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a) 25. (x-4) = 0
=> x -4 =0
x = 4
b) 43 - (24-x) = 20
43 - 24 + x = 20
19 + x = 20
x = 1
c) 3.(x+7) - 15 = 27
3.x + 21 - 15 = 27
3.x + 6 = 27
3.x = 21
x = 7
d)... bn ghi thiếu đề r
e) (2.x-6).(x-7) = 0
=> 2.x -6 = 0 => 2x = 6 => x = 3
x - 7 = 0 => x = 7
KL: x = 3 hoặc x = 7
phần d lm tương tự như phần f nha bn!
a,25(x-4)=0
x-4=0
x=4
b,43-(24-x)=20
43-24+x=20
x=1
c,3(x+7)-15=27
3x+21-15=27
3x=21
x=7
d,(x-4)(x-12)=0
x-4=0=>x=4
x-12=0=>x=12
e,(2x-6)(x-7)=0
2x-6=0=>x=3
x-7=0=>x=7
f,(5x-10)(2x-8)=0
5x-10=0=>x=2
2x-8=0=>x=2
a) 5. (x - 7) = 6
x -7 = 6 : 5
x = 1.2 + 7
x = 8,2
b) 25 + (15 - x) =20
15 - x= 20- 25
x = 20
c) 25 (x - 4) = 0
x - 4 = 0 :25
x = 4
d) 43 - (24 - x) = 20
24 - x= 43 -20
x = 24 - 23
x = 1
b) -26 - ( x - 7 ) = 0
x - 7 = -26 - 0
x - 7 = -26
x = -26 + 7
x = -19
Bài 2 :
a) 3 - ( 17 - x ) = -12
( 17 - x ) = 3 - ( -12 )
( 17 - x ) = 15
x = 17 - 15
x = 2
1/ -7264 + (1543 + 7264)
=-7264 + 1543 + 7264=1543
2/ (144 – 97) – 144
=144-97-144=-97
3/ (-145) – (18 – 145)(Vì có dấu trừ ở trước ngoặc nên p đổi dấu)
=-145-18+145=-18
4/ 111 + (-11 + 27)
=111-11+27=137
a ) \(5.\left(x-7\right)=0\)
\(\Leftrightarrow x-7=5.0\)
\(\Leftrightarrow x-7=0\)
\(\Leftrightarrow x=7\)
b ) \(34.\left(2.x-6\right)=0\)
\(\Leftrightarrow2.x-6=34.0\)
\(\Leftrightarrow2.x-6=0\)
\(\Leftrightarrow2.x=0+6\)
\(\Leftrightarrow2.x=6\)
\(\Leftrightarrow x=6\div2\)
\(\Leftrightarrow x=3\)
c ) \(25+\left(15-x\right)=30\)
\(\Leftrightarrow25+\left(15-x\right)=-\left(x-40\right)\)
\(\Leftrightarrow-\left(x-40\right)=2.3.5\)
\(\Leftrightarrow40-x=30\)
\(\Leftrightarrow-x=-10\)
\(\Leftrightarrow x=10\)
d ) \(43-\left(24-x\right)=20\)
\(\Leftrightarrow24-x=43-20\)
\(\Leftrightarrow24-x=23\)
\(\Leftrightarrow x=24-23\)
\(\Leftrightarrow x=1\)
e ) \(2.\left(x-5\right)-17=25\)
\(\Leftrightarrow2.\left(x-5\right)=25+17\)
\(\Leftrightarrow2.\left(x-5\right)=42\)
\(\Leftrightarrow x-5=42\div2\)
\(\Leftrightarrow x-5=21\)
\(\Leftrightarrow x=21+5\)
\(\Leftrightarrow x=26\)
f ) \(24+3.\left(5-x\right)=27\)
\(\Leftrightarrow3.\left(5-x\right)=27-24\)'
\(\Leftrightarrow3.\left(5-x\right)=3\)
\(\Leftrightarrow5-x=3\div3\)
\(\Leftrightarrow5-x=1\)
\(\Leftrightarrow x=5-1\)
\(\Leftrightarrow x=4\)
g ) \(15\div x-2=3\)
\(\Leftrightarrow15\div x=3+2\)
\(\Leftrightarrow15\div x=5\)
\(\Leftrightarrow x=15\div5\)
\(\Leftrightarrow x=3\)
h ) \(\left(32-x\div5\right)\div13=2\)
\(\Leftrightarrow32-x\div5=2\times13\)
\(\Leftrightarrow32-x\div5=26\)
\(\Leftrightarrow x\div5=32-26\)
\(\Leftrightarrow x\div5=6\)
\(\Leftrightarrow x=5.6\)
\(\Leftrightarrow x=30\)
g ) \(\left(6-2x\right)\left(x-8\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}6-2x=0\\x-8=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=8\end{matrix}\right.\)
Vậy \(x\in\left\{3;8\right\}\)
Mình làm hết nhaa !!
