x = 81 = 34
=> x = 4
b) 2x + 23 = 23.32
2x = 64 = 26
=> x = 6
c, d bn lm tương tự như phần a nha
e) (1+2x)3 = 729 = 93
=> 1 + 2x = 9
2x = 8
x = 4
f) 2x + 2x+3 = 144
2x.(1+23) = 144
2x.9 = 144
2x = 16 = 24
=> x = 4
\(a,[\left(8.x-12\right):4].3^3.3=3^6.6\)
\(\left(8x-12\right):4=54\)
\(8x-12=216\)
\(8x=228\)
\(x=28,5\)
\(b,41-2^{x+1}=9\)
\(2^{x+1}=41-9\)
\(2^{x+1}=32\)
\(2^{x+1}=2^5\)
\(\Rightarrow x+1=5\)
\(\Rightarrow x=4\)
Bài 1 :
a/ \(a^3.a^9=a^{3+9}=a^{12}\)
b/\(\left(a^5\right)^7=a^{5.7}=a^{35}\)
c/ \(\left(a^6\right).4.a^{12}=a^{24}.a^{12}.4=a^{24+12}.4=a^{36}.4\)
d/ \(\left(2^3\right)^5.\left(2^3\right)^3=2^{15}.2^9=2^{15+9}=2^{24}\)
e/ \(5^6:5^3+3^3.3^2\)
\(=5^3+3^5=125+243=368\)
i/ \(4.5^2-2.3^2\)
\(=2^2.5^2-2.3^2\)
\(=2^2.25-2^2.14\)
\(=2^2.\left(25-14\right)\)
\(=2^2.11\)
\(=4.11=44\)
a,71.2-6.(2x+5)=10^5:10^3
142-6.(2x+5)=10^2
142-6.(2x+5)=100
6.(2x+5)=142-100
6.(2x+5)=42
2x+5=42:6
2x+5=7
2x=7-5
2x=2
x=1
Vậy x=1
a) (7x - 11)3 = 25.52 + 200
=> (7x - 11)3 = 1000
=> (7x - 11)3 = 103
=> 7x - 11 = 10
=> 7x = 10 + 11
=> 7x = 21
=> x = 21 : 7
=> x = 3
b) x10 = 1x
=> x10 = 1
=> x10 = 110
=> x = 1
c) x10 = x
=> x10 - x = 0
=> x(x9 - 1) = 0
=> \(\orbr{\begin{cases}x=0\\x^9-1=0\end{cases}}\)
=> \(\orbr{\begin{cases}x=0\\x^9=1\end{cases}}\)
=> \(\orbr{\begin{cases}x=0\\x=1\end{cases}}\)
Vậy...
\(a,2.3^x=10.3^{12}+8.27^4\)
\(\Leftrightarrow2.3^x=3^{12}\left(10+8\right)\)
\(\Leftrightarrow2.3^x=3^{12}.18\)
\(\Leftrightarrow2.3^x=3^{12}.3^2.2\)
\(\Leftrightarrow2.3^x=2.3^{14}\)
\(\Rightarrow3^x=3^{14}\)
\(\Rightarrow x=14\)
\(b,2^{4x}.3^6=12^6\)
\(\Leftrightarrow2^{4x}.3^6=2^{12}.3^6\)
\(\Rightarrow2^{4x}=2^{12}\)
\(\Rightarrow4x=12\)
\(\Rightarrow x=3\)