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a)2x+2*2x=256
=>22x+2=256
=>22x+2=28
=>2x+2=8
=>2x=6
=>x=3
b)2x+2+2x=80
=>2x(22+1)=80
=>2x*5=80
=>2x=16
=>2x=24
=>x=4
c)2x+2-2x=96
=>2x(22-1)=96
=>2x*3=96
=>2x=32
=>2x=25
=>x=5
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\(\left|x-1\right|+\left|x+5\right|=\left|x-1\right|+\left|-x-5\right|\)
\(\Rightarrow\left|x-1\right|+\left|x+5\right|\ge\left|x-1-x-5\right|\)
\(\Rightarrow\left|x-1\right|+\left|x+5\right|\ge\left|-6\right|=6\)
dấu "=" xảy ra khi \(\left(x-1\right).\left(x+5\right)\ge0\)
\(\Rightarrow-5\le x\le1\)
Vậy x={-5,-4,-3,-2,-1,0,1}
b) \(\hept{\begin{cases}\left(2x-y+3\right)^4\ge0\\\left|y+2\right|\ge0\end{cases}}\)
mà \(\left(2x-y+3\right)^4+\left|y+2\right|=0\)
dấu "=" xảy ra khi \(\hept{\begin{cases}\left(2x-y+3\right)^4=0\\\left|y+2\right|=0\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}x=-\frac{5}{2}\\y=-2\end{cases}}\)
vậy \(x=-\frac{5}{2},y=-2\)
∣x−1∣+∣x+5∣=∣x−1∣+∣−x−5∣
⇒∣�−1∣+∣�+5∣≥∣�−1−�−5∣⇒∣x−1∣+∣x+5∣≥∣x−1−x−5∣
⇒∣�−1∣+∣�+5∣≥∣−6∣=6⇒∣x−1∣+∣x+5∣≥∣−6∣=6
dấu "=" xảy ra khi (�−1).(�+5)≥0(x−1).(x+5)≥0
⇒−5≤�≤1⇒−5≤x≤1
Vậy x={-5,-4,-3,-2,-1,0,1}
b) \hept{(2�−�+3)4≥0∣�+2∣≥0\hept{(2x−y+3)4≥0∣y+2∣≥0
mà (2�−�+3)4+∣�+2∣=0(2x−y+3)4+∣y+2∣=0
dấu "=" xảy ra khi \hept{(2�−�+3)4=0∣�+2∣=0\hept{(2x−y+3)4=0∣y+2∣=0
⇒\hept{�=−52�=−2⇒\hept{x=−25y=−2
vậy �=−52,�=−2x=−25,y=−2
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a)\(\frac{x}{4}=\frac{y}{5}=\frac{x.y}{4.5}=\frac{80}{20}=4\)
\(x=4\cdot4=16\\ y=5\cdot4=20\)mk ko bt cau b
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x = 4 nha bạn .
2^x + 2^x+2 = 80
2^4 + 2^4+2 = 80
x = 4 nha bạn .