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\(3,8:\left(2x\right)=\frac{1}{4}:2\frac{2}{3}\)
\(3,8:\left(2x\right)=\frac{3}{32}\)
\(\Rightarrow2x=3,8:\frac{3}{32}\)
\(\Rightarrow x=\frac{608}{15}:2=\frac{304}{15}\)
\(\left(a\right)\) tức là bài a hay là gt trog tỉ lệ thức v pn?
b) \(3,8:\left(2x\right)=\frac{1}{4}:\frac{8}{3}\)
= \(3,8:\left(2x\right)=\frac{3}{32}\)
\(\Rightarrow2x=3,8:\frac{3}{32}=\frac{608}{15}\)
\(\Rightarrow x\frac{608}{15}:2=\frac{304}{15}\)
\(\Rightarrow\frac{304}{15}\)
( 0,25x ) : 3 = 5/6 : 0,125
( 1/4x ) : 3 = 5/6 : 1/8
( 1/4x ) : 3 = 5/6 x 8
( 1/4x ) : 3 = 20/3
1/4x = 20/3 x 3
1/4x = 20
x = 20 : 1/4
x = 80
0,01 : 2,5 = ( 0,75x ) : 0,75
1/100 : 25/10 = (3/4x) : 3/4
1/100 x 10/25 = (3/4x) : 3/4
=>(3/4x) : 3/4 = 1/250
3/4x = 1/250 x 3/4
3/4x = 3/1000
x = 3/1000 : 3/4
x = 1/250
a)\(3,8:\left(2x\right)=\dfrac{1}{4}:2\dfrac{2}{3}\)
\(2x=3,8:\dfrac{3}{32}\)
\(x=\dfrac{608}{15}:2\)
\(x=\dfrac{304}{15}\)
b)\(\left(0,25x\right):3=\dfrac{5}{6}:0,125\)
\(0,25x=\dfrac{20}{3}\times3\)
\(x=20:0,25\)
\(x=80\)
c) \(0,01:2,5=\left(0,75\times x\right):0,75\)
\(0,004=0,75\times x:0,75\)
\(0,004=x\times0,75:0,75\)
\(0,004=x\times1\)
\(0,004=x\)
\(\Rightarrow x=0,004\)
d)\(1\dfrac{1}{3}:0,8=\dfrac{2}{3}:\left(0,1x\right)\)
\(\dfrac{5}{3}=\dfrac{2}{3}:0,1\times x\)
\(\dfrac{5}{3}=\dfrac{20}{3}\times x\)
\(\Rightarrow x=\dfrac{20}{3}:\dfrac{5}{3}\)
\(x=4\)
a) \(x=20\dfrac{4}{15}.\)
b) \(x=80\)
c) \(x=0,004\)
d) \(x=4.\)
a) Lm r nkoa!
b) \(\left(0,25x\right):3=\frac{5}{6}:0,125\)
\(=\left(0,25x\right):3=\frac{20}{3}\)
\(\Rightarrow0,25x=\frac{20}{3}\cdot3=20\)
\(\Rightarrow x=20:0,25=80\)
\(\Rightarrow x=80\)
c) \(0,01:2,5=\left(0,75x\right):0,75\)
\(=\frac{1}{250}=\left(0,75x\right):0,75\)
\(\Rightarrow0,75x=\frac{1}{250}\cdot0,75=\frac{3}{1000}\)
\(\Rightarrow x=\frac{3}{1000}:0,75=\frac{1}{250}\)
\(\Rightarrow x=\frac{1}{250}\)
d) \(1\frac{1}{3}:0,8=\frac{2}{3}:\left(0,1x\right)\)
\(=\frac{5}{3}=\frac{2}{3}:\left(0,1x\right)\)
\(\Rightarrow0,1x=\frac{2}{3}:\frac{5}{3}=\frac{2}{5}\)
\(\Rightarrow x=\frac{2}{5}:0,1=4\)
\(\Rightarrow4\)
\(\frac{x-1}{x-2}=\frac{x+3}{x+4}\)
\(\Rightarrow\left(x-1\right)\left(x+4\right)=\left(x-2\right)\left(x+3\right)\)
\(\Leftrightarrow x^2+4x-x-4=x^2+3x-2x-6\)
\(\Leftrightarrow x^2+4x-x-4-x^2-3x+2x+6=0\)
\(\Leftrightarrow2x+2=0\)
\(\Leftrightarrow2x=-2\)
\(\Leftrightarrow x=-1\)VẬY X=-1 LÀ NGHIỆM CỦA PHƯƠNG TRÌNH \(\frac{x-1}{x-2}=\frac{x+3}{x+4}\)