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\(4\left(x+1\right)\left(-x+2\right)+\left(2x-1\right)\left(2x+3\right)=-11\)
\(\text{⇔}-4x^2+4x+8+4x^2+4x-3=-11\)
\(\text{⇔}8x+5=-11\)
\(\text{⇔}8x=-16\)
\(\text{⇔}x=-2\)
Vậy: \(x=-2\)
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\(\left(2x+4\right)\left(3x+1\right)\left(x-2\right)-\left(-3x^2+1\right)\left(-2x+\dfrac{2}{3}\right)=-\dfrac{26}{3}\)
\(\text{⇔}6x^3+2x^2-24x-8-6x^3-2x^2-2x+\dfrac{2}{3}=-\dfrac{26}{3}\)
\(\text{⇔}-26x-\dfrac{22}{3}=-\dfrac{26}{3}\)
\(\text{⇔}-26x=-\dfrac{4}{3}\)
\(\text{⇔}x=\dfrac{2}{39}\)


mk làm lun nha
a, 2x^2-6x-3x-2x^2=26
-9x=26
x=-26/9
b,x^2+2.x.4+16-(x^2-1)=16
x^2+8x+16-x^2+1=16
8x=-1
x=-1/8
c,(2x)^2-2.2x.1+1-4(x^2-7^2)=0
4x^2-4x+1-4x^2+196=0
-4x=-197
x=197/4
d,x^2-5x-4x+20=0
-9x=-20
x=20/9
**** cho mk nha

a) 2x (x - 5) - x (3 + 2x) = 26
=> 2x2 - 10x - (3x - 2x2) = 26
=> 2x2 - 10x - 3x - 2x2 = 26
=> -13x = 26 => x = 26 : (-13) = -2
xin loi nhung hoi nhiu mik viet cau tra loi dc ko - Nguyễn Diệu Thảo


\(\left(x+2\right)\left(x^2-2x+4\right)-x\left(x-3\right)\left(x+3\right)=26\)
\(\Leftrightarrow x^3+8-x\left(x^2-9\right)=26\)
\(\Leftrightarrow x^3+8-x^3+9x=26\)
\(\Leftrightarrow9x=18\)
\(\Leftrightarrow x=2\)
\(\left(x+2\right)\left(x^2-2x+4\right)-x\left(x-3\right)\left(x+3\right)=26\)
\(\Leftrightarrow x^3+2^3-x.\left(x^2-3^2\right)=26\)
\(\Leftrightarrow x^3+2^3-x^3+9x^2=26\)
\(\Leftrightarrow8+9x=26\)
\(\Leftrightarrow9x=26-8\)
\(\Leftrightarrow9x=18\)
\(\Leftrightarrow x=18:9\)
\(\Leftrightarrow x=2\)
\(\Leftrightarrow\left(x+2\right)\left(x^2-2x+2^2\right)-x\left(x^2-3^2\right)=26\\ \Leftrightarrow x^3+2^3-x^3+9x=26\\ \Leftrightarrow9x+8=26\\ \Rightarrow x=\dfrac{26-8}{9}=2\)
Lời giải:
$(x+2)(x^2-2x+4)-x(x+3)(x-3)=26$
$\Leftrightarrow x^3+8-x(x^2-9)=26$
$\Leftrightarrow 9x+8=26$
$\Leftrightarrow 9x=18$
$\Leftrightarrow x=2$