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\(42-2\left(32-2^{x+1}\right)=10\)
\(\Leftrightarrow2^{x+1}=16\)
\(\Leftrightarrow2^{x+1}=2^4\)
=> x = 4
\(42-2.\left(32-2^{x+1}\right)=10\)
\(2.\left(32-2^{x+1}\right)=42-10\)
\(2.\left(32-2^{x+1}\right)=32\)
\(32-2^{x+1}=32:2\)
\(32-2^{x+1}=16\)
\(2^{x+1}=32-16\)
\(2^{x+1}=16\)
\(2^{x+1}=2^4\)
\(x+1=4\)
\(x=4-1\)
\(x=3\)
1) 2016 +x = 169x
<=> 2016 = 168x
<=> x=12
2) (26 - 3x) : 5= 4
<=> 26 - 3x = 20
<=> 3x =6
<=> x=2
3) x + 32 - 17 = 21
<=> x + 15 = 21
<=> x= 6
a) => (x+32) - 17 = 42:2 = 21
=> x+32 = 21+17 = 38
=> x=38-32=6
b) => 61+(53-x) = 1785:17=105
=> 53-x = 105-61=44
=> x = 53-44 =9
c) => x^2 +54 -32 = 244:2 = 122
=> x^2 +22 = 122
=> x^2 = 122-2=100
=> x= 10 hoặc -10
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[(46-32)^2-(54-42)^2]*36-1872
=(14^2-12^2)*36-1872
=(196-144).36-1872
=52.36-1872
=1872-1872
=0
(x-7)^7=(x-7)^8
=>(x-7)^7-(x-7)^8=0
=>(x-7)^7.1-(x-7)^7.(x-7)=0
=>(x-7)^7.[1-(x-7)]=0
\(\Rightarrow\orbr{\begin{cases}x-7=0\\1-\left(x-7\right)=0\end{cases}\Rightarrow\orbr{\begin{cases}x=7;-7\\x=0\end{cases}}}\)
Vậy x={7;-7;0}
1+2^3+3^3-4^2.x=20
=>36-4^2.x=20
=>4^2.x=16=4^2
=>2.x=2
=>x=1
a)[(x+32)+17] :2=42
(x+32)+17=42.2
(x+32)+17=84
x+32=84-17
x+32=67
x=67-32
x=35
b)[61+(53-x)]:17=1785
61+(53-x)=1785.17
61+(53-x)=10345
53-x=30345-61
53-x=30284
x=53-30284
x=-30231
42 - (2x + 32) + 12 = 6.2
42 - (2x + 32) + 12 = 12
42 - (2x + 32 ) = 12 - 12
42 - (2x + 32) = 0
2x + 32 = 42 - 0
2x + 32 = 42
2x = 42 - 32
2x = 10
=> x = 10 : 2
=> x = 5
a , 32 - 2 ( x + 1 ) = 42
2 ( x + 1 ) = 32 - 42
2 ( x + 1 ) = -10
x + 1 = -10 : 2 = -5
x = -5 - 1 = -6
b, 12 - 5 (x + 2 ) = 32
5 ( x + 2 ) = 12 - 32 = -20
x + 2 = -20 : 5 = -4
x = -4 - 2 = -6
c , 14 - 5 ( x + 4 ) = 9
5 ( x + 4 ) = 14 - 9
5 ( x + 4 ) = 5
x + 4 = 5 : 5 = 1
x = 1 - 4 = -3
d , 24 - 6 ( 2x + 1 ) = 6
6 ( 2x + 1 ) = 24 - 6
6 ( 2x + 1 ) = 18
2x + 1 = 18 : 6
2x + 1 = 3
2x = 3 - 1 = 2
x = 2 : 2 = 1
32-2.(x+1)=42
2.(x+1)=32-42
2(x+1)=-10
x+1=(-10):2
x+1=-5
x=-5-1
x=-6
32-2.(x+1)=42
2.(x+1)=42+32
2.(x+1)=74
x+1=74:2
x+1=37
x=37-1
x=36
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