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a) \(3^{x+1}=729\)\(\Leftrightarrow3.3^x=729\Rightarrow3^x=243\Rightarrow3^x=3^5\Rightarrow x=5\)
b) \(2^x+2^{x+1}+2^{x+3}=704\Rightarrow2^x+2^x.2+2^x.2^3=704\Rightarrow2^x\left(1+2+8\right)=704\)
\(\Rightarrow2^x.11=704\Rightarrow2^x=64\Rightarrow2^x=2^5\Rightarrow x=5\)

\(-5.\left(x+\frac{1}{5}\right)-\frac{1}{2}.\left(x-\frac{2}{3}\right)=\frac{3}{2}x-\frac{5}{6}\)
\(\Rightarrow-5x-1-\frac{1}{2}x+\frac{1}{3}=\frac{3}{2}x-\frac{5}{6}\)
\(\Rightarrow-5x-\frac{1}{2}x-\frac{3}{2}x=\frac{-5}{6}-\frac{1}{3}+1\)
\(\Rightarrow-7x=\frac{-1}{6}\)
\(\Rightarrow x=\frac{1}{42}\)
Vậy ...
\(\)
\(3.\left(3x-\frac{1}{2}\right)^3+\frac{1}{9}=0\)
\(\Rightarrow3.\left(3x-\frac{1}{2}\right)^3=\frac{-1}{9}\)
\(\Rightarrow\left(3x-\frac{1}{2}\right)^3=\frac{-1}{27}\)
\(\Rightarrow\left(3x-\frac{1}{2}\right)^3=\left(\frac{-1}{3}\right)^3\)
\(\Rightarrow3x-\frac{1}{2}=\frac{-1}{3}\)
\(\Rightarrow3x=\frac{1}{6}\)
\(\Rightarrow x=\frac{1}{18}\)
Vậy...

\(1\frac{3}{4}x-5=-3\frac{1}{3}\)
=> \(\frac{7}{4}x=-\frac{10}{3}+5\)
=> \(\frac{7}{4}x=\frac{5}{3}\)
=> x = 5/3 : 7/4
=> x = 20/21
\(\frac{x-2}{20}=\frac{5}{2-x}\)
=> (x - 2)(2 - x) = 20.5
=> -(x - 2)2 = 100
=> (x - 2)2 = -102
=> ko có giá trị x

a, \(\frac{x}{5}=\frac{2}{3}\Leftrightarrow x=\frac{10}{3}\)
b, \(\frac{x}{-24}=\frac{20}{42}\Leftrightarrow x=-\frac{80}{7}\)
c, \(\frac{x+3}{15}=\frac{1}{3}\Leftrightarrow3x+9=15\Leftrightarrow x=2\)
d, \(\frac{2}{3}x-\frac{3}{2}x=\frac{5}{12}\Leftrightarrow x\left(\frac{2}{3}-\frac{3}{2}\right)=\frac{5}{12}\Leftrightarrow-\frac{5}{6}x=\frac{5}{12}\Leftrightarrow x=-\frac{1}{2}\)

\(-5\left(x+\frac{1}{5}\right)-\frac{1}{2}\left(x-\frac{2}{3}\right)=\frac{3}{2}x\)
\(\Leftrightarrow-5x-1-\frac{1}{2}x+\frac{1}{3}-\frac{3}{2}x=0\)
\(\Leftrightarrow-5x-\frac{1}{2}x-\frac{3}{2}x=0+1-\frac{1}{3}\)
\(\Leftrightarrow x\left(-5-\frac{1}{2}-\frac{3}{2}\right)=\frac{2}{3}\)
\(\Leftrightarrow-7x=\frac{2}{3}\)
\(\Leftrightarrow x=\frac{2}{3}:\left(-7\right)=\frac{-2}{21}\)

kakashi hahahahahahahahahahahahahahahahahahahahahahahahahahahahaha
\(\frac{5}{2x}-3=\frac{1}{x}\)
\(\frac{5}{2x}-\frac{1}{x}=3\)
\(\frac{5}{2x}-\frac{2}{2x}=3\)
\(\frac{3}{2x}=3\)
\(\frac{1}{2x}=\frac11\)
\(2x=1\)
\(x=\frac12\)
vậy x = \(\frac12\)
5/2.x - 3 = 1/x
⇔ 5x² - 6x = 2
⇔ 5x² - 6x - 2 = 0
Giải phương trình bậc 2:
x = (3 ± √19) / 5
Vậy x = (3 + √19) / 5 hoặc x = (3 - √19) / 5.