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33 . 32x - 1 = 81
33 . 32x - 1 = 34
32x - 1 = 34 : 33 = 3
=> 2x - 1 = 1
2x = 2
x = 2 : 2 = 1
a,5x + 5x + 2 = 650
=> 5x+5x.52=650
=> 5x.(1+25)=650
=> 5x=52
=> x=2
3x - 1 + 5 . 3x - 1 = 162
3x-1.(1+5)=162
=> 3x-1=27
=> 3x-1=33
=> x-1=3
=> x=4
5 x + 5 x + 2 = 650 3x - 1 + 5 . 3x - 1 = 162
5 x( 1 + 5 2 ) = 650 3x - 1 ( 5 + 1 ) = 162
5 x = 25 3x - 1 = 27
\(\Rightarrow\)x = 2 \(\Rightarrow\)x - 1 = 3
\(\Rightarrow\)x = 4
a)3x-1+5.3x-1=162
3x-1.1+5.3x-1=162
3x-1.(5+1)=162
3x-1.6=162
3x-1=162/6
3x-1=27
3x-1=33
Suy ra x-1=3
x=3+1=4
b)2x+3+2x=144
2x.8+2x=144
2x.8+2x.1=144
2x.(8+1)=144
2x.9=144
2x=144/9
2x=16
2x=24
Suy ra x=4
a) Ta có 3x - 1 + 5.3x - 1 = 162
<=> 6.3x - 1 = 162
<=> 3x - 1 = 27
<=> 3x - 1 = 33
<=> x - 1 = 3
<=> x = 4
Vậy x = 4 là giá trị cần tìm
b) 2x + 3 + 2x = 144
<=> 2x.23 + 2x = 144
<=> 2x.8 + 2x = 144
<=> 2x.9 = 144
<=> 2x = 16
<=> 2x = 24
<=> x = 4
Vậy x = 4 là giá trị cần tìm
\(2^{x+2}-2^x=96\)
\(\Rightarrow2^x\cdot2^2-2^x=96\)
\(\Rightarrow2^x\left(2^2-1\right)=96\)
\(\Rightarrow2^x\left(4-1\right)=96\)
\(\Rightarrow2^x\cdot3=96\)
\(\Rightarrow2^x=96:3\)
\(\Rightarrow2^x=32\)
\(\Rightarrow2^x=2^5\)
\(\Rightarrow x=5\)
\(5^x+5^{x+1}=750\)
\(\Rightarrow5^x+5^x\cdot5=750\)
\(\Rightarrow5^x\left(1+5\right)=750\)
\(\Rightarrow5^x\cdot6=750\)
\(\Rightarrow5^x=750:6\)
\(\Rightarrow5^x=125\)
\(\Rightarrow5^x=5^3\)
\(\Rightarrow x=3\)
\(2^{x+3}+2^x=144\)
\(\Rightarrow2^x\cdot2^3+2^x=144\)
\(\Rightarrow2^x\left(2^3+1\right)=144\)
\(\Rightarrow2^x\cdot9=144\)
\(\Rightarrow2^x=144:9\)
\(\Rightarrow2^x=16\)
\(\Rightarrow2^x=2^4\)
\(\Rightarrow x=4\)
Lời giải:
$3^{-1}.3^x+5.3^{x-1}=162$
$3^{x-1}+5.3^{x-1}=162$
$3^{x-1}(1+5)=162$
$3^{x-1}.6=162$
$3^{x-1}=27=3^3$
$\Rightarrow x-1=3$
$\Rightarrow x=4$
3x.3x+1+5.32x+1=162
3x.3x.3+5.32x.3=162
32x..3+5.32x.3=162
32x.(3+5.3)=162
32x.18=162
32x=162:18
32x=9
32x=32
=>2x=2
x=2:2
x=1
vạy x=1