a)5.(x-7)=0
x-7=0:5
x-7=0
x=0+7
x=7
Vậy x=7
b)34.(2x-6)=0
2x-6 =0:34
2x-6 =0
2x=0+6
2x=6
x=6:2
x=3
Vậy x= 3
c)25+(15-x)=30
15-x=30-25
15-x=5
x=15-5
x=10
Vậy x=10
d)43-(24-x)=20
24-x =43-20
24-x=23
x=24-23
x=1
vậy x=1
e)2(x-5)-17=25
2(x-5)=25+17
2(x-5)=42
x-5=42:2
x-5=21
x=21+5
x=26
Vậy x=26
f)24+3(5-x)=27
3(5-x)=27-24
3(5-x)=3
5-x =3:3
5-x=1
x=5-1
x=4
Vậy x=4
g)15:x-2=3
15:x=3+2
15:x=5
x=15:5
x=3
Vậy x=3
h)( 32-x:5):13=2
32-x:5 =2.13
32-x :5=26
x:5= 32-26
x:5=6
x=6.5
x=30
Vậy x=30
k)(6-2x)(x-8)=0
➩6-2x=0 hoặc x-8=0
2x=6-0 x=0+8
2x=6 x=8
x=6:2
x=3
Vậy x=3 hoặc x=8
Answer:
\(9.\left(x+28\right)=0\)
\(\Rightarrow x+28=0\)
\(\Rightarrow x=-28\)
\(\left(27-x\right).\left(x+9\right)=0\)
\(\Rightarrow\orbr{\begin{cases}27-x=0\\x+9=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=27\\x=-9\end{cases}}\)
\(\left(-x\right).\left(x-43\right)=0\)
\(\Rightarrow\orbr{\begin{cases}-x=0\\x-43=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=0\\x=43\end{cases}}\)
a) 9 . ( x + 28 ) = 0 <=> x = -28
b) (27-x)(x+9)= 0 <=> x = 27 hoac x = -9
c) (-x)(x-43)=0 <=> x =0 hoac x = 43
1
37.(43-51)-43.(37-51)
=37.43-37.51-43.37-43.51
=(37.43-43.57)-(37.51-43.51)
=0-(-306)
=306
2
a.(x-1).(2x+2)=0
=>x-1 hoặc 2x+2=0
=>x=1 hoặc 2x=-2
=>x=1 hoặc x=-1
Vậy x=+1
b.(6x-12).(x-3)=0
=>6x-12 hoặc x-3=0
=>6x=12 hoặc x=3
=>x=2 hoặc x=3
Vậy x=2 hoặc x=3
\(\left(x-9\right)\left(x+2\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-9=0\\x+2=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=0+9\\x=0-2\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=9\\x=-2\end{cases}}\)
Vậy x = 9 hoặc x = -2
17 - (43 - |x|) = 45
=> 43 - |x| = 17 - 45
=> 43 - |x| = -28
=> |x| = 43 + 28
=> |x| = 71
=> x = 71 hoặc x = -71
Vậy x = 71 hoặc x = -71
\(\left(-x\right)\cdot\left(x-43\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}-x=0\\x-43=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=43\end{matrix}\right.\)