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a) 7(x-5)+14=56
<=>7(x-5)=42
<=>x-5=6
<=>x=11
b)9(x+1)-3=15
<=>9(x+1)=18
<=>x+1=2
<=>x=1
c)12(x+5)-36=48
<=>12(x+5)=84
<=>x+5=7
<=>x=2
d)5(x+14)=145
<=>x+14=29
<=>x=15
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a. 5x . 514 = 578
5x = 578 : 514 = 564
5x = 564 => x = 64
b. 7x . 49 = 727
7x . 72 = 727
7x = 727 : 72 = 725
7x = 725 => x = 25
c.
a) \(5^x.5^{14}=5^{78}\)
\(\Rightarrow5^{x+14}=5^{78}\)
\(\Leftrightarrow x+14=78\)
\(\Leftrightarrow x=64\)
Vậy x = 64
b) \(7^x.49=7^{27}\)
\(\Rightarrow7^x.7^2=7^{27}\)
\(\Leftrightarrow7^{x+2}=7^{27}\)
\(\Leftrightarrow x+2=27\Leftrightarrow x=25\)
Vậy x = 25
c) \(\left(x^4\right)^{11}=x\Rightarrow x^{44}=x\)
\(\Leftrightarrow x=\orbr{\begin{cases}0\\1\end{cases}}\)
Vậy x = 0 hoặc x = 1
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d , ( x : 7 + 15 ) . 23 + 391 => Đề thiếu
e , ( 19 . x + 2 . 52 ) : 14 = ( 13 - 8 ) 2 - 42
=> ( 19 . x + 2 . 52 ) : 14 = 52 - 16
=> ( 19 . x + 2 . 52 ) : 14 = 25 - 16 = 9
=> 19 . x + 2 . 52 = 9 x 14 = 126
=> 19 . x + 2 . 25 = 126
=> 19 . x + 50 = 126
=> 19 . x = 126 - 50 = 76
=> x = 76 : 19 = 4
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13 sao trừ được 18 bạn xem có sai đề ko
nếu sai đề gửi đề mới mình giải cho
a, ( 19X + 2 x 52 ) : 14 = ( 13 - 18 )2 - 42
( 19X + 2 x 52 ) : 14 = ( -5 )2 - 42
( 19X + 2 x 52 ) : 14 = 25 - 16
( 19X + 2 x 25 ) : 14 = 9
( 19X + 2 x 25 ) = 9 . 14
19X + 2 x 25 = 126
19X + 50 = 126
19X = 126 - 50
19X = 76
X = 76 : 19 = 4
b, 2 x 3X = 10 x 312 + 8 x 274
2 x 3X = 10 . 531441 + 8 . 531441
2 x 3X = 2 x 3X = 531441( 10+8)
2 x 3X = 531441 . 18 = 9565938
3x = 9565938 : 2 = 4782969
ma 3^( dungf mt ra tips keets quar )
Hok tot
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a/ (ghi lại cái đề)
=>+ 3x-7=2
3x=2+7=9
x=3
+ 3x-7=-2
3x=-2+7=5
x=\(\frac{5}{3}\)
b/ (5x-10)2=100
=> +5x-10=10
5x=10+10=20
x=4
+ 5x-10=-10
5x=-10+10=0
x=0
\(\left(x-5\right)^{14}:\left(x-5\right)^2=\left(x-5\right)^4\)
\(\Leftrightarrow\left(x-5\right)^{12}=\left(x-5\right)^4\)
\(\Leftrightarrow\orbr{\begin{cases}x-5=0\\x-5=1\end{cases}\Leftrightarrow\orbr{\begin{cases}x=5\\x=6\end{cases}}}\)
giải thích cho mk đoạn cuối