\(x^{50}\)= x 

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25 tháng 12 2016

x50 = x  <=>  x50 - x =0  <=>  x(x49 - 1) =0  

=>\(\orbr{\begin{cases}x=0\\x^{49}-1=0\end{cases}}\)<=>\(\orbr{\begin{cases}x=0\\x=1\end{cases}}\)

25 tháng 12 2016

x = 1

nho tk cho minh nha

a: x/5=32/80

nên x/5=2/5

hay x=2

13/x=26/30

nên 13/x=13/15

hay x=15

-x/7=22/-77

=>x/7=2/7

hay x=2

b: x/9=28/36

=>x/9=7/9

hay x=7

-10/x=50/55

=>-10/x=10/11

hay x=-11

288:(x-3)2=2

=> (x-3)2=144

=>x-3=12(vì x thuộc N)

=> x=15

14 tháng 4 2019

\(8.6+288:\left(x-3\right)^2=50\)

\(\Rightarrow48+288:\left(x-3\right)^2=50\)

\(\Rightarrow288:\left(x-3\right)^2=50-48=2\)

\(\Rightarrow\left(x-3\right)^2=288:2=144\)

Mà \(\left(x-3\right)^2=144=12^2\)

\(\Rightarrow x-3=12\)

\(\Rightarrow x=12+3\)

\(\Rightarrow x=15\)

24 tháng 7 2019

a) \(\frac{4}{3}x-1=\frac{x}{5}\)

=> \(\frac{4}{3}x-\frac{1}{5}x=1\)

=> \(\frac{17}{15}x=1\)

=> \(x=1:\frac{17}{15}=\frac{15}{17}\)

b) \(x+50\%=\frac{4\left(x+1\right)}{3}-\frac{1}{3}\)

=> \(x+\frac{1}{2}=\frac{4x+4-1}{3}\)

=> \(\frac{2x+1}{2}=\frac{4x+3}{3}\)

=> \(\left(2x+1\right).3=2.\left(4x+3\right)\)

=> \(6x+3=8x+6\)

=> \(6x-8x=6-3\)

=> \(-2x=3\)

=> \(x=3:\left(-2\right)=-\frac{3}{2}\)

\(a,\frac{4}{3}x-1=\frac{x}{5}\)

\(\Rightarrow\frac{4}{3}x=\frac{x}{5}+1\)

\(\Rightarrow\frac{4x}{3}=\frac{x+5}{5}\)

\(\Rightarrow20x=3x+15\)

\(\Rightarrow17x=15\)

\(\Rightarrow x=\frac{15}{17}\)

\(b,x+50\%=\frac{4\left(x+1\right)}{3}-\frac{1}{3}\)

\(\Rightarrow x+\frac{1}{2}=\frac{4x+4-1}{3}\)

\(\Rightarrow\frac{2x+1}{2}=\frac{4x+3}{3}\)

\(\Rightarrow3\left(2x+1\right)=\left(4x+3\right).2\)

\(\Rightarrow6x+3=8x+6\)

\(\Rightarrow2x=-3\)

\(\Rightarrow x=-\frac{3}{2}\)

\(c,-200\%.x+\frac{4}{3}=\frac{7}{4}\left(x+1\right)\)

\(\Rightarrow-2x+\frac{4}{3}=\frac{7}{4}x+\frac{7}{4}\)

\(\Rightarrow\frac{-6x+4}{3}=\frac{7x+7}{4}\)

\(\Rightarrow4\left(-6x+4\right)=\left(7x+7\right)3\)

\(\Rightarrow-24x+16=21x+21\)

\(\Rightarrow45x=-5\)

\(\Rightarrow x=-\frac{1}{7}\)

7 tháng 4 2019

\(\left(2\frac{4}{5}x-50\right)\div\frac{2}{3}=51\)

\(\frac{14}{5}x-50=51\times\frac{2}{3}\)

\(\frac{14}{5}x-50=34\)

\(\frac{14}{5}x=84\)

\(x=84\times\frac{5}{14}\)

\(x=30\)

7 tháng 4 2019

\(a,\left(2\frac{4}{5}.x-50\right):\frac{2}{3}=51\)

    \(\left(\frac{14}{5}.x-50\right):\frac{2}{3}=51\)

   \(\frac{14}{5}.x-50=51\times\frac{2}{3}\)

   \(\frac{14}{5}.x-50=34\)

   \(\frac{14}{5}.x=34+50\)

   \(\frac{14}{5}.x=84\)

    \(x=84:\frac{14}{5}\)

   \(x=\frac{405}{14}\)

18 tháng 4 2017

a)\(\frac{-2}{3}.x+\frac{1}{5}=\frac{3}{10}\)

\(\frac{-2}{3}x=\frac{3}{10}-\frac{1}{5}=\frac{1}{10}\)

\(\frac{-2}{3}x=\frac{1}{10}\)

\(x=\frac{1}{10}\div\frac{-2}{3}=\frac{-3}{20}\)

b)\(\left(50\%.x+2\frac{1}{4}\right).\frac{-2}{3}=\frac{17}{6}\)

\(50\%.x+2\frac{1}{4}=\frac{17}{6}\div\frac{-2}{3}\)\(=\frac{-17}{4}\)

\(50\%.x+2\frac{1}{4}=\frac{-17}{4}\)

\(50\%.x=\frac{-17}{4}-2\frac{1}{4}=\frac{-17}{4}-\frac{9}{4}=\frac{-26}{4}=\frac{-13}{2}\)

\(50\%.x=\frac{-13}{2}\)

\(x=\frac{-13}{2}\div50\%=-13\)

18 tháng 4 2017

\(\frac{-2}{3}\)\(\hept{\begin{cases}.\\.\\.\end{cases}ads}\)

25 tháng 12 2016

\(x^{50}=x\)

\(\Rightarrow x^{50}-x=0\)

\(\Rightarrow x\cdot x^{49}-x\cdot1=0\)

\(\Rightarrow x\cdot\left(x^{49}-1\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x=0\\x^{49}-1=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\x^{49}=1\end{cases}\Rightarrow}\orbr{\begin{cases}x=0\\x=1\end{cases}}}\)

Vậy: \(x\in\left\{0;1\right\}\)

25 tháng 12 2016

\(x^{50}=x\)

\(x^{50}-x=0\)

\(x.x^{49}-x.1=0\)

\(x.\left(x^{49}-1\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x=0\\x^{49}-1=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\x^{49}=1\Rightarrow x=1\end{cases}}}\)