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a) Ta có : 5x = 125
=> 5x = 53
=> x = 3
b) Ta có : 32x = 81
=> 32x = 34
=> 2x = 4
=> x = 4 : 2 = 2
c) Ta có : 52x + 3 - 2 . 52 = 52 . 3
=> 52x + 3 = 52 . 3 + 2 . 52
=> 52x + 3 = 52 . (3 + 2)
=> 52x + 3 = 52 . 5 = 53
=> 2x + 3 = 3
=> 2x = 3 - 3 = 0
=> x = 0 : 2 = 0
a)5x=125<=>5x=53=>x=3
b)32x=81<=>32x=34=>2x=4=>x=2
c)52x+3-50=75
52x+3=75+50
52x+3=125
<=>52x+3=53
=>2x+3=3
=>2x=0
=>x=0
\(1,2x+3x-4x=\left(-2\right)^3\)
<=>\(x=-8\)
\(2,x-2x=4^2+4^0\)
<=>\(-x=16+1\)
<=>\(-x=17\)
<=>\(x=-17\)
\(3,2^3x-3^2x=|12-21|\)
<=>\(-x=9\)
<=>\(x=-9\)
\(4,x-45=2x+54\)
<=>\(x-2x=54+45\)
<=>\(-x=99\)
<=>\(x=-99\)
\(5,5x-12+23=6^7:6^5\)
<=>\(5x+11=6^2\)
<=>\(5x+11=36\)
<=>\(5x=25\)
<=>\(x=5\)
a) 5^x=125
=> 5^x=5^2
=>x=2
b) 3^2*x=81
=>3^2*x=9^2
=>3^2*x=(3^2)^2
=>x=2
câu c chưa hiểu chỗ 5^2x3 hay 5^2*3 vậy ?
a) \(5^x=125\)
\(5^x=5^3\)
\(\Rightarrow x=3\)
b)\(3^{2x}=81\)
\(3^{2x}=3^4\)
\(\Rightarrow2x=4\)
\(x=4:2\)
\(x=2\)
c)\(5^{2x-3}-2.5^2=5^2.3\)
\(5^{2x-3}=5^2.3+5^2.2\)
\(5^{2x-3}=5^2.\left(3+2\right)\)
\(5^{2x-3}=5^3\)
\(\Rightarrow2x-3=3\)
\(2x=3+3\)
\(2x=6\)
\(x=6:2\)
\(x=3\)
(2x - 6)5 = (2x - 6)2
=> (2x - 6)5 - (2x - 6)2 = 0
=> (2x - 6)2.[(2x - 6)3 - 1] = 0
=> \(\orbr{\begin{cases}\left(2x-6\right)^2=0\\\left(2x-6\right)^3-1=0\end{cases}}\)
=> \(\orbr{\begin{cases}2x-6=0\\\left(2x-6\right)^3=1\end{cases}}\)
=> \(\orbr{\begin{cases}2x=6\\2x-6=1\end{cases}}\)
=> \(\orbr{\begin{cases}x=3\\2x=7\end{cases}}\)
=> \(\orbr{\begin{cases}x=3\\x=\frac{7}{2}\left(ktm\right)\end{cases}}\)
33x - 4 - x0 = 8
=> 33x - 4 - 1 = 8
=> 33x - 4 = 8 +1
=> 33x - 4 = 9
=> 33x - 4= 32
=> 3x - 4 = 2
=> 3x = 2 + 4
=> 3x = 6
=> x = 6 : 3 = 2
Bài 1 . Tìm x
a) 723 - ( 7x - 152 ) = 714
7x - 152 = 723 - 714
7x - 152 = 9
7x = 9 + 152
7x = 161
x = 161 : 7
x = 23
Vậy x = 23
b) ( 2x - 130 ) : 4 + 213 = 52 + 193
( 2x - 130 ) : 4 + 213 = 218
( 2x - 130 ) : 4 = 218 - 213
( 2x - 130 ) : 4 = 5
2x - 130 = 5 . 4
2x - 130 = 20
2x = 20 + 130
2x = 150
x = 150 : 2
x = 75
Vậy x = 75
c) ( x - 6 )2 = 9
( x - 6 )2 = 32
x - 6 = 3 <=> x = 3 + 6 <=> x = 9
x - 6 = -3 <=> x = -3 + 6 <=> x = 3
\(5^{2x-3}-2.5^2=5^2.3\)
\(5^{2x-3}=5^3\)
\(2x-3=3\)
\(2x=6\)
\(x=3\)