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A/ \(\frac{x}{17}=\frac{60}{204}\)
\(204x=60.17\)
\(204x=1020\)
\(x=\frac{1020}{204}\)
\(x=\frac{17}{4}=4,25\)
vậy x= 4,25
B/ \(\left(6+x\right).11=33.7\)
\(66+11x=231\)
\(11x=231-66=165\)
\(x=\frac{165}{11}\)
\(x=15\)
vậy x = 15
C/ \(\left(12+x\right).3=\left(43-x\right).2\)
\(36+3x=86-2x\)
\(3x+2x=86-36\)
\(5x=50\)
\(x=\frac{50}{5}=10\)
vậy x=10

a) \(x\cdot\frac{13}{20}+x:2=\frac{4}{7}\)
\(x\cdot\frac{13}{20}+x\cdot\frac{1}{2}=\frac{4}{7}\)
\(x\cdot\left(\frac{13}{20}+\frac{1}{2}\right)=\frac{4}{7}\)
\(x\cdot\frac{23}{20}=\frac{4}{7}\)
\(x=\frac{4}{7}:\frac{23}{20}\)
b) \(x:1+x:\frac{1}{2}+x:\frac{125}{1000}=6\)
\(x\cdot\frac{1}{2}+x\cdot2+x\cdot8=6\)
\(x\cdot\left(\frac{1}{2}+2+8\right)=6\)
\(x\cdot\frac{21}{2}=6\)
\(x=6:\frac{21}{2}\)
\(x=\frac{6}{7}\)

a ) ( x + 74 ) - 318 = 200
x + 74 = 200 + 318
x + 74 = 518
x = 518 - 74
x = 444
b ) 3636 : ( 12 . x - 91 ) = 36
12 . x - 91 = 3636 : 36
12 . x - 91 = 101
12 . x = 101 + 91
12 . x = 192
x = 192 : 12
x = 16
c ) ( x : 23 + 45 ) . 67 = 8911
x : 23 + 45 = 8911 : 67
x : 23 + 45 = 133
x : 23 = 133 - 45
x : 23 = 88
x = 88 . 23
x = 2024
d ) ( 3 . x - 6 ) + 57 = 60
3 . x - 6 = 60 - 57
3 . x - 6 = 3
3 . x = 3 + 6
3 . x = 9
x = 9 : 3
x = 3
\(a)\) \(\left(x+74\right)-318=200\)
\(x+74=518\)
\(x=444\)
Vậy x = 444
\(b)\) \(3636:\left(12x-91\right)=36\)
\(12x-91=101\)
\(12x=192\)
\(x=16\)
Vậy x = 16
\(c)\) \(\left(x:23+45\right)67=8911\)
\(x:23+45=133\)
\(x:23=88\)
\(x=2024\)
Vậy x = 2024
\(d)\left(3x-6\right)+57=60\)
\(3x-6=3\)
\(3x=9\)
\(x=3\)
Vậy x = 3

\(3\times\left(\frac{x}{4}+\frac{x}{28}+\frac{x}{70}+\frac{x}{130}\right)=\frac{60}{13}\)
=> \(\frac{x}{4}+\frac{x}{28}+\frac{x}{70}+\frac{x}{130}=\frac{20}{13}\)
=> \(\frac{x}{1\cdot4}+\frac{x}{4\cdot7}+\frac{x}{7\cdot10}+\frac{x}{10\cdot13}=\frac{20}{13}\)
=> \(\frac{x}{3}\left(\frac{3}{1\cdot4}+\frac{3}{4\cdot7}+\frac{3}{7\cdot10}+\frac{3}{10\cdot13}\right)=\frac{20}{13}\)
=> \(\frac{x}{3}\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+...+\frac{1}{10}-\frac{1}{13}\right)=\frac{20}{13}\)
=> \(\frac{x}{3}\left(1-\frac{1}{13}\right)=\frac{20}{13}\)
=> \(\frac{x}{3}\cdot\frac{12}{13}=\frac{20}{13}\)
=> \(\frac{x}{3}=\frac{20}{13}:\frac{12}{13}=\frac{20}{13}\cdot\frac{13}{12}=\frac{5}{3}\)
=> x = 5
\(3\cdot\left(\frac{x}{4}+\frac{x}{28}+\frac{x}{70}+\frac{x}{130}\right)=\frac{60}{13}\)
\(3\cdot\left(\frac{x}{1\cdot4}+\frac{x}{4\cdot7}+\frac{x}{7\cdot10}+\frac{x}{10\cdot13}\right)=\frac{60}{13}\)
\(3\left(x-3\right)\left(\frac{3}{1\cdot4}+\frac{3}{4\cdot7}+\frac{3}{7\cdot10}+\frac{3}{10\cdot13}\right)=\frac{60}{13}\)
\(\left(3x-9\right)\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}\right)=\frac{60}{13}\)
\(\left(3x-9\right)\left(1-\frac{1}{13}\right)=\frac{60}{13}\)
\(\left(3x-9\right)\cdot\frac{12}{13}=\frac{60}{13}\)
\(3x-9=\frac{\frac{60}{13}}{\frac{12}{13}}\)
\(3x-9=5\)
\(3x=5+9\)
\(3x=14\)
\(x=\frac{14}{3}\approx4,667\)

a)\(\frac{x}{17}=\frac{60}{204}=\frac{5}{17}\Rightarrow x=5\)
b)\(\frac{6+x}{33}=\frac{7}{11}\Rightarrow11\left(6+x\right)=7.33\Rightarrow11.6+11x=231\Rightarrow66+11x=231\)
\(\Rightarrow11x=231-66\Rightarrow11x=165\Rightarrow x=\frac{165}{11}=15\)
c)\(\frac{12+x}{43-x}=\frac{2}{3}\Rightarrow2\left(43-x\right)=3\left(12+x\right)\Rightarrow2.43-2x=3.12+3x\)
\(86-2x=36+3x\Rightarrow86-36=3x+2x\Rightarrow50=5x\Rightarrow x=\frac{50}{5}=10\)


\(\frac{x}{12}=\frac{3}{x}\Rightarrow12\cdot3=x^2\Rightarrow36=x^2\Rightarrow x=6\left(x\inℕ\right)\)

a) ta có : 60/204= 60:12/204:12 =5/7
suy ra : x = 5
b) 7/11 = 7x3/11x3 = 21/33
suy ra 6+x = 21
x = 21 -6
x = 15
ý c) bạn làm tương tự nhé
X x 1,1 + X x 8,9 = 60
X x ( 1,1 + 8,9 ) = 60
X x 10 = 60
X = 60 : 10
X = 6
Vậy X = 6
Tk mk nha
x = 6 nha