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\(\left(5^2+3^2\right).x+\left(5^2-3^2\right).x-40.x=10^2\)
\(\Rightarrow\left(25+9\right)x+\left(25-9\right)x-40x=100\)
\(\Rightarrow34x+16x-40x=100\Rightarrow\left(34+16-40\right)x=100\)
\(\Rightarrow10x=100\Rightarrow x=100\div10=10\)
Vậy \(x=10\)

2x+2 + 2x = 40
2x . 22 + 2x = 40
2x . 4 + 2x . 1 = 40
2x . ( 4 + 1 ) = 40
2x . 5 = 40
2x = 40 : 5
2x = 8
2x = 23
=> x = 3

2x . 26 . 24 = 23 . 260
2x + 6 + 4 = 23 + 60
2x + 10 = 263
=> x + 10 = 63
x = 63 - 10
x = 53
a/ 5x.52.53=52.540
5x.55=542
5x=537
x=37
b/ 2x.26.24=23.260
2x.210=263
2x=253
x=53

Ta có: (X-3)2=(X-3)4
=>X-3)4-(X-3)2=0
=>(X-3)2.(X-3.X-3-1)=0
=>(X-3)2= 0 hoặc X-3.X-3-1=0
Suy ra x=3;4
b, 3.(2x+1)+2x+2
=3.2x+1+2x+1.2
=2x+1.(3+2)
=2x+1.5=40
=2x+1=40:5=8
=2x+1=23
=>x+1=3
=>x=3-1=2
=> là suy ra nha bạn
a) ( X - 3 ) 2 = ( X - 3 )4 <=> X - 3 =1
=> X = 1+3
=> X = 4
Chú thích <=> : khi và chỉ khi
=> : suy ra
b) Mình ko biết ______________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________-sorry-____________________________________________________________________________________________________________________________________-__________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________
\(x=\sqrt{40}\)
hoặc \(x=-\sqrt{40}\)
học tốt
40 = x2
x = \(\sqrt{40}\)
hoặc x = \(\sqrt{-40}\)